我的问题是，我希望返回camelcases(而不是标准PascalCase) JSON数据通过ActionResults从ASP。NET MVC控制器方法，由JSON.NET序列化。
作为一个例子，考虑下面的c#类:
public class Person
{
public string FirstName { get; set; }
public string LastName { get; set; }
}
默认情况下，当从MVC控制器返回这个类的实例作为JSON时，它将以以下方式序列化:
{
"FirstName": "Joe",
"LastName": "Public"
}
我希望它被序列化(由JSON.NET)为:
{
"firstName": "Joe",
"lastName": "Public"
}
我怎么做呢?
当前回答
安装包Microsoft.AspNetCore.Mvc.NewtonsoftJson
这解决了我的问题
其他回答
我在Mats Karlsson的博客上找到了一个很好的解决方法。解决方案是编写ActionResult的子类，通过JSON序列化数据。NET，将后者配置为遵循camelCase约定:
public class JsonCamelCaseResult : ActionResult
{
public JsonCamelCaseResult(object data, JsonRequestBehavior jsonRequestBehavior)
{
Data = data;
JsonRequestBehavior = jsonRequestBehavior;
}
public Encoding ContentEncoding { get; set; }
public string ContentType { get; set; }
public object Data { get; set; }
public JsonRequestBehavior JsonRequestBehavior { get; set; }
public override void ExecuteResult(ControllerContext context)
{
if (context == null)
{
throw new ArgumentNullException("context");
}
if (JsonRequestBehavior == JsonRequestBehavior.DenyGet && String.Equals(context.HttpContext.Request.HttpMethod, "GET", StringComparison.OrdinalIgnoreCase))
{
throw new InvalidOperationException("This request has been blocked because sensitive information could be disclosed to third party web sites when this is used in a GET request. To allow GET requests, set JsonRequestBehavior to AllowGet.");
}
var response = context.HttpContext.Response;
response.ContentType = !String.IsNullOrEmpty(ContentType) ? ContentType : "application/json";
if (ContentEncoding != null)
{
response.ContentEncoding = ContentEncoding;
}
if (Data == null)
return;
var jsonSerializerSettings = new JsonSerializerSettings
{
ContractResolver = new CamelCasePropertyNamesContractResolver()
};
response.Write(JsonConvert.SerializeObject(Data, jsonSerializerSettings));
}
}
然后在你的MVC控制器方法中像下面这样使用这个类:
public ActionResult GetPerson()
{
return new JsonCamelCaseResult(new Person { FirstName = "Joe", LastName = "Public" }, JsonRequestBehavior.AllowGet)};
}
我是这样做的:
public static class JsonExtension
{
public static string ToJson(this object value)
{
var settings = new JsonSerializerSettings
{
ContractResolver = new CamelCasePropertyNamesContractResolver(),
NullValueHandling = NullValueHandling.Ignore,
ReferenceLoopHandling = ReferenceLoopHandling.Serialize
};
return JsonConvert.SerializeObject(value, settings);
}
}
这是MVC核心中一个简单的扩展方法，它会给你项目中的每个对象ToJson()能力，在我看来，在一个MVC项目中，大多数对象应该有成为json的能力，当然这取决于:)
如果你在。net core web api中返回ActionResult，或IHttpAction结果，那么你可以用Ok()方法包装你的模型，该方法将匹配你前端的情况并为你序列化它。不需要使用JsonConvert。：）
在我看来越简单越好!
你为什么不这样做呢?
public class CourseController : JsonController
{
public ActionResult ManageCoursesModel()
{
return JsonContent(<somedata>);
}
}
简单基类控制器
public class JsonController : BaseController
{
protected ContentResult JsonContent(Object data)
{
return new ContentResult
{
ContentType = "application/json",
Content = JsonConvert.SerializeObject(data, new JsonSerializerSettings {
ContractResolver = new CamelCasePropertyNamesContractResolver() }),
ContentEncoding = Encoding.UTF8
};
}
}
或者，简单地说:
JsonConvert.SerializeObject(
<YOUR OBJECT>,
new JsonSerializerSettings
{
ContractResolver = new CamelCasePropertyNamesContractResolver()
});
例如:
return new ContentResult
{
ContentType = "application/json",
Content = JsonConvert.SerializeObject(new { content = result, rows = dto }, new JsonSerializerSettings { ContractResolver = new CamelCasePropertyNamesContractResolver() }),
ContentEncoding = Encoding.UTF8
};
