有没有一个聪明的方法让用户在隐藏和查看密码之间切换在一个android EditText? 许多基于PC的应用程序都允许用户这样做。


当前回答

尝试https://github.com/maksim88/PasswordEditText项目在github。 你甚至不需要改变你的Java代码使用它。只改变

EditText

标签

com.maksim88.passwordedittext.PasswordEditText

在XML文件中。

其他回答

显示:

editText.setInputType(InputType.TYPE_TEXT_VARIATION_VISIBLE_PASSWORD);

隐藏:

editText.setInputType(InputType.TYPE_CLASS_TEXT | InputType.TYPE_TEXT_VARIATION_PASSWORD);

在这些之后,光标被重置,所以:

editText.setSelection(editText.length());

添加这个方法:

fun EditText.revertTransformation() {
    transformationMethod = when(transformationMethod) {
        is PasswordTransformationMethod -> SingleLineTransformationMethod.getInstance()
        else -> PasswordTransformationMethod.getInstance()
    }
}

调用它将在输入类型状态之间切换(您可以将Single-Line转换更改为您喜欢的)。使用的例子:

editText.revertTransformation()

这是我的解决方案没有使用TextInputEditText和转换方法。

XML

<LinearLayout
        android:layout_width="match_parent"
        android:layout_height="wrap_content"
        android:orientation="vertical">

        <TextView
            style="@style/FormLabel"
            android:layout_width="match_parent"
            android:layout_height="wrap_content"
            android:text="@string/username" />

        <EditText
            android:id="@+id/loginUsername"
            style="@style/EditTextStyle"
            android:layout_width="match_parent"
            android:layout_height="wrap_content"
            android:drawableLeft="@drawable/ic_person_outline_black_24dp"
            android:drawableStart="@drawable/ic_person_outline_black_24dp"
            android:inputType="textEmailAddress"
            android:textColor="@color/black" />

        <TextView
            style="@style/FormLabel"
            android:layout_width="match_parent"
            android:layout_height="wrap_content"
            android:layout_marginTop="20dp"
            android:text="@string/password" />

        <EditText
            android:id="@+id/loginPassword"
            style="@style/EditTextStyle"
            android:layout_width="match_parent"
            android:layout_height="wrap_content"
            android:drawableEnd="@drawable/ic_visibility_off_black_24dp"
            android:drawableLeft="@drawable/ic_lock_outline_black_24dp"
            android:drawableRight="@drawable/ic_visibility_off_black_24dp"
            android:drawableStart="@drawable/ic_lock_outline_black_24dp"
            android:inputType="textPassword"
            android:textColor="@color/black" />
    </LinearLayout>

Java代码

boolean VISIBLE_PASSWORD = false;  //declare as global variable befor onCreate() 
loginPassword = (EditText)findViewById(R.id.loginPassword);
loginPassword.setOnTouchListener(new View.OnTouchListener() {
        public boolean onTouch(View v, MotionEvent event) {
            final int DRAWABLE_LEFT = 0;
            final int DRAWABLE_TOP = 1;
            final int DRAWABLE_RIGHT = 2;
            final int DRAWABLE_BOTTOM = 3;

            if (event.getAction() == MotionEvent.ACTION_UP) {
                if (event.getRawX() >= (loginPassword.getRight() - loginPassword.getCompoundDrawables()[DRAWABLE_RIGHT].getBounds().width())) {
                    // your action here
                    //Helper.toast(LoginActivity.this, "Toggle visibility");
                    if (VISIBLE_PASSWORD) {
                        VISIBLE_PASSWORD = false;
                        loginPassword.setInputType(InputType.TYPE_CLASS_TEXT | InputType.TYPE_TEXT_VARIATION_PASSWORD);
                        loginPassword.setCompoundDrawablesWithIntrinsicBounds(R.drawable.ic_lock_outline_black_24dp, 0, R.drawable.ic_visibility_off_black_24dp, 0);
                    } else {
                        VISIBLE_PASSWORD = true;
                        loginPassword.setInputType(InputType.TYPE_CLASS_TEXT);
                        loginPassword.setCompoundDrawablesWithIntrinsicBounds(R.drawable.ic_lock_outline_black_24dp, 0, R.drawable.ic_visibility_black_24dp, 0);
                    }
                    return false;
                }
            }
            return false;
        }
    });

您必须询问当前文本是否已经显示了圆点,函数PasswordTransformationMethod.getInstance()允许您这样做。

这是我在kotlin中的函数:

        fun hideAndShowPassword(editText: EditText, indicator: ImageView) {

        if (editText.transformationMethod == PasswordTransformationMethod.getInstance()) {
            editText.transformationMethod = HideReturnsTransformationMethod.getInstance()
            indicator.setImageDrawable(
                ContextCompat.getDrawable(
                    editText.context,
                    R.drawable.eye
                )
            )
            indicator.imageTintList =
                ContextCompat.getColorStateList(editText.context, R.color.colorTintIcons)
        } else {
            editText.transformationMethod = PasswordTransformationMethod.getInstance()
            indicator.setImageDrawable(
                ContextCompat.getDrawable(
                    editText.context,
                    R.drawable.eye_off
                )
            )
            indicator.imageTintList =
                ContextCompat.getColorStateList(editText.context, R.color.colorTintIcons)
        }

        editText.setSelection(editText.text.length)
    }

只需在Xml文件中创建一个复选框

然后简单的用Java代码编写这个函数

checkbox = findViewById(R.id.checkbox);
        checkbox.setOnCheckedChangeListener(new CompoundButton.OnCheckedChangeListener(){
            @Override
            public void onCheckedChanged(CompoundButton buttonView, boolean isChecked){

                if (isChecked) {
                    password.setTransformationMethod(null);
                }
                else{
                    password.setTransformationMethod(new PasswordTransformationMethod());
                }
            }

        });