我需要从字符串的末尾删除空格。我该怎么做呢? 示例:如果字符串是“Hello”,它必须变成“Hello”
当前回答
给你…
- (NSString *)removeEndSpaceFrom:(NSString *)strtoremove{
NSUInteger location = 0;
unichar charBuffer[[strtoremove length]];
[strtoremove getCharacters:charBuffer];
int i = 0;
for(i = [strtoremove length]; i >0; i--) {
NSCharacterSet* charSet = [NSCharacterSet whitespaceCharacterSet];
if(![charSet characterIsMember:charBuffer[i - 1]]) {
break;
}
}
return [strtoremove substringWithRange:NSMakeRange(location, i - location)];
}
现在就叫它。假设你有一个字符串,它前面有空格,后面也有空格,你只想去掉末尾的空格,你可以这样调用它:
NSString *oneTwoThree = @" TestString ";
NSString *resultString;
resultString = [self removeEndSpaceFrom:oneTwoThree];
resultString的结尾将没有空格。
其他回答
let string = "测试修剪过的字符串"
对于删除空白和新行使用以下代码:-
let str_trim = yourString。trimmingCharacters (.whitespacesAndNewlines):
对于仅从字符串中删除空格使用以下代码:-
let str_trim = yourString。trimmingCharacters (.whitespaces):
从这里的答案来看:https://stackoverflow.com/a/5691567/251012
- (NSString *)stringByTrimmingTrailingCharactersInSet:(NSCharacterSet *)characterSet {
NSRange rangeOfLastWantedCharacter = [self rangeOfCharacterFromSet:[characterSet invertedSet]
options:NSBackwardsSearch];
if (rangeOfLastWantedCharacter.location == NSNotFound) {
return @"";
}
return [self substringToIndex:rangeOfLastWantedCharacter.location+1]; // non-inclusive
}
NSString *trimmedString = [string stringByTrimmingCharactersInSet:
[NSCharacterSet whitespaceAndNewlineCharacterSet]];
//for remove whitespace and new line character
NSString *trimmedString = [string stringByTrimmingCharactersInSet:
[NSCharacterSet punctuationCharacterSet]];
//for remove characters in punctuation category
还有许多其他字符集。根据你的要求自己检查一下。
我想出了这个函数,它的行为基本类似于Alex的答案:
-(NSString*)trimLastSpace:(NSString*)str{
int i = str.length - 1;
for (; i >= 0 && [str characterAtIndex:i] == ' '; i--);
return [str substringToIndex:i + 1];
}
whitespaceCharacterSet除了空格本身还包括制表符,在我的情况下不能出现。所以我想一个简单的比较就足够了。
在斯威夫特
从字符串的两侧修剪空格和换行:
var url: String = "\n http://example.com/xyz.mp4 "
var trimmedUrl: String = url.stringByTrimmingCharactersInSet(NSCharacterSet.whitespaceAndNewlineCharacterSet())