编辑二——这段代码是一个非常丑陋的旧代码。你不会想要的。

这将使用system . io . package . zippackage将。\in文件的内容压缩为。\out.zip

$zipArchive = $pwd.path + "\out.zip"
[System.Reflection.Assembly]::Load("WindowsBase,Version=3.0.0.0, Culture=neutral, PublicKeyToken=31bf3856ad364e35")
$ZipPackage=[System.IO.Packaging.ZipPackage]::Open($zipArchive,
  [System.IO.FileMode]"OpenOrCreate", [System.IO.FileAccess]"ReadWrite")
$in = gci .\in | select -expand fullName
[array]$files = $in -replace "C:","" -replace "\\","/"
ForEach ($file In $files)
{
   $partName=New-Object System.Uri($file, [System.UriKind]"Relative")
   $part=$ZipPackage.CreatePart($partName, "application/zip",
      [System.IO.Packaging.CompressionOption]"Maximum")
   $bytes=[System.IO.File]::ReadAllBytes($file)
   $stream=$part.GetStream()
   $stream.Write($bytes, 0, $bytes.Length)
   $stream.Close()
}
$ZipPackage.Close()

编辑:不可靠的大文件，可能>10mb, YMMV。与appdomain证据和隔离存储有关。更友好的。net 4.5方法在PS v3上工作得很好，但在我的情况下需要更多的内存。要从PS v2使用. net 4，配置文件需要一个不受支持的调整。

如果您前往CodePlex并获取PowerShell社区扩展，您可以使用他们的write-zip cmdlet。

自

CodePlex处于只读模式，准备关闭

你可以去PowerShell画廊。

如果你安装了WinRAR:

function ZipUsingRar([String] $directory, [String] $zipFileName)
{
  Write-Output "Performing operation ""Zip File"" on Target ""Item: $directory Destination:"
  Write-Output ($zipFileName + """")
  $pathToWinRar = "c:\Program Files\WinRAR\WinRar.exe";
  [Array]$arguments = "a", "-afzip", "-df", "-ep1", "$zipFileName", "$directory";
  & $pathToWinRar $arguments;
}

参数的含义:afzip创建zip归档，df删除文件，ep1不创建归档内的完整目录路径

这很晦涩，但很有效。7za.exe是7zip的独立版本，可通过安装包获得。

# get files to be send
$logFiles = Get-ChildItem C:\Logging\*.* -Include *.log | where {$_.Name -match $yesterday} 

foreach ($logFile in $logFiles)
{
    Write-Host ("Processing " + $logFile.FullName)

    # compress file
    & ./7za.exe a -mmt=off ($logFile.FullName + ".7z") $logFile.FullName

}

安装7zip(或下载命令行版本)并使用PowerShell方法:

function create-7zip([String] $aDirectory, [String] $aZipfile){
    [string]$pathToZipExe = "$($Env:ProgramFiles)\7-Zip\7z.exe";
    [Array]$arguments = "a", "-tzip", "$aZipfile", "$aDirectory", "-r";
    & $pathToZipExe $arguments;
}

你可以这样调用它:

create-7zip "c:\temp\myFolder" "c:\temp\myFolder.zip"

System.IO.Packaging.ZipPackage呢?

它需要。net 3.0或更高版本。

#Load some assemblys. (No line break!)
[System.Reflection.Assembly]::Load("WindowsBase, Version=3.0.0.0, Culture=neutral, PublicKeyToken=31bf3856ad364e35")

#Create a zip file named "MyZipFile.zip". (No line break!)
$ZipPackage=[System.IO.Packaging.ZipPackage]::Open("C:\MyZipFile.zip",
   [System.IO.FileMode]"OpenOrCreate", [System.IO.FileAccess]"ReadWrite")

#The files I want to add to my archive:
$files = @("/Penguins.jpg", "/Lighthouse.jpg")

#For each file you want to add, we must extract the bytes
#and add them to a part of the zip file.
ForEach ($file In $files)
{
   $partName=New-Object System.Uri($file, [System.UriKind]"Relative")
   #Create each part. (No line break!)
   $part=$ZipPackage.CreatePart($partName, "",
      [System.IO.Packaging.CompressionOption]"Maximum")
   $bytes=[System.IO.File]::ReadAllBytes($file)
   $stream=$part.GetStream()
   $stream.Write($bytes, 0, $bytes.Length)
   $stream.Close()
}

#Close the package when we're done.
$ZipPackage.Close()

通过安德斯·赫塞尔博姆