非常简单的形式:

private fun updatePasswordVisibility(editText: AppCompatEditText) {
        if (editText.transformationMethod is PasswordTransformationMethod) {
            editText.transformationMethod = null
        } else {
            editText.transformationMethod = PasswordTransformationMethod()
        }
        editText.setSelection(editText.length())
    }

希望能有所帮助。

这是我的解决方案没有使用TextInputEditText和转换方法。

XML

<LinearLayout
        android:layout_width="match_parent"
        android:layout_height="wrap_content"
        android:orientation="vertical">

        <TextView
            style="@style/FormLabel"
            android:layout_width="match_parent"
            android:layout_height="wrap_content"
            android:text="@string/username" />

        <EditText
            android:id="@+id/loginUsername"
            style="@style/EditTextStyle"
            android:layout_width="match_parent"
            android:layout_height="wrap_content"
            android:drawableLeft="@drawable/ic_person_outline_black_24dp"
            android:drawableStart="@drawable/ic_person_outline_black_24dp"
            android:inputType="textEmailAddress"
            android:textColor="@color/black" />

        <TextView
            style="@style/FormLabel"
            android:layout_width="match_parent"
            android:layout_height="wrap_content"
            android:layout_marginTop="20dp"
            android:text="@string/password" />

        <EditText
            android:id="@+id/loginPassword"
            style="@style/EditTextStyle"
            android:layout_width="match_parent"
            android:layout_height="wrap_content"
            android:drawableEnd="@drawable/ic_visibility_off_black_24dp"
            android:drawableLeft="@drawable/ic_lock_outline_black_24dp"
            android:drawableRight="@drawable/ic_visibility_off_black_24dp"
            android:drawableStart="@drawable/ic_lock_outline_black_24dp"
            android:inputType="textPassword"
            android:textColor="@color/black" />
    </LinearLayout>

Java代码

boolean VISIBLE_PASSWORD = false;  //declare as global variable befor onCreate() 
loginPassword = (EditText)findViewById(R.id.loginPassword);
loginPassword.setOnTouchListener(new View.OnTouchListener() {
        public boolean onTouch(View v, MotionEvent event) {
            final int DRAWABLE_LEFT = 0;
            final int DRAWABLE_TOP = 1;
            final int DRAWABLE_RIGHT = 2;
            final int DRAWABLE_BOTTOM = 3;

            if (event.getAction() == MotionEvent.ACTION_UP) {
                if (event.getRawX() >= (loginPassword.getRight() - loginPassword.getCompoundDrawables()[DRAWABLE_RIGHT].getBounds().width())) {
                    // your action here
                    //Helper.toast(LoginActivity.this, "Toggle visibility");
                    if (VISIBLE_PASSWORD) {
                        VISIBLE_PASSWORD = false;
                        loginPassword.setInputType(InputType.TYPE_CLASS_TEXT | InputType.TYPE_TEXT_VARIATION_PASSWORD);
                        loginPassword.setCompoundDrawablesWithIntrinsicBounds(R.drawable.ic_lock_outline_black_24dp, 0, R.drawable.ic_visibility_off_black_24dp, 0);
                    } else {
                        VISIBLE_PASSWORD = true;
                        loginPassword.setInputType(InputType.TYPE_CLASS_TEXT);
                        loginPassword.setCompoundDrawablesWithIntrinsicBounds(R.drawable.ic_lock_outline_black_24dp, 0, R.drawable.ic_visibility_black_24dp, 0);
                    }
                    return false;
                }
            }
            return false;
        }
    });

你可以使用app:passwordToggleEnabled="true"

下面是一个例子

<android.support.design.widget.TextInputLayout
        android:id="@+id/password"
        android:layout_width="match_parent"
        android:layout_height="wrap_content"
        app:passwordToggleEnabled="true"
        android:textColorHint="@color/colorhint"
        android:textColor="@color/colortext">

非常简单的形式:

private fun updatePasswordVisibility(editText: AppCompatEditText) {
        if (editText.transformationMethod is PasswordTransformationMethod) {
            editText.transformationMethod = null
        } else {
            editText.transformationMethod = PasswordTransformationMethod()
        }
        editText.setSelection(editText.length())
    }

希望能有所帮助。

我使用了一个OnClickListener()，它与我想用作toogle的按钮相关联。

private EditText email_et, contraseña_et;
protected void onCreate(Bundle savedInstanceState) {
....
contraseña_et = (EditText) findViewById(R.id.contraseña_et);
....
vercontra_btn.setOnClickListener(new View.OnClickListener() {
        @Override
        public void onClick(View v) {
            int inputType = contraseña_et.getInputType();
            if (inputType == 129){
                contraseña_et.setInputType(1);
            } else {
                contraseña_et.setInputType(129);
            }
            contraseña_et.setSelection(contraseña_et.getText().length());
        }
    });

阅读文档，int值似乎是不同的，所以我调试找到正确的值，它的工作棒极了，这是一个更容易一点的方式。

[顺便说一下，Contraseña是西班牙语的密码]

显示:

editText.setInputType(InputType.TYPE_TEXT_VARIATION_VISIBLE_PASSWORD);

隐藏:

editText.setInputType(InputType.TYPE_CLASS_TEXT | InputType.TYPE_TEXT_VARIATION_PASSWORD);

在这些之后，光标被重置，所以:

editText.setSelection(editText.length());