我需要通过GPS程序获得我的当前位置。 我怎样才能做到呢?


当前回答

我已经发布了一个小的库,可以很容易地在Android中获取位置数据,它甚至照顾到Android M运行时权限。

您可以在这里查看它:https://github.com/julioromano/RxLocation并使用它或其源代码作为实现的示例。

其他回答

LocationManager是一个类,它提供内置方法来获取最后知道的位置

步骤1:如下所示创建LocationManager对象

导航(导航);

步骤2:添加标准

*Criteria is use for setting accuracy*

Criteria criteria = new Criteria();
int currentapiVersion = android.os.Build.VERSION.SDK_INT;

if (currentapiVersion >= android.os.Build.VERSION_CODES.HONEYCOMB) {

    criteria.setSpeedAccuracy(Criteria.ACCURACY_HIGH);
    criteria.setAccuracy(Criteria.ACCURACY_FINE);
    criteria.setAltitudeRequired(true);
    criteria.setBearingRequired(true);
    criteria.setSpeedRequired(true);

}

步骤3:获取可用的提供商

有两种类型的供应商GPS和网络

 String provider = locationManager.getBestProvider(criteria, true);

第四步:了解最后知道的地点

Location location = locationManager.getLastKnownLocation(provider);

第五步:获取经纬度

如果location对象为空,那么不要尝试调用下面的方法

getLatitude和getLongitude是返回双值的方法

class MyLocation {
    Timer timer1;
    LocationManager lm;
    LocationResult locationResult;
    boolean gps_enabled = false;
    boolean network_enabled = false;

    public boolean getLocation(Context context, LocationResult result) {
        // I use LocationResult callback class to pass location value from
        // MyLocation to user code.
        locationResult = result;
        if (lm == null)
            lm = (LocationManager) context
                    .getSystemService(Context.LOCATION_SERVICE);

        // Exceptions will be thrown if the provider is not permitted.
        try {
            gps_enabled = lm.isProviderEnabled(LocationManager.GPS_PROVIDER);
        }
        catch (Exception ex) {
        }
        try {
            network_enabled = lm
                    .isProviderEnabled(LocationManager.NETWORK_PROVIDER);
        }
        catch (Exception ex) {
        }

        // Don't start listeners if no provider is enabled.
        if (!gps_enabled && !network_enabled)
            return false;

        if (gps_enabled)
            lm.requestLocationUpdates(LocationManager.GPS_PROVIDER, 0, 0,
                    locationListenerGps);
        if (network_enabled)
            lm.requestLocationUpdates(LocationManager.NETWORK_PROVIDER, 0, 0,
                    locationListenerNetwork);
        timer1 = new Timer();
        timer1.schedule(new GetLastLocation(), 5000);
        return true;
    }

    LocationListener locationListenerGps = new LocationListener() {
        public void onLocationChanged(Location location) {
            timer1.cancel();
            locationResult.gotLocation(location);
            lm.removeUpdates(this);
            lm.removeUpdates(locationListenerNetwork);
        }

        public void onProviderDisabled(String provider) {
        }

        public void onProviderEnabled(String provider) {
        }

        public void onStatusChanged(String provider, int status, Bundle extras) {
        }
    };

    LocationListener locationListenerNetwork = new LocationListener() {
        public void onLocationChanged(Location location) {
            timer1.cancel();
            locationResult.gotLocation(location);
            lm.removeUpdates(this);
            lm.removeUpdates(locationListenerGps);
        }

        public void onProviderDisabled(String provider) {
        }

        public void onProviderEnabled(String provider) {
        }

        public void onStatusChanged(String provider, int status, Bundle extras) {
        }
    };

    class GetLastLocation extends TimerTask {
        @Override
        public void run() {
            lm.removeUpdates(locationListenerGps);
            lm.removeUpdates(locationListenerNetwork);

            Location net_loc = null, gps_loc = null;
            if (gps_enabled)
                gps_loc = lm.getLastKnownLocation(LocationManager.GPS_PROVIDER);
            if (network_enabled)
                net_loc = lm
                        .getLastKnownLocation(LocationManager.NETWORK_PROVIDER);

            // If there are both values, use the latest one.
            if (gps_loc != null && net_loc != null) {
                if (gps_loc.getTime() > net_loc.getTime())
                    locationResult.gotLocation(gps_loc);
                else
                    locationResult.gotLocation(net_loc);
                return;
            }

            if (gps_loc != null) {
                locationResult.gotLocation(gps_loc);
                return;
            }
            if (net_loc != null) {
                locationResult.gotLocation(net_loc);
                return;
            }
            locationResult.gotLocation(null);
        }
    }

    public static abstract class LocationResult {
        public abstract void gotLocation(Location location);
    }
}

我希望这对你有所帮助……

我已经得到非常准确的位置使用FusedLocationProviderClient (谷歌播放服务要求)

权限要求

android.permission.ACCESS_FINE_LOCATION

android.permission.ACCESS_COARSE_LOCATION

依赖

“com.google.android.gms: play-services-location: 15.0.0”

