你遇到过的源代码中最好的注释是什么?
当前回答
//The following 1056 lines of code in this next method
//is a line by line port from VB.NET to C#.
//I ported this code but did not write the original code.
//It remains to me a mystery as to what
//the business logic is trying to accomplish here other than to serve as
//some sort of a compensation shell game invented by a den of thieves.
//Oh well, everyone wants this stuff to work the same as before.
//I guess the devil you know is better than the devil you don't.
其他回答
下面的代码是在Python模拟教程中看到的。
# This is my rifle.
def rifle(type='hunting'):
print('This is my (%s) rifle.' % type)
# This is my gun.
def gun(type='hand'):
print('This is my (%s) gun.' % type)
# This is for fighting.
def fighting(type='illegal'):
print('This is for (%s) fighting.' % type)
# This is for fun.
def fun(type='gaming'):
print('This is for (%s) fun.' % type)
作者一定是《恶搞之家》的粉丝。^ _ ^
从http://www.madore.org/ ~大卫/电脑/ callcc.html:
/* Yow! DEMONS are flying through my NOSE! */
/*
after hours of consulting the tome of google
i have discovered that by the will of unknown forces
without the below line, IE7 believes that 6px = 12px
*/
font-size: 0px;
%%return_median
hit_the_sweet_spot(Arg)->
.
.
# There is a bug in the next line. $searchParameters != {} will always return true, because {} is creating
# a new hash reference on the fly, and the inequality operater is comparing the memory location of it
# to the memory location of $searchParameters, and they will always be different.
# This means that the following code will always get executed as long as $nodes is defined.
# I'm leaving it there because it has always been there, and although I'm sure it was originally meant to
# mean %$searchParameters (essentially "is this hash not empty"), I'm afraid to change it.
if ( $nodes && $searchParameters != {} )
{
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