我收集了一些极端案例和脑筋急转弯,总是想听到更多。这个页面只涵盖了c#语言的一些细节,但我也发现了。net核心的东西也很有趣。例如,这里有一个没有在页面上,但我觉得不可思议:

string x = new string(new char[0]);
string y = new string(new char[0]);
Console.WriteLine(object.ReferenceEquals(x, y));

我希望输出False -毕竟,“new”(具有引用类型)总是创建一个新对象,不是吗?c#和CLI的规范都表明应该这样做。嗯,在这个特殊情况下不是这样。它输出True,并且在我测试过的框架的每个版本上都是这样。(不可否认,我还没有在Mono上尝试过……)

只是为了澄清,这只是我正在寻找的事情的一个例子-我并不是特别寻找对这个奇怪现象的讨论/解释。(这和普通的弦乐实习不一样;特别地,当调用构造函数时,字符串实习通常不会发生。)我真的是在要求类似的奇怪行为。

还有其他的宝藏吗?


当前回答

下面将打印False而不是抛出溢出异常:

Console.WriteLine("{0}", yep(int.MaxValue ));


private bool yep( int val )
{
    return ( 0 < val * 2);
}

其他回答

我不确定你是否会说这是Windows Vista/7的怪癖或。net的怪癖,但它让我挠头了好一阵子。

string filename = @"c:\program files\my folder\test.txt";
System.IO.File.WriteAllText(filename, "Hello world.");
bool exists = System.IO.File.Exists(filename); // returns true;
string text = System.IO.File.ReadAllText(filename); // Returns "Hello world."

在Windows Vista/7中,文件实际上会被写入C:\Users\<username>\Virtual Store\Program Files\my folder\test.txt

This one's pretty hard to top. I ran into it while I was trying to build a RealProxy implementation that truly supports Begin/EndInvoke (thanks MS for making this impossible to do without horrible hacks). This example is basically a bug in the CLR, the unmanaged code path for BeginInvoke doesn't validate that the return message from RealProxy.PrivateInvoke (and my Invoke override) is returning an instance of an IAsyncResult. Once it's returned, the CLR gets incredibly confused and loses any idea of whats going on, as demonstrated by the tests at the bottom.

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Runtime.Remoting.Proxies;
using System.Reflection;
using System.Runtime.Remoting.Messaging;

namespace BrokenProxy
{
    class NotAnIAsyncResult
    {
        public string SomeProperty { get; set; }
    }

    class BrokenProxy : RealProxy
    {
        private void HackFlags()
        {
            var flagsField = typeof(RealProxy).GetField("_flags", BindingFlags.NonPublic | BindingFlags.Instance);
            int val = (int)flagsField.GetValue(this);
            val |= 1; // 1 = RemotingProxy, check out System.Runtime.Remoting.Proxies.RealProxyFlags
            flagsField.SetValue(this, val);
        }

        public BrokenProxy(Type t)
            : base(t)
        {
            HackFlags();
        }

        public override IMessage Invoke(IMessage msg)
        {
            var naiar = new NotAnIAsyncResult();
            naiar.SomeProperty = "o noes";
            return new ReturnMessage(naiar, null, 0, null, (IMethodCallMessage)msg);
        }
    }

    interface IRandomInterface
    {
        int DoSomething();
    }

    class Program
    {
        static void Main(string[] args)
        {
            BrokenProxy bp = new BrokenProxy(typeof(IRandomInterface));
            var instance = (IRandomInterface)bp.GetTransparentProxy();
            Func<int> doSomethingDelegate = instance.DoSomething;
            IAsyncResult notAnIAsyncResult = doSomethingDelegate.BeginInvoke(null, null);

            var interfaces = notAnIAsyncResult.GetType().GetInterfaces();
            Console.WriteLine(!interfaces.Any() ? "No interfaces on notAnIAsyncResult" : "Interfaces");
            Console.WriteLine(notAnIAsyncResult is IAsyncResult); // Should be false, is it?!
            Console.WriteLine(((NotAnIAsyncResult)notAnIAsyncResult).SomeProperty);
            Console.WriteLine(((IAsyncResult)notAnIAsyncResult).IsCompleted); // No way this works.
        }
    }
}

输出:

No interfaces on notAnIAsyncResult
True
o noes

Unhandled Exception: System.EntryPointNotFoundException: Entry point was not found.
   at System.IAsyncResult.get_IsCompleted()
   at BrokenProxy.Program.Main(String[] args) 

下面是一个示例,说明如何创建导致错误消息“试图读写受保护内存”的结构。这通常表明其他记忆被破坏了。” 成功与失败的差别非常细微。

下面的单元测试演示了这个问题。

看看你能不能找出问题出在哪里。

    [Test]
    public void Test()
    {
        var bar = new MyClass
        {
            Foo = 500
        };
        bar.Foo += 500;

        Assert.That(bar.Foo.Value.Amount, Is.EqualTo(1000));
    }

    private class MyClass
    {
        public MyStruct? Foo { get; set; }
    }

    private struct MyStruct
    {
        public decimal Amount { get; private set; }

        public MyStruct(decimal amount) : this()
        {
            Amount = amount;
        }

        public static MyStruct operator +(MyStruct x, MyStruct y)
        {
            return new MyStruct(x.Amount + y.Amount);
        }

        public static MyStruct operator +(MyStruct x, decimal y)
        {
            return new MyStruct(x.Amount + y);
        }

        public static implicit operator MyStruct(int value)
        {
            return new MyStruct(value);
        }

        public static implicit operator MyStruct(decimal value)
        {
            return new MyStruct(value);
        }
    }

我不久前问了一个问题:

条件运算符不能隐式强制转换?

考虑到:

Bool aBoolValue;

其中aBoolValue被赋值为True或False;

以下文件将无法编译:

Byte aByteValue = aBoolValue ? 1 : 0;

但这将:

Int anIntValue = aBoolValue ? 1 : 0;

提供的答案也很好。

今天刚发现一件小玩意儿

public class Base
{
   public virtual void Initialize(dynamic stuff) { 
   //...
   }
}
public class Derived:Base
{
   public override void Initialize(dynamic stuff) {
   base.Initialize(stuff);
   //...
   }
}

这会引发编译错误。

对方法'Initialize'的调用需要动态分派,但不能这样做,因为它是基本访问表达式的一部分。考虑强制转换动态参数或取消基本访问。

如果我写底。初始化(stuff as object);它工作得很完美,但这似乎是一个“神奇的词”,因为它的功能完全相同,一切仍然是动态的……