我如何从十六进制字符串格式创建一个UIColor,如#00FF00?


当前回答

大多数发布的解决方案使用了Scanner,但至少在现代Swift中你并不真正需要它。相反,你可以简单地使用UInt init和基数16,然后使用基本的二进制操作来获得UIColor组件:

func stringToColor(color: String) -> UIColor {
    guard let i = UInt(color, radix: 16) else {
        return UIColor.white
    }
    return UIColor(
        red: CGFloat((i & 0xFF0000) >> 16) / 255.0,
        green: CGFloat((i & 0xFF00) >> 8) / 255.0,
        blue: CGFloat(i & 0xFF) / 255.0,
        alpha: 1.0
    )
}

这个解决方案期望输入像“FF00FF”,你可能需要删除前面的哈希符号(#),如果你的字符串中有一个。

其他回答

您可以使用各种在线工具将HEX字符串转换为实际的UIColor。查看uicolor.org或UI颜色选择器。输出将被转换为Objective-C代码,如下所示:

[UIColor colorWithRed:0.93 green:0.80 blue:0.80 alpha:1.0];

可以嵌入到应用程序中。希望这能有所帮助!

Xamarin的。iOS你可以使用下面的宏来代替宏:

public UIColor UIColorFromHexValue(int value, float alpha = 1f) =>
    UIColor.FromRGBA(
        ((value & 0xFF0000) >> 16) / 255.0f,
        ((value & 0x00FF00) >> 16) / 255.0f,
        ((value & 0x0000FF) >> 16) / 255.0f,
        alpha);

用法类似:

label.TextColor = UIColorFromHexValue(0xBC1128);

有一个很好的帖子是关于如何解决OP的问题,从十六进制字符串中提取UIColor。下面给出的解决方案与其他解决方案不同,因为它支持字符串值,可能包括'0x'或'#'前缀的十六进制字符串表示…(请参阅使用)

这是主要的部分…

- (UIColor *)getUIColorObjectFromHexString:(NSString *)hexStr alpha:(CGFloat)alpha
{
  // Convert hex string to an integer
  unsigned int hexint = [self intFromHexString:hexStr];
 
  // Create a color object, specifying alpha as well
  UIColor *color =
    [UIColor colorWithRed:((CGFloat) ((hexint & 0xFF0000) >> 16))/255
    green:((CGFloat) ((hexint & 0xFF00) >> 8))/255
    blue:((CGFloat) (hexint & 0xFF))/255
    alpha:alpha];
 
  return color;
}

助手方法……

- (unsigned int)intFromHexString:(NSString *)hexStr
{
  unsigned int hexInt = 0;
 
  // Create scanner
  NSScanner *scanner = [NSScanner scannerWithString:hexStr];
 
  // Tell scanner to skip the # character
  [scanner setCharactersToBeSkipped:[NSCharacterSet characterSetWithCharactersInString:@"#"]];
 
  // Scan hex value
  [scanner scanHexInt:&hexInt];
 
  return hexInt;
}

用法:

NSString *hexStr1 = @"123ABC";
NSString *hexStr2 = @"#123ABC";
NSString *hexStr3 = @"0x123ABC";

UIColor *color1 = [self getUIColorObjectFromHexString:hexStr1 alpha:.9];
NSLog(@"UIColor: %@", color1);
 
UIColor *color2 = [self getUIColorObjectFromHexString:hexStr2 alpha:.9];
NSLog(@"UIColor: %@", color2);
 
UIColor *color3 = [self getUIColorObjectFromHexString:hexStr3 alpha:.9];
NSLog(@"UIColor: %@", color3);

完整的参考文章

Swift 2 +

我已经将这个解决方案移植到Swift 2.2。注意,我已经将alpha参数更改为使用默认设置为1.0。我还根据Swift 2.2中的NSScanner类的要求将int类型更新为UInt32。

func colorWithHexString(hexString: String, alpha:CGFloat = 1.0) -> UIColor {
    
    // Convert hex string to an integer
    let hexint = Int(self.intFromHexString(hexString))
    let red = CGFloat((hexint & 0xff0000) >> 16) / 255.0
    let green = CGFloat((hexint & 0xff00) >> 8) / 255.0
    let blue = CGFloat((hexint & 0xff) >> 0) / 255.0 
    
    // Create color object, specifying alpha as well
    let color = UIColor(red: red, green: green, blue: blue, alpha: alpha)
    return color
}

func intFromHexString(hexStr: String) -> UInt32 {
    var hexInt: UInt32 = 0
    // Create scanner
    let scanner: NSScanner = NSScanner(string: hexStr)
    // Tell scanner to skip the # character
    scanner.charactersToBeSkipped = NSCharacterSet(charactersInString: "#")
    // Scan hex value
    scanner.scanHexInt(&hexInt)
    return hexInt
}

