问:Java中的异常处理真的很慢吗?
传统观点以及大量谷歌结果表明，不应该将异常逻辑用于Java中的正常程序流。通常会给出两个原因，
它真的很慢——甚至比普通代码慢一个数量级(给出的原因各不相同)，
and
它很混乱，因为人们只希望在异常代码中处理错误。
这个问题是关于第一条的。
As an example, this page describes Java exception handling as "very slow" and relates the slowness to the creation of the exception message string - "this string is then used in creating the exception object that is thrown. This is not fast." The article Effective Exception Handling in Java says that "the reason for this is due to the object creation aspect of exception handling, which thereby makes throwing exceptions inherently slow". Another reason out there is that the stack trace generation is what slows it down.
My testing (using Java 1.6.0_07, Java HotSpot 10.0, on 32 bit Linux), indicates that exception handling is no slower than regular code. I tried running a method in a loop that executes some code. At the end of the method, I use a boolean to indicate whether to return or throw. This way the actual processing is the same. I tried running the methods in different orders and averaging my test times, thinking it may have been the JVM warming up. In all my tests, the throw was at least as fast as the return, if not faster (up to 3.1% faster). I am completely open to the possibility that my tests were wrong, but I haven't seen anything out there in the way of the code sample, test comparisons, or results in the last year or two that show exception handling in Java to actually be slow.
引导我走上这条路的是我需要使用的一个API，它将抛出异常作为正常控制逻辑的一部分。我想纠正它们的用法，但现在我可能做不到。我是否应该赞美他们的前瞻思维?
在论文《即时编译中的高效Java异常处理》中，作者建议，即使没有抛出异常，仅异常处理程序的存在就足以阻止JIT编译器正确优化代码，从而降低代码的速度。我还没有测试过这个理论。
不幸的是，我的回答太长了，不能在这里发表。所以让我在这里总结一下，并向你推荐http://www.fuwjax.com/how-slow-are-java-exceptions/以获得更具体的细节。
这里真正的问题不是“与“从未失败的代码”相比，“将失败报告为异常”的速度有多慢?”，正如人们所接受的回答可能会让你相信的那样。相反，问题应该是“与其他方式报告的失败相比，‘作为异常报告的失败’有多慢?”通常，报告失败的另外两种方法是使用哨兵值或使用结果包装器。
哨兵值是在成功情况下返回一个类，在失败情况下返回另一个类的尝试。你几乎可以把它看作是返回一个异常而不是抛出一个异常。这需要一个与success对象共享的父类，然后执行“instanceof”检查和几个类型转换来获得成功或失败的信息。
事实证明，冒着类型安全的风险，Sentinel值比异常快，但仅快大约2倍。现在，这可能看起来很多，但2倍只包括实现差异的成本。实际上，这个因素要低得多，因为我们可能失败的方法要比本页其他地方示例代码中的几个算术运算符有趣得多。
另一方面，结果包装器根本不牺牲类型安全。它们将成功和失败信息包装在单个类中。因此，它们提供了一个“isSuccess()”来代替“instanceof”，并为成功和失败对象提供了getter。但是，结果对象大约比使用异常慢2倍。事实证明，每次创建一个新的包装器对象比有时抛出异常要昂贵得多。
最重要的是，异常是语言提供的一种指示方法可能失败的方式。没有其他方法可以仅从API判断哪些方法总是(大部分)工作，哪些方法报告失败。
异常比哨兵更安全，比结果对象更快，并且比两者都不那么令人惊讶。我并不是建议用try/catch替换if/else，但是异常是报告失败的正确方式，即使在业务逻辑中也是如此。
也就是说，我想指出的是，我遇到的两种最常见的实质上影响性能的方法是创建不必要的对象和嵌套循环。如果可以在创建异常和不创建异常之间选择，请不要创建异常。如果要在有时创建异常或始终创建另一个对象之间做出选择，那么就创建异常。
关于异常性能的好文章是:
https://shipilev.net/blog/2014/exceptional-performance/
实例化vs重用现有的，有堆栈跟踪和没有，等等:
Benchmark Mode Samples Mean Mean error Units
dynamicException avgt 25 1901.196 14.572 ns/op
dynamicException_NoStack avgt 25 67.029 0.212 ns/op
dynamicException_NoStack_UsedData avgt 25 68.952 0.441 ns/op
dynamicException_NoStack_UsedStack avgt 25 137.329 1.039 ns/op
dynamicException_UsedData avgt 25 1900.770 9.359 ns/op
dynamicException_UsedStack avgt 25 20033.658 118.600 ns/op
plain avgt 25 1.259 0.002 ns/op
