我想让我的应用看起来更专业,所以我决定添加一个启动画面。
我应该如何进行实现呢?
我想让我的应用看起来更专业,所以我决定添加一个启动画面。
我应该如何进行实现呢?
当前回答
我在android中使用线程制作Flash屏幕。
import android.content.Intent;
import android.os.Bundle;
import android.support.annotation.Nullable;
import android.support.v7.app.AppCompatActivity;
public class HomeScreen extends AppCompatActivity{
@Override
protected void onCreate(@Nullable Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.screen_home);
Thread thread = new Thread(){
public void run(){
try {
Thread.sleep(3 * 1000);
Intent i = new Intent(HomeScreen.this, MainActivity.class);
startActivity(i);
} catch (InterruptedException e) {
}
}
};
thread.start();
}
}
其他回答
Create an activity: Splash Create a layout XML file: splash.xml Put UI components in the splash.xml layout so it looks how you want your Splash.java may look like this: public class Splash extends Activity { @Override public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.splash); int secondsDelayed = 1; new Handler().postDelayed(new Runnable() { public void run() { startActivity(new Intent(Splash.this, ActivityB.class)); finish(); } }, secondsDelayed * 1000); } } change ActivityB.class to whichever activity you want to start after the splash screen check your manifest file and it should look like
<活动 android: name = "。屏” android: label = " @string / app_name " > > < /活动 <活动 android: name = "。飞溅” android: label = " @string / title_activity_splash_screen " > <意图过滤器> <action android:name="android.intent.action. main " /> <category android:name="android.intent.category. launcher " /> < /意图过滤器> > < /活动
Create an Activity SplashScreen.java public class SplashScreen extends Activity { protected boolean _active = true; protected int _splashTime = 3000; // time to display the splash screen in ms @Override public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.splashscreen); Thread splashTread = new Thread() { @Override public void run() { try { int waited = 0; while (_active && (waited < _splashTime)) { sleep(100); if (_active) { waited += 100; } } } catch (Exception e) { } finally { startActivity(new Intent(SplashScreen.this, MainActivity.class)); finish(); } }; }; splashTread.start(); } } splashscreen.xml will be like this <?xml version="1.0" encoding="utf-8"?> <RelativeLayout xmlns:android="http://schemas.android.com/apk/res/android" android:layout_width="600px" android:layout_height="1024px" android:background="#FF0000"> </RelativeLayout>
我在android中使用线程制作Flash屏幕。
import android.content.Intent;
import android.os.Bundle;
import android.support.annotation.Nullable;
import android.support.v7.app.AppCompatActivity;
public class HomeScreen extends AppCompatActivity{
@Override
protected void onCreate(@Nullable Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.screen_home);
Thread thread = new Thread(){
public void run(){
try {
Thread.sleep(3 * 1000);
Intent i = new Intent(HomeScreen.this, MainActivity.class);
startActivity(i);
} catch (InterruptedException e) {
}
}
};
thread.start();
}
}
在Kotlin中编写以下代码:-
Handler().postDelayed({
val mainIntent = Intent(this@SplashActivity, LoginActivity::class.java)
startActivity(mainIntent)
finish()
}, 500)
希望这对你有所帮助,谢谢........
public class MainActivity extends Activity {
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
Thread t=new Thread()
{
public void run()
{
try {
sleep(2000);
finish();
Intent cv=new Intent(MainActivity.this,HomeScreen.class/*otherclass*/);
startActivity(cv);
}
catch (InterruptedException e) {
e.printStackTrace();
}
}
};
t.start();
}