我需要增加一个datetime值的月份
next_month = datetime.datetime(mydate.year, mydate.month+1, 1)
当月份为12时，它变成13，并引发错误“month必须在1..12”。(我预计时间会增加)
我想使用timedelta，但它不带month参数。 有一个relativedelta python包，但我不想只为此安装它。 还有一个使用strtotime的解决方案。
time = strtotime(str(mydate));
next_month = date("Y-m-d", strtotime("+1 month", time));
我不想从datetime转换为str再转换为time，再转换为datetime;因此，它仍然是一个图书馆
有人有像使用timedelta一样好的简单的解决方案吗?
当前回答
这个怎么样?(不需要任何额外的库)
from datetime import date, timedelta
from calendar import monthrange
today = date.today()
month_later = date(today.year, today.month, monthrange(today.year, today.month)[1]) + timedelta(1)
其他回答
不使用日历的解决方案:
def add_month_year(date, years=0, months=0):
year, month = date.year + years, date.month + months + 1
dyear, month = divmod(month - 1, 12)
rdate = datetime.date(year + dyear, month + 1, 1) - datetime.timedelta(1)
return rdate.replace(day = min(rdate.day, date.day))
使用time对象的示例:
start_time = time.gmtime(time.time()) # start now
#increment one month
start_time = time.gmtime(time.mktime([start_time.tm_year, start_time.tm_mon+1, start_time.tm_mday, start_time.tm_hour, start_time.tm_min, start_time.tm_sec, 0, 0, 0]))
好的，通过一些调整和使用timedelta，我们开始:
from datetime import datetime, timedelta
def inc_date(origin_date):
day = origin_date.day
month = origin_date.month
year = origin_date.year
if origin_date.month == 12:
delta = datetime(year + 1, 1, day) - origin_date
else:
delta = datetime(year, month + 1, day) - origin_date
return origin_date + delta
final_date = inc_date(datetime.today())
print final_date.date()
与Dave Webb的解决方案的理想相似，但没有所有棘手的模运算:
import datetime, calendar
def increment_month(date):
# Go to first of this month, and add 32 days to get to the next month
next_month = date.replace(day=1) + datetime.timedelta(32)
# Get the day of month that corresponds
day = min(date.day, calendar.monthrange(next_month.year, next_month.month)[1])
return next_month.replace(day=day)
我的解决方案非常简单，不需要任何额外的模块:
def addmonth(date):
if date.day < 20:
date2 = date+timedelta(32)
else :
date2 = date+timedelta(25)
date2.replace(date2.year, date2.month, day)
return date2
