你可以使用Magiq，一个LINQ的批处理操作框架。

你可以使用Magiq，一个LINQ的批处理操作框架。

这是我使用的扩展方法…

    /// <summary>
    /// Executes an Update statement block on all elements in an  IEnumerable of T
    /// sequence.
    /// </summary>
    /// <typeparam name="TSource">The source element type.</typeparam>
    /// <param name="source">The source sequence.</param>
    /// <param name="action">The action method to execute for each element.</param>
    /// <returns>The number of records affected.</returns>
    public static int Update<TSource>(this IEnumerable<TSource> source, Func<TSource> action)
    {
        if (source == null) throw new ArgumentNullException("source");
        if (action == null) throw new ArgumentNullException("action");
        if (typeof (TSource).IsValueType)
            throw new NotSupportedException("value type elements are not supported by update.");

        var count = 0;
        foreach (var element in source)
        {
            action(element);
            count++;
        }
        return count;
    }

我正在做这个

Collection.All(c => { c.needsChange = value; return true; });

我已经尝试了一些变化，我一直回到这个家伙的解。

http://www.hookedonlinq.com/UpdateOperator.ashx

同样，这是别人的解。但我已经将代码编译成一个小库，并经常使用它。

我将把他的代码粘贴在这里，以防他的网站(博客)在未来的某个时候不复存在。(没有什么比看到一个帖子说“这是你需要的确切答案”更糟糕的了，点击，然后是死网址。)

    public static class UpdateExtensions {

    public delegate void Func<TArg0>(TArg0 element);

    /// <summary>
    /// Executes an Update statement block on all elements in an IEnumerable<T> sequence.
    /// </summary>
    /// <typeparam name="TSource">The source element type.</typeparam>
    /// <param name="source">The source sequence.</param>
    /// <param name="update">The update statement to execute for each element.</param>
    /// <returns>The numer of records affected.</returns>
    public static int Update<TSource>(this IEnumerable<TSource> source, Func<TSource> update)
    {
        if (source == null) throw new ArgumentNullException("source");
        if (update == null) throw new ArgumentNullException("update");
        if (typeof(TSource).IsValueType)
            throw new NotSupportedException("value type elements are not supported by update.");

        int count = 0;
        foreach (TSource element in source)
        {
            update(element);
            count++;
        }
        return count;
    }
}



int count = drawingObjects
        .Where(d => d.IsSelected && d.Color == Colors.Blue)
        .Update(e => { e.Color = Color.Red; e.Selected = false; } );

实际上我找到了一个扩展方法，可以很好地完成我想要的

public static IEnumerable<T> ForEach<T>(
    this IEnumerable<T> source,
    Action<T> act)
{
    foreach (T element in source) act(element);
    return source;
}