芬兰湾的科特林代码

val client = FusedLocationProviderClient(this)
val location = client.lastLocation
location.addOnCompleteListener {
    // this is a lambda expression and we get an 'it' iterator to access the 'result'
    // it.result.latitude gives the latitude
    // it.result.longitude gives the longitude 
    val geocoder = Geocoder(applicationContext, Locale.getDefault())
    val address = geocoder.getFromLocation(it.result.latitude, it.result.longitude, 1)
    if (address != null && address.size > 0) {
        // Get the current city
        city = address[0].locality
    }
}
location.addOnFailureListener {
    // Some error in getting the location, let's log it
    Log.d("xtraces", it.message)
}

获取位置的最佳方法如下所示

// put dependancy
 implementation 'com.google.android.gms:play-services-location:11.0.4'

// PUT permissions in Menifest
<uses-permission android:name="android.permission.INTERNET" />
<uses-permission android:name="android.permission.ACCESS_COARSE_LOCATION" />
<uses-permission android:name="android.permission.ACCESS_FINE_LOCATION" /> 


// create a Java file as below

public class SingleShotLocationProvider {

  public static interface LocationCallback {
      public void onNewLocationAvailable(GPSCoordinates location);
  }

   // calls back to calling thread, note this is for low grain: if you want higher precision, swap the
   // contents of the else and if. Also be sure to check gps permission/settings are allowed.
   // call usually takes <10ms

  public static void requestSingleUpdate(final Context context, final LocationCallback callback) {
    final LocationManager locationManager = (LocationManager) context.getSystemService(Context.LOCATION_SERVICE);
    boolean isNetworkEnabled = locationManager.isProviderEnabled(LocationManager.NETWORK_PROVIDER);
    if (isNetworkEnabled) {
        Criteria criteria = new Criteria();
        criteria.setAccuracy(Criteria.ACCURACY_COARSE);
        if (ActivityCompat.checkSelfPermission(context, Manifest.permission.ACCESS_FINE_LOCATION) != PackageManager.PERMISSION_GRANTED &&
                ActivityCompat.checkSelfPermission(context, Manifest.permission.ACCESS_COARSE_LOCATION) != PackageManager.PERMISSION_GRANTED) {

            return;
        }
        locationManager.requestSingleUpdate(criteria, new LocationListener() {
            @Override
            public void onLocationChanged(Location location) {
                callback.onNewLocationAvailable(new GPSCoordinates(location.getLatitude(), location.getLongitude()));
            }

            @Override
            public void onStatusChanged(String provider, int status, Bundle extras) {
            }

            @Override
            public void onProviderEnabled(String provider) {
            }

            @Override
            public void onProviderDisabled(String provider) {
            }
        }, null);
     } else {
        boolean isGPSEnabled = locationManager.isProviderEnabled(LocationManager.GPS_PROVIDER);
        if (isGPSEnabled) {
            Criteria criteria = new Criteria();
            criteria.setAccuracy(Criteria.ACCURACY_FINE);
            locationManager.requestSingleUpdate(criteria, new LocationListener() {
                @Override
                public void onLocationChanged(Location location) {
                    callback.onNewLocationAvailable(new GPSCoordinates(location.getLatitude(), location.getLongitude()));
                }

                @Override public void onStatusChanged(String provider, int status, Bundle extras) { }
                @Override public void onProviderEnabled(String provider) { }
                @Override public void onProviderDisabled(String provider) { }
            }, null);
        }
     }
  }


  // consider returning Location instead of this dummy wrapper class
  public static class GPSCoordinates {
     public float longitude = -1;
     public float latitude = -1;

     public GPSCoordinates(float theLatitude, float theLongitude) {
        longitude = theLongitude;
        latitude = theLatitude;
     }

     public GPSCoordinates(double theLatitude, double theLongitude) {
        longitude = (float) theLongitude;
        latitude = (float) theLatitude;
     }
  }

}
// FILE FINISHED


// FETCH LOCATION FROM ACTIVITY AS BELOW
public void getLocation(Context context) {
    MyApplication.log(LOG_TAG, "getLocation() ");

    SingleShotLocationProvider.requestSingleUpdate(context,
            new SingleShotLocationProvider.LocationCallback() {
                @Override
                public void onNewLocationAvailable(SingleShotLocationProvider.GPSCoordinates loc) {
                    location = loc;
                    MyApplication.log(LOG_TAG, "getLocation() LAT: " + location.latitude + ", LON: " + location.longitude);               
                }
            });
}

Edit 2022:不要使用这个库,因为该库有内存泄漏,不再支持/更新。

我将推荐使用智能位置库 使用起来非常简单,它很好地包装了位置逻辑。

启动位置服务:

SmartLocation.with(context).location()
    .start(new OnLocationUpdatedListener() { ... });

如果你只想获得一个单一的位置(不是周期性的),你可以使用oneFix修饰符。例子:

SmartLocation.with(context).location()
    .oneFix()
    .start(new OnLocationUpdatedListener() { ... });