staticException avgt 25 1.510 0.001 ns/op
staticException_NoStack avgt 25 1.514 0.003 ns/op
staticException_NoStack_UsedData avgt 25 4.185 0.015 ns/op
staticException_NoStack_UsedStack avgt 25 19.110 0.051 ns/op
staticException_UsedData avgt 25 4.159 0.007 ns/op
staticException_UsedStack avgt 25 25.144 0.186 ns/op
根据堆栈跟踪的深度:
Benchmark Mode Samples Mean Mean error Units
exception_0000 avgt 25 1959.068 30.783 ns/op
exception_0001 avgt 25 1945.958 12.104 ns/op
exception_0002 avgt 25 2063.575 47.708 ns/op
exception_0004 avgt 25 2211.882 29.417 ns/op
exception_0008 avgt 25 2472.729 57.336 ns/op
exception_0016 avgt 25 2950.847 29.863 ns/op
exception_0032 avgt 25 4416.548 50.340 ns/op
exception_0064 avgt 25 6845.140 40.114 ns/op
exception_0128 avgt 25 11774.758 54.299 ns/op
exception_0256 avgt 25 21617.526 101.379 ns/op
exception_0512 avgt 25 42780.434 144.594 ns/op
exception_1024 avgt 25 82839.358 291.434 ns/op
有关其他详细信息(包括来自JIT的x64汇编程序)，请阅读原始博客文章。
这意味着Hibernate/Spring/etc-EE-shit因为异常(xD)而变慢。
通过重写应用程序控制流，避免异常(返回错误作为返回)，提高应用程序的性能10 -100倍，这取决于你抛出它们的频率))
使用附带的代码，在JDK 15上，@Mecki测试用例得到了完全不同的结果。这基本上是在5个循环中运行代码，第一个循环稍微短一些，给VM一些时间来热身。
结果:
Loop 1 10000 cycles
method1 took 1 ms, result was 2
method2 took 0 ms, result was 2
method3 took 22 ms, result was 2
method4 took 22 ms, result was 2
method5 took 24 ms, result was 2
Loop 2 10000000 cycles
method1 took 39 ms, result was 2
method2 took 39 ms, result was 2
method3 took 1558 ms, result was 2
method4 took 1640 ms, result was 2
method5 took 1717 ms, result was 2
Loop 3 10000000 cycles
method1 took 49 ms, result was 2
method2 took 48 ms, result was 2
method3 took 126 ms, result was 2
method4 took 88 ms, result was 2
method5 took 87 ms, result was 2
Loop 4 10000000 cycles
method1 took 34 ms, result was 2
method2 took 34 ms, result was 2
method3 took 33 ms, result was 2
method4 took 98 ms, result was 2
method5 took 58 ms, result was 2
Loop 5 10000000 cycles
method1 took 34 ms, result was 2
method2 took 33 ms, result was 2
method3 took 33 ms, result was 2
method4 took 48 ms, result was 2
method5 took 49 ms, result was 2
package hs.jfx.eventstream.api;
public class Snippet {
int value;
public int getValue() {
return value;
}
public void reset() {
value = 0;
}
// Calculates without exception
public void method1(int i) {
value = ((value + i) / i) << 1;
// Will never be true
if ((i & 0xFFFFFFF) == 1000000000) {
System.out.println("You'll never see this!");
}
}
// Could in theory throw one, but never will
public void method2(int i) throws Exception {
value = ((value + i) / i) << 1;
// Will never be true
if ((i & 0xFFFFFFF) == 1000000000) {
throw new Exception();
}
}
private static final NoStackTraceRuntimeException E = new NoStackTraceRuntimeException();
// This one will regularly throw one
public void method3(int i) throws NoStackTraceRuntimeException {
value = ((value + i) / i) << 1;
// i & 1 is equally fast to calculate as i & 0xFFFFFFF; it is both
// an AND operation between two integers. The size of the number plays
