试试这个:

if (s.charAt(0) == s.charAt(s.length() - 1))

代码:

public class Test {
    public static void main(String args[]) {
        String string = args[0];
        System.out.println("last character: " +
                           string.substring(string.length() - 1)); 
    }
}

java Test abcdef的输出:

last character: f

下面是我用来获取字符串的最后n个字符的方法:

public static String takeLast(String value, int count) {
    if (value == null || value.trim().length() == 0) return "";
    if (count < 1) return "";

    if (value.length() > count) {
        return value.substring(value.length() - count);
    } else {
        return value;
    }
}

然后像这样使用它:

String testStr = "this is a test string";
String last1 = takeLast(testStr, 1); //Output: g
String last4 = takeLast(testStr, 4); //Output: ring

public char LastChar(String a){
    return a.charAt(a.length() - 1);
}

试试这个:

if (s.charAt(0) == s.charAt(s.length() - 1))

下面是一个使用String.charAt()的方法:

String str = "India";
System.out.println("last char = " + str.charAt(str.length() - 1));

结果输出是last char = a。