我想在MySQL数据库中取出重复的记录。这可以用:

SELECT address, count(id) as cnt FROM list
GROUP BY address HAVING cnt > 1

结果是:

100 MAIN ST    2

我想要拖动它,以便它显示复制的每一行。喜欢的东西:

JIM    JONES    100 MAIN ST
JOHN   SMITH    100 MAIN ST

有什么想法可以做到吗?我试图避免做第一个,然后在代码中用第二个查询查找重复。


当前回答

    SELECT *
    FROM (SELECT  address, COUNT(id) AS cnt
    FROM list
    GROUP BY address
    HAVING ( COUNT(id) > 1 ))

其他回答

SELECT * FROM booking WHERE DATE(created_at) = '2022-01-11' 和代码在( 从预订中选择代码 按代码分组 have COUNT(code) > )由id DESC订购

SELECT id, count(*) as c  
 FROM 'list'
GROUP BY id HAVING c > 1

这将返回id和该id重复的次数,或者什么都没有,在这种情况下,您将不会有重复的id。

通过(例如:address)更改组中的id,它将返回一个地址由第一个找到的id与该地址重复标识的次数。

SELECT id, count(*) as c  
 FROM 'list'
GROUP BY address HAVING c > 1

我希望这能有所帮助。喜欢。)

这样不是更简单吗?

SELECT *
FROM tc_tariff_groups
GROUP BY group_id
HAVING COUNT(group_id) >1

?

    SELECT *
    FROM (SELECT  address, COUNT(id) AS cnt
    FROM list
    GROUP BY address
    HAVING ( COUNT(id) > 1 ))

会是这样的:

SELECT  t1.firstname t1.lastname t1.address FROM list  t1
    INNER JOIN  list t2 
    WHERE 
        t1.id < t2.id AND 
        t1.address = t2.address;