这是可行的，但您需要插入自己的错误检查。

public class StringConcatenate {

    public static void main(String[] args){

        // Create two arrays to concatenate and one array to hold both
        String[] arr1 = new String[]{"s","t","r","i","n","g"};
        String[] arr2 = new String[]{"s","t","r","i","n","g"};
        String[] arrBoth = new String[arr1.length+arr2.length];

        // Copy elements from first array into first part of new array
        for(int i = 0; i < arr1.length; i++){
            arrBoth[i] = arr1[i];
        }

        // Copy elements from second array into last part of new array
        for(int j = arr1.length;j < arrBoth.length;j++){
            arrBoth[j] = arr2[j-arr1.length];
        }

        // Print result
        for(int k = 0; k < arrBoth.length; k++){
            System.out.print(arrBoth[k]);
        }

        // Additional line to make your terminal look better at completion!
        System.out.println();
    }
}

它可能不是最有效的，但除了Java自己的API之外，它不依赖其他任何东西。

这是算盘常用的密码。

String[] a = {"a", "b", "c"};
String[] b = {"1", "2", "3"};
String[] c = N.concat(a, b); // c = ["a", "b", "c", "1", "2", "3"]

// N.concat(...) is null-safety.
a = null;
c = N.concat(a, b); // c = ["1", "2", "3"]

用lambda连接一系列紧凑、快速且类型安全的数组

@SafeVarargs
public static <T> T[] concat( T[]... arrays ) {
  return( Stream.of( arrays ).reduce( ( arr1, arr2 ) -> {
      T[] rslt = Arrays.copyOf( arr1, arr1.length + arr2.length );
      System.arraycopy( arr2, 0, rslt, arr1.length, arr2.length );
      return( rslt );
    } ).orElse( null ) );
};

在没有参数的情况下调用时返回null

例如，具有3个阵列：

String[] a = new String[] { "a", "b", "c", "d" };
String[] b = new String[] { "e", "f", "g", "h" };
String[] c = new String[] { "i", "j", "k", "l" };

concat( a, b, c );  // [a, b, c, d, e, f, g, h, i, j, k, l]

“……可能是唯一通用和类型安全的方法”–适用于：

Number[] array1 = { 1, 2, 3 };
Number[] array2 = { 4.0, 5.0, 6.0 };
Number[] array = concat( array1, array2 );  // [1, 2, 3, 4.0, 5.0, 6.0]

这一个只适用于int，但想法是通用的

public static int[] junta(int[] v, int[] w) {

int[] junta = new int[v.length + w.length];

for (int i = 0; i < v.length; i++) {            
    junta[i] = v[i];
}

for (int j = v.length; j < junta.length; j++) {
    junta[j] = w[j - v.length];
}

应该会成功的。这是假设String[]第一个，String[]第二个

List<String> myList = new ArrayList<String>(Arrays.asList(first));
myList.addAll(new ArrayList<String>(Arrays.asList(second)));
String[] both = myList.toArray(new String[myList.size()]);

这应该是一个衬垫。

public String [] concatenate (final String array1[], final String array2[])
{
    return Stream.concat(Stream.of(array1), Stream.of(array2)).toArray(String[]::new);
}