另一个解决方案是使用fstring从列表中写入

lines = ['hello','world']
with open('filename.txt', "w") as fhandle:
  for line in lines:
    fhandle.write(f'{line}\n')

作为一个函数

def write_list(fname, lines):
    with open(fname, "w") as fhandle:
      for line in lines:
        fhandle.write(f'{line}\n')

write_list('filename.txt', ['hello','world'])

好的，这里有一个安全的方法。

with open('example.txt', 'w') as f:
 for i in range(10):
  f.write(str(i+1))
  f.write('\n')

这将在新行中对每个数字写入1到10。

另一个解决方案是使用fstring从列表中写入

lines = ['hello','world']
with open('filename.txt', "w") as fhandle:
  for line in lines:
    fhandle.write(f'{line}\n')

作为一个函数

def write_list(fname, lines):
    with open(fname, "w") as fhandle:
      for line in lines:
        fhandle.write(f'{line}\n')

write_list('filename.txt', ['hello','world'])

你可以使用c风格的字符串格式化:

file.write("%s\n" % "myString")

更多关于字符串格式。

对我来说，在print()语句上使用append (a)和open()看起来更容易:

save_url  = ".\test.txt"

your_text = "This will be on line 1"
print(your_text, file=open(save_url, "a+"))

another_text = "This will be on line 2"
print(another_text, file=open(save_url, "a+"))

another_text = "This will be on line 3"
print(another_text, file=open(save_url, "a+"))

这是我自己想出来的解决方法为了系统地产生n作为分离器。它使用一个字符串列表，其中每个字符串是文件的一行，但它似乎也可以为您工作。(Python 3 +)。

#Takes a list of strings and prints it to a file.
def writeFile(file, strList):
    line = 0
    lines = []
    while line < len(strList):
        lines.append(cheekyNew(line) + strList[line])
        line += 1
    file = open(file, "w")
    file.writelines(lines)
    file.close()

#Returns "\n" if the int entered isn't zero, otherwise "".
def cheekyNew(line):
    if line != 0:
        return "\n"
    return ""