有没有一个聪明的方法让用户在隐藏和查看密码之间切换在一个android EditText? 许多基于PC的应用程序都允许用户这样做。


当前回答

使用复选框并相应地更改输入类型。

public void onCheckedChanged(CompoundButton buttonView, boolean isChecked) {
    int start,end;
    Log.i("inside checkbox chnge",""+isChecked);
    if(!isChecked){
        start=passWordEditText.getSelectionStart();
        end=passWordEditText.getSelectionEnd();
        passWordEditText.setTransformationMethod(new PasswordTransformationMethod());;
        passWordEditText.setSelection(start,end);
    }else{
        start=passWordEditText.getSelectionStart();
        end=passWordEditText.getSelectionEnd();
        passWordEditText.setTransformationMethod(null);
        passWordEditText.setSelection(start,end);
    }
}

其他回答

你可以使用下面的代码显示/隐藏密码:

XML代码:

<EditText
        android:id="@+id/etPassword"
        android:layout_width="wrap_content"
        android:layout_height="wrap_content"
        android:layout_marginLeft="21dp"
        android:layout_marginTop="14dp"
        android:ems="10"
        android:inputType="textPassword" >
        <requestFocus />
    </EditText>
    <CheckBox
        android:id="@+id/cbShowPwd"
        android:layout_width="wrap_content"
        android:layout_height="wrap_content"
        android:layout_alignLeft="@+id/etPassword"
        android:layout_below="@+id/etPassword"
        android:text="@string/show_pwd" />

JAVA代码:

EditText mEtPwd;
CheckBox mCbShowPwd;


mEtPwd = (EditText) findViewById(R.id.etPassword);
mCbShowPwd = (CheckBox) findViewById(R.id.cbShowPwd);

mCbShowPwd.setOnCheckedChangeListener(new CompoundButton.OnCheckedChangeListener() {
    @Override
    public void onCheckedChanged(CompoundButton buttonView, boolean isChecked) {
        // checkbox status is changed from uncheck to checked.
        if (!isChecked) {
            // show password
            mEtPwd.setTransformationMethod(PasswordTransformationMethod.getInstance());
        } else {
            // hide password
            mEtPwd.setTransformationMethod(HideReturnsTransformationMethod.getInstance());
        }
    }
});

这是我的解决方案没有使用TextInputEditText和转换方法。

XML

<LinearLayout
        android:layout_width="match_parent"
        android:layout_height="wrap_content"
        android:orientation="vertical">

        <TextView
            style="@style/FormLabel"
            android:layout_width="match_parent"
            android:layout_height="wrap_content"
            android:text="@string/username" />

        <EditText
            android:id="@+id/loginUsername"
            style="@style/EditTextStyle"
            android:layout_width="match_parent"
            android:layout_height="wrap_content"
            android:drawableLeft="@drawable/ic_person_outline_black_24dp"
            android:drawableStart="@drawable/ic_person_outline_black_24dp"
            android:inputType="textEmailAddress"
            android:textColor="@color/black" />

        <TextView
            style="@style/FormLabel"
            android:layout_width="match_parent"
            android:layout_height="wrap_content"
            android:layout_marginTop="20dp"
            android:text="@string/password" />

        <EditText
            android:id="@+id/loginPassword"
            style="@style/EditTextStyle"
            android:layout_width="match_parent"
            android:layout_height="wrap_content"
            android:drawableEnd="@drawable/ic_visibility_off_black_24dp"
            android:drawableLeft="@drawable/ic_lock_outline_black_24dp"
            android:drawableRight="@drawable/ic_visibility_off_black_24dp"
            android:drawableStart="@drawable/ic_lock_outline_black_24dp"
            android:inputType="textPassword"
            android:textColor="@color/black" />
    </LinearLayout>

