是否可以使用PowerShell创建zip存档?


当前回答

下面是sonjz回答的一个稍微改进的版本,它增加了一个覆盖选项。

function Zip-Files(
        [Parameter(Position=0, Mandatory=$true, ValueFromPipeline=$false)]
        [string] $zipfilename,
        [Parameter(Position=1, Mandatory=$true, ValueFromPipeline=$false)]
        [string] $sourcedir,
        [Parameter(Position=2, Mandatory=$false, ValueFromPipeline=$false)]
        [bool] $overwrite)

{
   Add-Type -Assembly System.IO.Compression.FileSystem
   $compressionLevel = [System.IO.Compression.CompressionLevel]::Optimal

    if ($overwrite -eq $true )
    {
        if (Test-Path $zipfilename)
        {
            Remove-Item $zipfilename
        }
    }

    [System.IO.Compression.ZipFile]::CreateFromDirectory($sourcedir, $zipfilename, $compressionLevel, $false)
}

其他回答

一个纯PowerShell的替代方案,与PowerShell 3和。net 4.5(如果你可以使用它):

function ZipFiles( $zipfilename, $sourcedir )
{
   Add-Type -Assembly System.IO.Compression.FileSystem
   $compressionLevel = [System.IO.Compression.CompressionLevel]::Optimal
   [System.IO.Compression.ZipFile]::CreateFromDirectory($sourcedir,
        $zipfilename, $compressionLevel, $false)
}

只需传入您想要创建的zip归档文件的完整路径,以及包含您想要压缩的文件的目录的完整路径。

旧线程,但仍然,我到了这里:)

这不是最初问题的答案,但也许有人会发现如何用PS创建ZipArchive对象是有用的。

# Example, if you have like I have a $myByteArray byte[] with the compressed data:
Add-Type -AssemblyName System.IO.Compression.FileSystem

# Fixed length stream:
$strm = New-Object -TypeName System.IO.MemoryStream -ArgumentList @(, $myByteArray);

# Create ZipArchive object
$arch = [System.IO.Compression.ZipArchive]::new($strm);

# List entries
$arch.Entries

下面是PowerShell v5的原生解决方案,使用cmdlet压缩-归档使用PowerShell创建Zip文件。

请参见微软文档 Compress-Archive。

示例1:

Compress-Archive `
    -LiteralPath C:\Reference\Draftdoc.docx, C:\Reference\Images\diagram2.vsd `
    -CompressionLevel Optimal `
    -DestinationPath C:\Archives\Draft.Zip

示例2:

Compress-Archive `
    -Path C:\Reference\* `
    -CompressionLevel Fastest `
    -DestinationPath C:\Archives\Draft

示例3:

Write-Output $files | Compress-Archive -DestinationPath $outzipfile

System.IO.Packaging.ZipPackage呢?

它需要。net 3.0或更高版本。

#Load some assemblys. (No line break!)
[System.Reflection.Assembly]::Load("WindowsBase, Version=3.0.0.0, Culture=neutral, PublicKeyToken=31bf3856ad364e35")

#Create a zip file named "MyZipFile.zip". (No line break!)
$ZipPackage=[System.IO.Packaging.ZipPackage]::Open("C:\MyZipFile.zip",
   [System.IO.FileMode]"OpenOrCreate", [System.IO.FileAccess]"ReadWrite")

#The files I want to add to my archive:
$files = @("/Penguins.jpg", "/Lighthouse.jpg")

#For each file you want to add, we must extract the bytes
#and add them to a part of the zip file.
ForEach ($file In $files)
{
   $partName=New-Object System.Uri($file, [System.UriKind]"Relative")
   #Create each part. (No line break!)
   $part=$ZipPackage.CreatePart($partName, "",
      [System.IO.Packaging.CompressionOption]"Maximum")
   $bytes=[System.IO.File]::ReadAllBytes($file)
   $stream=$part.GetStream()
   $stream.Write($bytes, 0, $bytes.Length)
   $stream.Close()
}

#Close the package when we're done.
$ZipPackage.Close()

通过安德斯·赫塞尔博姆

这里有一个完整的命令行示例,可以从cmd.exe或ssh或您想要的任何地方启动!

powershell.exe -nologo -noprofile -command "&{ Add-Type -A 'System.IO.Compression.FileSystem' [System.IO.Compression.ZipFile]::CreateFromDirectory('c:/path/to/source/folder/', 'c:/path/to/output/file.zip');}"

问候