我有一个带有一些GET参数的URL,如下所示:
www.test.com/t.html?a=1&b=3&c=m2-m3-m4-m5
我需要得到c的全部值。我试图读取URL,但只得到m2。如何使用JavaScript执行此操作?
我有一个带有一些GET参数的URL,如下所示:
www.test.com/t.html?a=1&b=3&c=m2-m3-m4-m5
我需要得到c的全部值。我试图读取URL,但只得到m2。如何使用JavaScript执行此操作?
当前回答
PHP parse_str copycat..:)
// Handles also array params well
function parseQueryString(query) {
var pars = (query != null ? query : "").replace(/&+/g, "&").split('&'),
par, key, val, re = /^([\w]+)\[(.*)\]/i, ra, ks, ki, i = 0,
params = {};
while ((par = pars.shift()) && (par = par.split('=', 2))) {
key = decodeURIComponent(par[0]);
// prevent param value going to be "undefined" as string
val = decodeURIComponent(par[1] || "").replace(/\+/g, " ");
// check array params
if (ra = re.exec(key)) {
ks = ra[1];
// init array param
if (!(ks in params)) {
params[ks] = {};
}
// set int key
ki = (ra[2] != "") ? ra[2] : i++;
// set array param
params[ks][ki] = val;
// go on..
continue;
}
// set param
params[key] = val;
}
return params;
}
var query = 'foo=1&bar=The+bar!%20&arr[]=a0&arr[]=a1&arr[s]=as&isset&arr[]=last';
var params = parseQueryString(query);
console.log(params)
console.log(params.foo) // 1
console.log(params.bar) // The bar!
console.log(params.arr[0]) // a0
console.log(params.arr[1]) // a1
console.log(params.arr.s) // as
console.log(params.arr.none) // undefined
console.log("isset" in params) // true like: isset($_GET['isset'])
/*
// in php
parse_str('foo=1&bar=The+bar!%20&arr[]=a0&arr[]=a1&arr[s]=as&isset&arr[]=last', $query);
print_r($query);
Array
(
[foo] => 1
[bar] => The bar!
[arr] => Array
(
[0] => a0
[1] => a1
[s] => as
[2] => last
)
[isset] =>
)*/
其他回答
最短路径:
new URL(location.href).searchParams.get("my_key");
优雅、实用的解决方案
让我们创建一个包含URL参数名作为关键字的对象,然后我们可以通过其名称轻松提取参数:
// URL: https://example.com/?test=true&orderId=9381
// Build an object containing key-value pairs
export const queryStringParams = window.location.search
.split('?')[1]
.split('&')
.map(keyValue => keyValue.split('='))
.reduce<QueryStringParams>((params, [key, value]) => {
params[key] = value;
return params;
}, {});
type QueryStringParams = {
[key: string]: string;
};
// Return URL parameter called "orderId"
return queryStringParams.orderId;
这是一种只检查一个参数的简单方法:
示例URL:
http://myserver/action?myParam=2
Javascript示例:
var myParam = location.search.split('myParam=')[1]
如果URL中存在“myParam”。。。变量myParam将包含“2”,否则将未定义。
在这种情况下,可能需要一个默认值:
var myParam = location.search.split('myParam=')[1] ? location.search.split('myParam=')[1] : 'myDefaultValue';
更新:这更有效:
var url = "http://www.example.com/index.php?myParam=384&login=admin"; // or window.location.href for current url
var captured = /myParam=([^&]+)/.exec(url)[1]; // Value is in [1] ('384' in our case)
var result = captured ? captured : 'myDefaultValue';
即使URL中充满了参数,它也能正常工作。
// Read a page's GET URL variables and return them as an associative array.
function getUrlVars()
{
var vars = [], hash;
var hashes = window.location.href.slice(window.location.href.indexOf('?') + 1).split('&');
for(var i = 0; i < hashes.length; i++)
{
hash = hashes[i].split('=');
vars.push(hash[0]);
vars[hash[0]] = hash[1];
}
return vars;
}
// Usage for URL: http://my.site.com/location?locationId=53cc272c0364aefcb78756cd&shared=false
var id = getUrlVars()["locationId"];
从这里得到:http://jquery-howto.blogspot.ru/2009/09/get-url-parameters-values-with-jquery.html
我很早以前就发现了这一点,非常简单:
function getUrlVars() {
var vars = {};
var parts = window.location.href.replace(/[?&]+([^=&]+)=([^&]*)/gi,
function(m,key,value) {
vars[key] = value;
});
return vars;
}
然后这样称呼:
var fType = getUrlVars()["type"];