public char lastChar(String s) {
     if (s == "" || s == null)
        return ' ';
    char lc = s.charAt(s.length() - 1);
    return lc;
}

其他答案包含大量不必要的文本和代码。这里有两种方法来获取字符串的最后一个字符:

char

char lastChar = myString.charAt(myString.length() - 1);

字符串

String lastChar = myString.substring(myString.length() - 1);

下面是我用来获取字符串的最后n个字符的方法:

public static String takeLast(String value, int count) {
    if (value == null || value.trim().length() == 0) return "";
    if (count < 1) return "";

    if (value.length() > count) {
        return value.substring(value.length() - count);
    } else {
        return value;
    }
}

然后像这样使用它:

String testStr = "this is a test string";
String last1 = takeLast(testStr, 1); //Output: g
String last4 = takeLast(testStr, 4); //Output: ring

String aString = "This will return the letter t";
System.out.println(aString.charAt(aString.length() - 1));

输出应该是:

t

编码快乐!

public char LastChar(String a){
    return a.charAt(a.length() - 1);
}

 public char lastChar(String s) {
     if (s == "" || s == null)
        return ' ';
    char lc = s.charAt(s.length() - 1);
    return lc;
}