斯威夫特 4+

采用与swift 4相同的变化逻辑,

func colorWithHexString(hexString: String, alpha:CGFloat = 1.0) -> UIColor {
    
    // Convert hex string to an integer
    let hexint = Int(self.intFromHexString(hexStr: hexString))
    let red = CGFloat((hexint & 0xff0000) >> 16) / 255.0
    let green = CGFloat((hexint & 0xff00) >> 8) / 255.0
    let blue = CGFloat((hexint & 0xff) >> 0) / 255.0
    
    // Create color object, specifying alpha as well
    let color = UIColor(red: red, green: green, blue: blue, alpha: alpha)
    return color
}

func intFromHexString(hexStr: String) -> UInt32 {
    var hexInt: UInt32 = 0
    // Create scanner
    let scanner: Scanner = Scanner(string: hexStr)
    // Tell scanner to skip the # character
    scanner.charactersToBeSkipped = CharacterSet(charactersIn: "#")
    // Scan hex value
    scanner.scanHexInt32(&hexInt)
    return hexInt
}

Swift 5 (iOS 13)+

下面显示了在SDK弃用scanHexInt32的情况下工作的更新。我将代码封装到Swift playground文件中。

//: A UIKit based Playground for presenting user interface
  
import UIKit
import PlaygroundSupport

class MyViewController : UIViewController {
    override func loadView() {
        let view = UIView()
        view.backgroundColor = .white

        let label = UILabel()
        label.frame = CGRect(x: 150, y: 200, width: 200, height: 20)
        label.text = "Hello World!"
        label.textColor = colorWithHexString(hexString: "22F728")
        
        view.addSubview(label)
        self.view = view
    }
    
    func colorWithHexString(hexString: String, alpha:CGFloat = 1.0) -> UIColor {

        // Convert hex string to an integer
        let hexint = Int(self.intFromHexString(hexStr: hexString))
        let red = CGFloat((hexint & 0xff0000) >> 16) / 255.0
        let green = CGFloat((hexint & 0xff00) >> 8) / 255.0
        let blue = CGFloat((hexint & 0xff) >> 0) / 255.0

        // Create color object, specifying alpha as well
        let color = UIColor(red: red, green: green, blue: blue, alpha: alpha)
        return color
    }

    func intFromHexString(hexStr: String) -> UInt32 {
        var hexInt: UInt32 = 0
        // Create scanner
        let scanner: Scanner = Scanner(string: hexStr)
        // Tell scanner to skip the # character
        scanner.charactersToBeSkipped = CharacterSet(charactersIn: "#")
        // Scan hex value
        hexInt = UInt32(bitPattern: scanner.scanInt32(representation: .hexadecimal) ?? 0)
        return hexInt
    }
}
// Present the view controller in the Live View window
PlaygroundPage.current.liveView = MyViewController()

彩色十六进制参考 HTML颜色名称和代码 十六进制颜色编码

使用任何转换器网站将十六进制颜色转换为RGB值(如果你谷歌“十六进制到RGB”,你会看到一吨)。例如,这个:http://www.rgbtohex.net/hextorgb/

然后将颜色属性更改为UIColor。例子:

self.profilePicture.layer.borderColor = [UIColor colorWithRed:0 green:167 blue:142 alpha:1.0].CGColor;

十六进制颜色值是:00a78e转换为RGB: R: 0 G: 167 B: 142

如果你给出的RGB值不在0到1.0之间,你必须将它们除以255。例子:

self.profilePicture.layer.borderColor = [UIColor colorWithRed:83.00/255.0 green:123.00/255.0 blue:53.00/255.0 alpha:1.0].CGColor; 

我最终为UIColor创建了一个类别,我可以在我的其他项目中重用,并添加了这个函数:

+ (UIColor *)colorFromHex:(unsigned long)hex
{
    return [UIColor colorWithRed:((float)((hex & 0xFF0000) >> 16))/255.0
                           green:((float)((hex & 0xFF00) >> 8))/255.0
                            blue:((float)(hex & 0xFF))/255.0
                           alpha:1.0];
}

用法是这样的:

UIColor *customRedColor = [UIColor colorFromHex:0x990000];

这比传递字符串并将其转换为数字然后移位位要快得多。

你也可以从你的.pch文件中导入类别,这样你就可以很容易地在你的应用程序中到处使用colorFromHex,就像它内置到UIColor中一样:

#ifdef __OBJC__
    #import <UIKit/UIKit.h>
    #import <Foundation/Foundation.h>
    // Your other stuff here...
    #import "UIColor+HexColor.h"
#endif