Bitmap bmp   = intent.getExtras().get("data");
  int size     = bmp.getRowBytes() * bmp.getHeight();
  ByteBuffer b = ByteBuffer.allocate(size);

  bmp.copyPixelsToBuffer(b);

  byte[] bytes = new byte[size];

  try {
     b.get(bytes, 0, bytes.length);
  } catch (BufferUnderflowException e) {
     // always happens
  }
  // do something with byte[]

当我在调用copyPixelsToBuffer后查看缓冲区时,字节都是0…从相机返回的位图是不可变的…但这不重要,因为它正在复制。

这段代码可能有什么问题?


当前回答

也许你需要倒带缓冲器?

同样,如果位图的步幅(以字节为单位)大于行长(以像素*字节/像素为单位),也可能发生这种情况。使字节的长度为b.remaining()而不是size。

其他回答

为了避免较大文件的OutOfMemory错误,我建议通过将位图分成几个部分并合并它们部分的字节来解决任务。

private byte[] getBitmapBytes(Bitmap bitmap)
{
    int chunkNumbers = 10;
    int bitmapSize = bitmap.getRowBytes() * bitmap.getHeight();
    byte[] imageBytes = new byte[bitmapSize];
    int rows, cols;
    int chunkHeight, chunkWidth;
    rows = cols = (int) Math.sqrt(chunkNumbers);
    chunkHeight = bitmap.getHeight() / rows;
    chunkWidth = bitmap.getWidth() / cols;

    int yCoord = 0;
    int bitmapsSizes = 0;

    for (int x = 0; x < rows; x++)
    {
        int xCoord = 0;
        for (int y = 0; y < cols; y++)
        {
            Bitmap bitmapChunk = Bitmap.createBitmap(bitmap, xCoord, yCoord, chunkWidth, chunkHeight);
            byte[] bitmapArray = getBytesFromBitmapChunk(bitmapChunk);
            System.arraycopy(bitmapArray, 0, imageBytes, bitmapsSizes, bitmapArray.length);
            bitmapsSizes = bitmapsSizes + bitmapArray.length;
            xCoord += chunkWidth;

            bitmapChunk.recycle();
            bitmapChunk = null;
        }
        yCoord += chunkHeight;
    }
    
    return imageBytes;
}


private byte[] getBytesFromBitmapChunk(Bitmap bitmap)
{
    int bitmapSize = bitmap.getRowBytes() * bitmap.getHeight();
    ByteBuffer byteBuffer = ByteBuffer.allocate(bitmapSize);
    bitmap.copyPixelsToBuffer(byteBuffer);
    byteBuffer.rewind();
    return byteBuffer.array();
}

我想这个可以

public static byte[] convertBitmapToByteArray(Bitmap bitmap){
        ByteBuffer byteBuffer = ByteBuffer.allocate(bitmap.getByteCount());
        bitmap.copyPixelsToBuffer(byteBuffer);
        byteBuffer.rewind();
        return byteBuffer.array();
    }

使用下面的函数将位图编码为字节[],反之亦然

public static String encodeTobase64(Bitmap image) {
    Bitmap immagex = image;
    ByteArrayOutputStream baos = new ByteArrayOutputStream();
    immagex.compress(Bitmap.CompressFormat.PNG, 90, baos);
    byte[] b = baos.toByteArray();
    String imageEncoded = Base64.encodeToString(b, Base64.DEFAULT);
    return imageEncoded;
}

public static Bitmap decodeBase64(String input) {
    byte[] decodedByte = Base64.decode(input, 0);
    return BitmapFactory.decodeByteArray(decodedByte, 0, decodedByte.length);
}

Ted Hopp是正确的,摘自API文档:

public void copyPixelsToBuffer (Buffer dst)

“…该方法返回后,缓冲区的当前位置将被更新:位置将按写入缓冲区的元素数量递增。 "

and

public ByteBuffer get (byte[] dst, int dstOffset, int byteCount)

从指定的偏移量开始,将字节从当前位置读入指定的字节数组,并将位置增加所读的字节数。

尝试转换字符串-位图或位图-字符串

/**
 * @param bitmap
 * @return converting bitmap and return a string
 */
public static String BitMapToString(Bitmap bitmap){
    ByteArrayOutputStream baos=new ByteArrayOutputStream();
    bitmap.compress(Bitmap.CompressFormat.PNG,100, baos);
    byte [] b=baos.toByteArray();
    String temp=Base64.encodeToString(b, Base64.DEFAULT);
    return temp;
}

/**
 * @param encodedString
 * @return bitmap (from given string)
 */
public static Bitmap StringToBitMap(String encodedString){
    try{
        byte [] encodeByte=Base64.decode(encodedString,Base64.DEFAULT);
        Bitmap bitmap= BitmapFactory.decodeByteArray(encodeByte, 0, encodeByte.length);
        return bitmap;
    }catch(Exception e){
        e.getMessage();
        return null;
    }
}