我需要测试是否设置了一个变量。我尝试了几种技术,但每当%1被引号包围时,它们似乎都失败了,例如%1是“c:\一些带空格的路径”。

IF NOT %1 GOTO MyLabel // This is invalid syntax
IF "%1" == "" GOTO MyLabel // Works unless %1 has double quotes which fatally kills bat execution
IF %1 == GOTO MyLabel // Gives an unexpected GOTO error.

根据这个网站,这些是支持的IF语法类型。所以,我不知道该怎么做。

IF [NOT] ERRORLEVEL number command
IF [NOT] string1==string2 command
IF [NOT] EXIST filename command

更新:在2020-10-25,我更新了接受的答案,从使用括号到使用波浪号。每个人都说波浪更好,因为它更安全。我有点撕裂,因为波浪线看起来更复杂,不太清楚它的目的是什么,但尽管如此,我改变了它。


当前回答

This way looks correct:

if "%~1" == "" if [%1] == [] echo Argument 1 is really empty.

First filter (if "%~1" == "") из safe way to detect argument is empty or "".
Second filter (if [%1] == []) will skip "" argument.
Remember we have two kind of empty arguments : really empty (nothing) and empty quotes "".
We have to detect both.

Next code takes all arguments "as is" in variable args:

:GetArgs
set args=%1
:ParseArgs
shift /1
if "%~1" == "" if [%1] == [] goto :DoneArgs
set args=%args% %1
goto :ParseArgs
:DoneArgs
if not defined args echo No arguments
if defined args echo Aguments are: %args%

This code correctly process "normal" arguments (simple words, "multiword phrases" or "") with balanced quotes.
Quoted arguments can even contain special chars like "a & b".
But it is still can fail with "abnormal" expressions with unbalanced quotes (do not use them).

其他回答

最好的半解决方案之一是将%1复制到一个变量中,然后使用延迟展开,如delayedxp。对于任何内容总是安全的。

set "param1=%~1"
setlocal EnableDelayedExpansion
if "!param1!"=="" ( echo it is empty )
rem ... or use the DEFINED keyword now
if defined param1 echo There is something

这样做的好处是处理param1是绝对安全的。

param1的设置将在许多情况下工作,如

test.bat hello"this is"a"test
test.bat you^&me

但它仍然失败于一些奇怪的内容,比如

test.bat ^&"&

才能得到100%的正确答案

它检测%1是否为空,但对于某些内容,它无法获取内容。 这对于区分空%1和有""的%1也是有用的。 它使用CALL命令的能力在不中止批处理文件的情况下失败。

@echo off
setlocal EnableDelayedExpansion
set "arg1="
call set "arg1=%%1"

if defined arg1 goto :arg_exists

set "arg1=#"
call set "arg1=%%1"
if "!arg1!" EQU "#" (
    echo arg1 exists, but can't assigned to a variable
    REM Try to fetch it a second time without quotes
    (call set arg1=%%1)
    goto :arg_exists
)

echo arg1 is missing
exit /b

:arg_exists
echo arg1 exists, perhaps the content is '!arg1!'

如果你想100%防弹获取内容,你可以阅读如何接收甚至是最奇怪的命令行参数?

不幸的是,我没有足够的声誉来评论或投票目前的答案,我不得不自己写。

最初OP的问题说的是“变量”而不是“参数”,这让人非常困惑,特别是因为这是谷歌中搜索如何测试空白变量的头号链接。自从我最初的答案以来,Stephan编辑了原始问题,以使用正确的术语,但我没有删除我的答案,而是决定留下它来帮助澄清任何困惑,特别是在谷歌仍然派人来这里寻找变量的情况下:

%1不是变量!它是一个命令行参数。

非常重要的区别。后面带数字的单个百分号表示命令行参数,而不是变量。

使用set命令设置变量,并使用2%符号(一个在前面,一个在后面)回收变量。例如%myvar%

要测试空变量,您可以使用“if not defined”语法(显式变量命令不需要任何百分号),例如:

set myvar1=foo  
if not defined myvar1 echo You won't see this because %myvar1% is defined.  
if not defined myvar2 echo You will see this because %myvar2% isn't defined.

(如果你想测试命令行参数,那么我建议参考jamesdlin的答案。)

使用!而不是“空字符串检查”

@echo off
SET a=
SET b=Hello
IF !%a%! == !! echo String a is empty
IF !%b%! == !! echo String b is empty

我根据这里的答案创建了这个小批处理脚本,因为有很多有效的答案。只要遵循相同的格式,可以随意添加:

REM Parameter-testing

Setlocal EnableDelayedExpansion EnableExtensions

IF NOT "%~1"=="" (echo Percent Tilde 1 failed with quotes) ELSE (echo SUCCESS)
IF NOT [%~1]==[] (echo Percent Tilde 1 failed with brackets) ELSE (echo SUCCESS)
IF NOT  "%1"=="" (echo Quotes one failed) ELSE (echo SUCCESS)
IF NOT [%1]==[] (echo Brackets one failed) ELSE (echo SUCCESS)
IF NOT "%1."=="." (echo Appended dot quotes one failed) ELSE (echo SUCCESS)
IF NOT [%1.]==[.] (echo Appended dot brackets one failed) ELSE (echo SUCCESS)

pause

空字符串是一对双引号/"",我们可以直接测试长度:

set ARG=%1
if not defined ARG goto nomore

set CHAR=%ARG:~2,1%
if defined CHAR goto goon

然后用双引号测试它的2个字符:

if ^%ARG:~1,1% == ^" if ^%ARG:~0,1% == ^" goto blank
::else
goto goon

这里有一个您可以使用的批处理脚本。我觉得它正好接住了空弦。

这只是一个例子,你只需要根据你的脚本定制上面的2(或3?)步骤。

@echo off
if not "%OS%"=="Windows_NT" goto EOF
:: I guess we need enableExtensions, CMIIW
setLocal enableExtensions
set i=0
set script=%0

:LOOP
set /a i=%i%+1

set A1=%1
if not defined A1 goto nomore

:: Assumption:
:: Empty string is (exactly) a pair of double-quotes ("")

:: Step out if str length is more than 2
set C3=%A1:~2,1%
if defined C3 goto goon

:: Check the first and second char for double-quotes
:: Any characters will do fine since we test it *literally*
if ^%A1:~1,1% == ^" if ^%A1:~0,1% == ^" goto blank
goto goon

:goon
echo.args[%i%]: [%1]
shift
goto LOOP

:blank
echo.args[%i%]: [%1] is empty string
shift
goto LOOP

:nomore
echo.
echo.command line:
echo.%script% %*

:EOF

酷刑测试结果:

.test.bat :: ""  ">"""bl" " "< "">"  (")(") "" :: ""-"  " "( )"">\>" ""
args[1]: [::]
args[2]: [""] is empty string
args[3]: [">"""bl" "]
args[4]: ["< "">"]
args[5]: [(")(")]
args[6]: [""] is empty string
args[7]: [::]
args[8]: [""-"  "]
args[9]: ["( )"">\>"]
args[10]: [""] is empty string

command line:
.test.bat :: ""  ">"""bl" " "< "">"  (")(") "" :: ""-"  " "( )"">\>" ""