在MySQL中查找重复的记录

我想在MySQL数据库中取出重复的记录。这可以用:

SELECT address, count(id) as cnt FROM list
GROUP BY address HAVING cnt > 1

结果是:

100 MAIN ST    2

我想要拖动它，以便它显示复制的每一行。喜欢的东西:

JIM    JONES    100 MAIN ST
JOHN   SMITH    100 MAIN ST

有什么想法可以做到吗?我试图避免做第一个，然后在代码中用第二个查询查找重复。

当前回答

SELECT date FROM logs group by date having count(*) >= 2

其他回答

不是很有效，但应该可以工作:

SELECT *
FROM list AS outer
WHERE (SELECT COUNT(*)
        FROM list AS inner
        WHERE inner.address = outer.address) > 1;

我试着用最好的答案来回答这个问题，但它还是把我弄糊涂了。实际上，我只需要在表的一个字段上。下面这个链接的例子对我来说效果很好:

SELECT COUNT(*) c,title FROM `data` GROUP BY title HAVING c > 1;

从列表中选择地址where address = any (Select address from (Select address, count(id) CNT from list group by address with CNT > 1) as t1)按地址排序

内部子查询返回具有重复地址的行外层子查询返回重复地址的地址列。外层子查询必须只返回一列，因为它被用作操作符'= any'的操作数。

 SELECT firstname, lastname, address FROM list
 WHERE 
 Address in 
 (SELECT address FROM list
 GROUP BY address
 HAVING count(*) > 1)

我使用以下方法:

SELECT * FROM mytable
WHERE id IN (
  SELECT id FROM mytable
  GROUP BY column1, column2, column3
  HAVING count(*) > 1
)

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