我的问题是，我希望返回camelcases(而不是标准PascalCase) JSON数据通过ActionResults从ASP。NET MVC控制器方法，由JSON.NET序列化。
作为一个例子，考虑下面的c#类:
public class Person
{
public string FirstName { get; set; }
public string LastName { get; set; }
}
默认情况下，当从MVC控制器返回这个类的实例作为JSON时，它将以以下方式序列化:
{
"FirstName": "Joe",
"LastName": "Public"
}
我希望它被序列化(由JSON.NET)为:
{
"firstName": "Joe",
"lastName": "Public"
}
我怎么做呢?
当前回答
您必须在“Startup.cs”文件中设置设置
您还必须在JsonConvert的默认值中定义它，这是如果您以后想直接使用库来序列化对象。
public void ConfigureServices(IServiceCollection services)
{
services.AddMvc().SetCompatibilityVersion(CompatibilityVersion.Version_2_2)
.AddJsonOptions(options => {
options.SerializerSettings.NullValueHandling = NullValueHandling.Ignore;
options.SerializerSettings.ContractResolver = new CamelCasePropertyNamesContractResolver();
});
JsonConvert.DefaultSettings = () => new JsonSerializerSettings
{
NullValueHandling = NullValueHandling.Ignore,
ContractResolver = new CamelCasePropertyNamesContractResolver()
};
}
其他回答
下面是一个动作方法，通过序列化一个对象数组返回一个json字符串(cameCase)。
public string GetSerializedCourseVms()
{
var courses = new[]
{
new CourseVm{Number = "CREA101", Name = "Care of Magical Creatures", Instructor ="Rubeus Hagrid"},
new CourseVm{Number = "DARK502", Name = "Defence against dark arts", Instructor ="Severus Snape"},
new CourseVm{Number = "TRAN201", Name = "Transfiguration", Instructor ="Minerva McGonal"}
};
var camelCaseFormatter = new JsonSerializerSettings();
camelCaseFormatter.ContractResolver = new CamelCasePropertyNamesContractResolver();
return JsonConvert.SerializeObject(courses, camelCaseFormatter);
}
注意作为第二个参数传递的JsonSerializerSettings实例。这就是骆驼案发生的原因。
或者，简单地说:
JsonConvert.SerializeObject(
<YOUR OBJECT>,
new JsonSerializerSettings
{
ContractResolver = new CamelCasePropertyNamesContractResolver()
});
例如:
return new ContentResult
{
ContentType = "application/json",
Content = JsonConvert.SerializeObject(new { content = result, rows = dto }, new JsonSerializerSettings { ContractResolver = new CamelCasePropertyNamesContractResolver() }),
ContentEncoding = Encoding.UTF8
};
自定义过滤器的另一种选择是创建一个扩展方法，将任何对象序列化为JSON。
public static class ObjectExtensions
{
/// <summary>Serializes the object to a JSON string.</summary>
/// <returns>A JSON string representation of the object.</returns>
public static string ToJson(this object value)
{
var settings = new JsonSerializerSettings
{
ContractResolver = new CamelCasePropertyNamesContractResolver(),
Converters = new List<JsonConverter> { new StringEnumConverter() }
};
return JsonConvert.SerializeObject(value, settings);
}
}
然后在从控制器动作返回时调用它。
return Content(person.ToJson(), "application/json");
在我看来越简单越好!
你为什么不这样做呢?
public class CourseController : JsonController
{
public ActionResult ManageCoursesModel()
{
return JsonContent(<somedata>);
}
}
简单基类控制器
public class JsonController : BaseController
{
protected ContentResult JsonContent(Object data)
{
return new ContentResult
{
ContentType = "application/json",
Content = JsonConvert.SerializeObject(data, new JsonSerializerSettings {
ContractResolver = new CamelCasePropertyNamesContractResolver() }),
ContentEncoding = Encoding.UTF8
};
}
}
您必须在“Startup.cs”文件中设置设置
您还必须在JsonConvert的默认值中定义它，这是如果您以后想直接使用库来序列化对象。
public void ConfigureServices(IServiceCollection services)
{
services.AddMvc().SetCompatibilityVersion(CompatibilityVersion.Version_2_2)
.AddJsonOptions(options => {
options.SerializerSettings.NullValueHandling = NullValueHandling.Ignore;
options.SerializerSettings.ContractResolver = new CamelCasePropertyNamesContractResolver();
});
JsonConvert.DefaultSettings = () => new JsonSerializerSettings
{
NullValueHandling = NullValueHandling.Ignore,
ContractResolver = new CamelCasePropertyNamesContractResolver()
};
}
