我需要测试是否设置了一个变量。我尝试了几种技术,但每当%1被引号包围时,它们似乎都失败了,例如%1是“c:\一些带空格的路径”。

IF NOT %1 GOTO MyLabel // This is invalid syntax
IF "%1" == "" GOTO MyLabel // Works unless %1 has double quotes which fatally kills bat execution
IF %1 == GOTO MyLabel // Gives an unexpected GOTO error.

根据这个网站,这些是支持的IF语法类型。所以,我不知道该怎么做。

IF [NOT] ERRORLEVEL number command
IF [NOT] string1==string2 command
IF [NOT] EXIST filename command

更新:在2020-10-25,我更新了接受的答案,从使用括号到使用波浪号。每个人都说波浪更好,因为它更安全。我有点撕裂,因为波浪线看起来更复杂,不太清楚它的目的是什么,但尽管如此,我改变了它。


当前回答

最简单的解决方案,由两行代码组成:

SET /A var02 = %var01% / 1
IF %ERRORLEVEL% NEQ 0 (ECHO Variable var01 is NOT EXIST)

其他回答

从IF /?:

如果命令扩展是启用If 变更如下: IF [/I] string1 compare-op string2命令 IF CMDEXTVERSION编号命令 IF定义变量命令 ...... DEFINED条件刚好 像EXISTS一样,除了它需要一个 环境变量名称和返回值 如果环境变量为,则为 定义的。

你可以使用:

IF "%~1" == "" GOTO MyLabel

去掉外部的引号。一般来说,这是一种比使用方括号更可靠的方法,因为即使变量中有空格,它也能工作。

This way looks correct:

if "%~1" == "" if [%1] == [] echo Argument 1 is really empty.

First filter (if "%~1" == "") из safe way to detect argument is empty or "".
Second filter (if [%1] == []) will skip "" argument.
Remember we have two kind of empty arguments : really empty (nothing) and empty quotes "".
We have to detect both.

Next code takes all arguments "as is" in variable args:

:GetArgs
set args=%1
:ParseArgs
shift /1
if "%~1" == "" if [%1] == [] goto :DoneArgs
set args=%args% %1
goto :ParseArgs
:DoneArgs
if not defined args echo No arguments
if defined args echo Aguments are: %args%

This code correctly process "normal" arguments (simple words, "multiword phrases" or "") with balanced quotes.
Quoted arguments can even contain special chars like "a & b".
But it is still can fail with "abnormal" expressions with unbalanced quotes (do not use them).

使用!而不是“空字符串检查”

@echo off
SET a=
SET b=Hello
IF !%a%! == !! echo String a is empty
IF !%b%! == !! echo String b is empty

你可以使用

if defined (variable) echo That's defined!
if not defined (variable) echo Nope. Undefined.