Java代码

boolean VISIBLE_PASSWORD = false;  //declare as global variable befor onCreate() 
loginPassword = (EditText)findViewById(R.id.loginPassword);
loginPassword.setOnTouchListener(new View.OnTouchListener() {
        public boolean onTouch(View v, MotionEvent event) {
            final int DRAWABLE_LEFT = 0;
            final int DRAWABLE_TOP = 1;
            final int DRAWABLE_RIGHT = 2;
            final int DRAWABLE_BOTTOM = 3;

            if (event.getAction() == MotionEvent.ACTION_UP) {
                if (event.getRawX() >= (loginPassword.getRight() - loginPassword.getCompoundDrawables()[DRAWABLE_RIGHT].getBounds().width())) {
                    // your action here
                    //Helper.toast(LoginActivity.this, "Toggle visibility");
                    if (VISIBLE_PASSWORD) {
                        VISIBLE_PASSWORD = false;
                        loginPassword.setInputType(InputType.TYPE_CLASS_TEXT | InputType.TYPE_TEXT_VARIATION_PASSWORD);
                        loginPassword.setCompoundDrawablesWithIntrinsicBounds(R.drawable.ic_lock_outline_black_24dp, 0, R.drawable.ic_visibility_off_black_24dp, 0);
                    } else {
                        VISIBLE_PASSWORD = true;
                        loginPassword.setInputType(InputType.TYPE_CLASS_TEXT);
                        loginPassword.setCompoundDrawablesWithIntrinsicBounds(R.drawable.ic_lock_outline_black_24dp, 0, R.drawable.ic_visibility_black_24dp, 0);
                    }
                    return false;
                }
            }
            return false;
        }
    });

我可以添加ShowPassword / HidePassword代码,只需几行,在一个块中独立:

protected void onCreate(Bundle savedInstanceState) {
    ...
    etPassword = (EditText)findViewById(R.id.password);
    etPassword.setTransformationMethod(new PasswordTransformationMethod()); // Hide password initially

    checkBoxShowPwd = (CheckBox)findViewById(R.id.checkBoxShowPwd);
    checkBoxShowPwd.setText(getString(R.string.label_show_password)); // Hide initially, but prompting "Show Password"
    checkBoxShowPwd.setOnCheckedChangeListener( new CompoundButton.OnCheckedChangeListener() {
        public void onCheckedChanged(CompoundButton arg0, boolean isChecked) {
            if (isChecked) {
                etPassword.setTransformationMethod(null); // Show password when box checked
                checkBoxShowPwd.setText(getString(R.string.label_hide_password)); // Prompting "Hide Password"
            } else {
                etPassword.setTransformationMethod(new PasswordTransformationMethod()); // Hide password when box not checked
                checkBoxShowPwd.setText(getString(R.string.label_show_password)); // Prompting "Show Password"
            }
        }
    } );
    ...

1 -创建一个选择器文件"show_password_selector.xml"

<selector xmlns:android="http://schemas.android.com/apk/res/android">
    <item android:drawable="@drawable/pwd_hide"
          android:state_selected="true"/>
    <item android:drawable="@drawable/pwd_show"
          android:state_selected="false" />
 </selector>

2 -将“show_password_selector”文件放入imageview。

<ImageView
    android:id="@+id/iv_pwd"
    android:layout_width="@dimen/_35sdp"
    android:layout_height="@dimen/_25sdp"
    android:layout_alignParentRight="true"
    android:layout_centerVertical="true"
    android:layout_marginRight="@dimen/_15sdp"
    android:src="@drawable/show_password_selector" />

3 -把下面的代码在java文件。

iv_new_pwd.setOnClickListener(new View.OnClickListener() {
    @Override
    public void onClick(View v) {
        if (iv_new_pwd.isSelected()) {
            iv_new_pwd.setSelected(false);
            Log.d("mytag", "in case 1");
            edt_new_pwd.setInputType(InputType.TYPE_CLASS_TEXT);
        } else {
            Log.d("mytag", "in case 1");
            iv_new_pwd.setSelected(true);
            edt_new_pwd.setInputType(InputType.TYPE_CLASS_TEXT | InputType.TYPE_TEXT_VARIATION_PASSWORD);
        }
    }
});

我的Kotlin扩展。编写一次,随处使用

fun EditText.tooglePassWord() {
this.tag = !((this.tag ?: false) as Boolean)
this.inputType = if (this.tag as Boolean)
    InputType.TYPE_TEXT_VARIATION_PASSWORD
else
    (InputType.TYPE_CLASS_TEXT or InputType.TYPE_TEXT_VARIATION_PASSWORD)

this.setSelection(this.length()) }

您可以将此方法保存在任何文件中,并在任何地方使用它 像这样使用它

ivShowPassword.click { etPassword.tooglePassWord() }

其中ivShowPassword是点击imageview(眼睛)和etPassword是编辑