我想让我的应用看起来更专业,所以我决定添加一个启动画面。
我应该如何进行实现呢?
我想让我的应用看起来更专业,所以我决定添加一个启动画面。
我应该如何进行实现呢?
当前回答
这是完整的代码
SplashActivity.java
public class SplashActivity extends AppCompatActivity {
private final int SPLASH_DISPLAY_DURATION = 1000;
@Override
public void onCreate(Bundle bundle) {
super.onCreate(bundle);
new Handler().postDelayed(new Runnable(){
@Override
public void run() {
Intent mainIntent = new Intent(SplashActivity.this,MainActivity.class);
SplashActivity.this.startActivity(mainIntent);
SplashActivity.this.finish();
}
}, SPLASH_DISPLAY_DURATION);
}}
在drawables中创建bg_splash.xml
<?xml version="1.0" encoding="utf-8"?><layer-list xmlns:android="http://schemas.android.com/apk/res/android">
<item
android:drawable="@color/app_color"/>
<item>
<bitmap
android:gravity="center"
android:src="@drawable/ic_in_app_logo_big"/>
</item></layer-list>
在styles.xml中创建一个自定义主题
<style name="SplashTheme" parent="Theme.AppCompat.NoActionBar">
<item name="android:windowBackground">@drawable/bg_splash</item>
</style>
最后在AndroidManifest.xml中指定活动的主题
<activity
android:name=".activities.SplashActivity"
android:label="@string/app_name"
android:screenOrientation="portrait"
android:theme="@style/SplashTheme">
<intent-filter>
<action android:name="android.intent.action.MAIN" />
<category android:name="android.intent.category.LAUNCHER" />
</intent-filter>
</activity>
欢呼。
其他回答
public class MainActivity extends Activity {
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
Thread t=new Thread()
{
public void run()
{
try {
sleep(2000);
finish();
Intent cv=new Intent(MainActivity.this,HomeScreen.class/*otherclass*/);
startActivity(cv);
}
catch (InterruptedException e) {
e.printStackTrace();
}
}
};
t.start();
}
在Android中,启动画面是一个有点不可用的对象:为了隐藏主活动启动的延迟,它不能尽快加载。使用它有两个原因:广告和网络运营。
实现为对话框使跳跃没有延迟从启动画面到主UI的活动。
public class SplashDialog extends Dialog {
ImageView splashscreen;
SplashLoader loader;
int splashTime = 4000;
public SplashDialog(Context context, int theme) {
super(context, theme);
}
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_splash);
setCancelable(false);
new Handler().postDelayed(new Runnable() {
@Override
public void run() {
cancel();
}
}, splashTime);
}
}
布局:
<?xml version="1.0" encoding="utf-8"?>
<RelativeLayout xmlns:android="http://schemas.android.com/apk/res/android"
android:layout_width="fill_parent"
android:layout_height="fill_parent"
android:background="@color/white">
<ImageView
android:id="@+id/splashscreen"
android:layout_width="190dp"
android:layout_height="190dp"
android:background="@drawable/whistle"
android:layout_centerInParent="true" />
</RelativeLayout>
并开始:
public class MyActivity extends ActionBarActivity {
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
if (getIntent().getCategories() != null && getIntent().getCategories().contains("android.intent.category.LAUNCHER")) {
showSplashScreen();
}
}
protected Dialog splashDialog;
protected void showSplashScreen() {
splashDialog = new SplashDialog(this, R.style.SplashScreen);
splashDialog.show();
}
...
}
进一步阅读:
应用发布时间和主题发布屏幕(Android Performance Patterns Season 6 Ep. 4) Android中的启动画面:正确的方法
旧的回答:
如何:简单的启动画面
这个答案会告诉你如何在应用启动时固定时间显示启动画面。例如,你可以选择显示3秒的启动画面。然而,如果你想要在可变的时间内(例如应用启动时间)显示飞溅屏幕,你应该看看Abdullah的答案https://stackoverflow.com/a/15832037/401025。但是要注意,应用程序在新设备上的启动速度可能非常快,所以用户只会看到一个flash,这是糟糕的用户体验。
首先,您需要在layout.xml文件中定义飞溅屏幕
<?xml version="1.0" encoding="utf-8"?>
<LinearLayout xmlns:android="http://schemas.android.com/apk/res/android"
android:orientation="vertical" android:layout_width="fill_parent"
android:layout_height="fill_parent">
<ImageView android:id="@+id/splashscreen" android:layout_width="wrap_content"
android:layout_height="fill_parent"
android:src="@drawable/splash"
android:layout_gravity="center"/>
<TextView android:layout_width="fill_parent"
android:layout_height="wrap_content"
android:text="Hello World, splash"/>
</LinearLayout>
你的活动:
import android.app.Activity;
import android.content.Intent;
import android.os.Bundle;
import android.os.Handler;
public class Splash extends Activity {
/** Duration of wait **/
private final int SPLASH_DISPLAY_LENGTH = 1000;
/** Called when the activity is first created. */
@Override
public void onCreate(Bundle icicle) {
super.onCreate(icicle);
setContentView(R.layout.splashscreen);
/* New Handler to start the Menu-Activity
* and close this Splash-Screen after some seconds.*/
new Handler().postDelayed(new Runnable(){
@Override
public void run() {
/* Create an Intent that will start the Menu-Activity. */
Intent mainIntent = new Intent(Splash.this,Menu.class);
Splash.this.startActivity(mainIntent);
Splash.this.finish();
}
}, SPLASH_DISPLAY_LENGTH);
}
}
这就是全部;)
在Kotlin中编写以下代码:-
Handler().postDelayed({
val mainIntent = Intent(this@SplashActivity, LoginActivity::class.java)
startActivity(mainIntent)
finish()
}, 500)
希望这对你有所帮助,谢谢........
一个超级灵活的启动屏幕如何,可以使用相同的代码,并在AndroidManifest.xml中定义,因此代码永远不需要更改。我通常开发代码库,不喜欢定制代码,因为它很草率。
<activity
android:name=".SplashActivity">
<intent-filter>
<action android:name="android.intent.action.MAIN" />
<category android:name="android.intent.category.LAUNCHER" />
</intent-filter>
<meta-data android:name="launch_class" android:value="com.mypackage.MyFirstActivity" />
<meta-data android:name="duration" android:value="5000" />
</activity>
然后SpashActivity本身查找“launch_class”的元数据,然后创建Intent本身。元数据“持续时间”定义了启动画面持续的时间。
public class SplashActivity extends Activity {
/** Called when the activity is first created. */
@Override
public void onCreate(Bundle icicle) {
super.onCreate(icicle);
setContentView(R.layout.activity_splash);
ComponentName componentName = new ComponentName(this, this.getClass());
try {
Bundle bundle = null;
bundle = getPackageManager().getActivityInfo(componentName, PackageManager.GET_META_DATA).metaData;
String launch_class = bundle.getString("launch_class");
//default of 2 seconds, otherwise defined in manifest
int duration = bundle.getInt("duration", 2000);
if(launch_class != null) {
try {
final Class<?> c = Class.forName(launch_class);
new Handler().postDelayed(new Runnable() {
@Override
public void run() {
Intent intent = new Intent(SplashActivity.this, c);
startActivity(intent);
finish();
}
}, duration);
} catch (ClassNotFoundException e) {
e.printStackTrace();
}
}
} catch (PackageManager.NameNotFoundException e) {
e.printStackTrace();
}
}
}