这为我工作len(list(df))。

像这样:

import pandas as pd
df = pd.DataFrame({"pear": [1,2,3], "apple": [2,3,4], "orange": [3,4,5]})

len(df.columns)
3

import pandas as pd
df = pd.DataFrame({"pear": [1,2,3], "apple": [2,3,4], "orange": [3,4,5]})


print(len(list(df.iterrows())))

给出行长度

3

[Program finished]

这为我工作len(list(df))。

选择:

df.shape[1]

(df。形状[0]是行数)

#use a regular expression to parse the column count
#https://docs.python.org/3/library/re.html

buffer = io.StringIO()
df.info(buf=buffer)
s = buffer.getvalue()
pat=re.search(r"total\s{1}[0-9]\s{1}column",s)
print(s)
phrase=pat.group(0)
value=re.findall(r'[0-9]+',phrase)[0]
print(int(value))