我的问题是，我希望返回camelcases(而不是标准PascalCase) JSON数据通过ActionResults从ASP。NET MVC控制器方法，由JSON.NET序列化。
作为一个例子，考虑下面的c#类:
public class Person
{
public string FirstName { get; set; }
public string LastName { get; set; }
}
默认情况下，当从MVC控制器返回这个类的实例作为JSON时，它将以以下方式序列化:
{
"FirstName": "Joe",
"LastName": "Public"
}
我希望它被序列化(由JSON.NET)为:
{
"firstName": "Joe",
"lastName": "Public"
}
我怎么做呢?
当前回答
下面是一个动作方法，通过序列化一个对象数组返回一个json字符串(cameCase)。
public string GetSerializedCourseVms()
{
var courses = new[]
{
new CourseVm{Number = "CREA101", Name = "Care of Magical Creatures", Instructor ="Rubeus Hagrid"},
new CourseVm{Number = "DARK502", Name = "Defence against dark arts", Instructor ="Severus Snape"},
new CourseVm{Number = "TRAN201", Name = "Transfiguration", Instructor ="Minerva McGonal"}
};
var camelCaseFormatter = new JsonSerializerSettings();
camelCaseFormatter.ContractResolver = new CamelCasePropertyNamesContractResolver();
return JsonConvert.SerializeObject(courses, camelCaseFormatter);
}
注意作为第二个参数传递的JsonSerializerSettings实例。这就是骆驼案发生的原因。
其他回答
我在Mats Karlsson的博客上找到了一个很好的解决方法。解决方案是编写ActionResult的子类，通过JSON序列化数据。NET，将后者配置为遵循camelCase约定:
public class JsonCamelCaseResult : ActionResult
{
public JsonCamelCaseResult(object data, JsonRequestBehavior jsonRequestBehavior)
{
Data = data;
JsonRequestBehavior = jsonRequestBehavior;
}
public Encoding ContentEncoding { get; set; }
public string ContentType { get; set; }
public object Data { get; set; }
public JsonRequestBehavior JsonRequestBehavior { get; set; }
public override void ExecuteResult(ControllerContext context)
{
if (context == null)
{
throw new ArgumentNullException("context");
}
if (JsonRequestBehavior == JsonRequestBehavior.DenyGet && String.Equals(context.HttpContext.Request.HttpMethod, "GET", StringComparison.OrdinalIgnoreCase))
{
throw new InvalidOperationException("This request has been blocked because sensitive information could be disclosed to third party web sites when this is used in a GET request. To allow GET requests, set JsonRequestBehavior to AllowGet.");
}
var response = context.HttpContext.Response;
response.ContentType = !String.IsNullOrEmpty(ContentType) ? ContentType : "application/json";
if (ContentEncoding != null)
{
response.ContentEncoding = ContentEncoding;
}
if (Data == null)
return;
var jsonSerializerSettings = new JsonSerializerSettings
{
ContractResolver = new CamelCasePropertyNamesContractResolver()
};
response.Write(JsonConvert.SerializeObject(Data, jsonSerializerSettings));
}
}
然后在你的MVC控制器方法中像下面这样使用这个类:
public ActionResult GetPerson()
{
return new JsonCamelCaseResult(new Person { FirstName = "Joe", LastName = "Public" }, JsonRequestBehavior.AllowGet)};
}
对于WebAPI，请查看这个链接: http://odetocode.com/blogs/scott/archive/2013/03/25/asp-net-webapi-tip-3-camelcasing-json.aspx
基本上，添加以下代码到你的Application_Start:
var formatters = GlobalConfiguration.Configuration.Formatters;
var jsonFormatter = formatters.JsonFormatter;
var settings = jsonFormatter.SerializerSettings;
settings.ContractResolver = new CamelCasePropertyNamesContractResolver();
或者，简单地说:
JsonConvert.SerializeObject(
<YOUR OBJECT>,
new JsonSerializerSettings
{
ContractResolver = new CamelCasePropertyNamesContractResolver()
});
例如:
return new ContentResult
{
ContentType = "application/json",
Content = JsonConvert.SerializeObject(new { content = result, rows = dto }, new JsonSerializerSettings { ContractResolver = new CamelCasePropertyNamesContractResolver() }),
ContentEncoding = Encoding.UTF8
};
如果你在。net core web api中返回ActionResult，或IHttpAction结果，那么你可以用Ok()方法包装你的模型，该方法将匹配你前端的情况并为你序列化它。不需要使用JsonConvert。：）
安装包Microsoft.AspNetCore.Mvc.NewtonsoftJson
这解决了我的问题
