我的问题是，我希望返回camelcases(而不是标准PascalCase) JSON数据通过ActionResults从ASP。NET MVC控制器方法，由JSON.NET序列化。
作为一个例子，考虑下面的c#类:
public class Person
{
public string FirstName { get; set; }
public string LastName { get; set; }
}
默认情况下，当从MVC控制器返回这个类的实例作为JSON时，它将以以下方式序列化:
{
"FirstName": "Joe",
"LastName": "Public"
}
我希望它被序列化(由JSON.NET)为:
{
"firstName": "Joe",
"lastName": "Public"
}
我怎么做呢?
当前回答
我想这就是你想要的简单答案。这是Shawn Wildermuth的博客:
// Add MVC services to the services container.
services.AddMvc()
.AddJsonOptions(opts =>
{
opts.SerializerSettings.ContractResolver = new CamelCasePropertyNamesContractResolver();
});
其他回答
如果你在。net core web api中返回ActionResult，或IHttpAction结果，那么你可以用Ok()方法包装你的模型，该方法将匹配你前端的情况并为你序列化它。不需要使用JsonConvert。：）
将Json NamingStrategy属性添加到类定义中。
[JsonObject(NamingStrategyType = typeof(CamelCaseNamingStrategy))] 公共阶层人 ｛ public string FirstName {get;设置;｝ 公共字符串LastName {get;设置;｝ ｝
或者，简单地说:
JsonConvert.SerializeObject(
<YOUR OBJECT>,
new JsonSerializerSettings
{
ContractResolver = new CamelCasePropertyNamesContractResolver()
});
例如:
return new ContentResult
{
ContentType = "application/json",
Content = JsonConvert.SerializeObject(new { content = result, rows = dto }, new JsonSerializerSettings { ContractResolver = new CamelCasePropertyNamesContractResolver() }),
ContentEncoding = Encoding.UTF8
};
下面是一个动作方法，通过序列化一个对象数组返回一个json字符串(cameCase)。
public string GetSerializedCourseVms()
{
var courses = new[]
{
new CourseVm{Number = "CREA101", Name = "Care of Magical Creatures", Instructor ="Rubeus Hagrid"},
new CourseVm{Number = "DARK502", Name = "Defence against dark arts", Instructor ="Severus Snape"},
new CourseVm{Number = "TRAN201", Name = "Transfiguration", Instructor ="Minerva McGonal"}
};
var camelCaseFormatter = new JsonSerializerSettings();
camelCaseFormatter.ContractResolver = new CamelCasePropertyNamesContractResolver();
return JsonConvert.SerializeObject(courses, camelCaseFormatter);
}
注意作为第二个参数传递的JsonSerializerSettings实例。这就是骆驼案发生的原因。
自定义过滤器的另一种选择是创建一个扩展方法，将任何对象序列化为JSON。
public static class ObjectExtensions
{
/// <summary>Serializes the object to a JSON string.</summary>
/// <returns>A JSON string representation of the object.</returns>
public static string ToJson(this object value)
{
var settings = new JsonSerializerSettings
{
ContractResolver = new CamelCasePropertyNamesContractResolver(),
Converters = new List<JsonConverter> { new StringEnumConverter() }
};
return JsonConvert.SerializeObject(value, settings);
}
}
然后在从控制器动作返回时调用它。
return Content(person.ToJson(), "application/json");