// no role. AND on 32 BIT always ANDs all 32 bits
if ((i & 0x1) == 1) {
throw E;
}
}
// This one will regularly throw one
public void method4(int i) throws NoStackTraceThrowable {
value = ((value + i) / i) << 1;
// i & 1 is equally fast to calculate as i & 0xFFFFFFF; it is both
// an AND operation between two integers. The size of the number plays
// no role. AND on 32 BIT always ANDs all 32 bits
if ((i & 0x1) == 1) {
throw new NoStackTraceThrowable();
}
}
// This one will regularly throw one
public void method5(int i) throws NoStackTraceRuntimeException {
value = ((value + i) / i) << 1;
// i & 1 is equally fast to calculate as i & 0xFFFFFFF; it is both
// an AND operation between two integers. The size of the number plays
// no role. AND on 32 BIT always ANDs all 32 bits
if ((i & 0x1) == 1) {
throw new NoStackTraceRuntimeException();
}
}
public static void main(String[] args) {
for(int k = 0; k < 5; k++) {
int cycles = 10000000;
if(k == 0) {
cycles = 10000;
try {
Thread.sleep(500);
}
catch(InterruptedException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
}
System.out.println("Loop " + (k + 1) + " " + cycles + " cycles");
int i;
long l;
Snippet t = new Snippet();
l = System.currentTimeMillis();
t.reset();
for (i = 1; i < cycles; i++) {
t.method1(i);
}
l = System.currentTimeMillis() - l;
System.out.println(
"method1 took " + l + " ms, result was " + t.getValue()
);
l = System.currentTimeMillis();
t.reset();
for (i = 1; i < cycles; i++) {
try {
t.method2(i);
} catch (Exception e) {
System.out.println("You'll never see this!");
}
}
l = System.currentTimeMillis() - l;
System.out.println(
"method2 took " + l + " ms, result was " + t.getValue()
);
l = System.currentTimeMillis();
t.reset();
for (i = 1; i < cycles; i++) {
try {
t.method3(i);
} catch (NoStackTraceRuntimeException e) {
// always comes here
}
}
l = System.currentTimeMillis() - l;
System.out.println(
"method3 took " + l + " ms, result was " + t.getValue()
);
l = System.currentTimeMillis();
t.reset();
for (i = 1; i < cycles; i++) {
try {
t.method4(i);
} catch (NoStackTraceThrowable e) {
// always comes here
}
}
l = System.currentTimeMillis() - l;
System.out.println( "method4 took " + l + " ms, result was " + t.getValue() );
l = System.currentTimeMillis();
t.reset();
for (i = 1; i < cycles; i++) {
try {
t.method5(i);
} catch (RuntimeException e) {
// always comes here
}
}
l = System.currentTimeMillis() - l;
System.out.println( "method5 took " + l + " ms, result was " + t.getValue() );
}
}
public static class NoStackTraceRuntimeException extends RuntimeException {
public NoStackTraceRuntimeException() {
super("my special throwable", null, false, false);
}
}
public static class NoStackTraceThrowable extends Throwable {
public NoStackTraceThrowable() {
super("my special throwable", null, false, false);
}
}
}
不知道这些主题是否相关，但我曾经想实现一个依赖于当前线程的堆栈跟踪的技巧:我想发现方法的名称，它触发了实例化类中的实例化(是的，这个想法很疯狂，我完全放弃了它)。所以我发现调用Thread.currentThread(). getstacktrace()是非常慢的(由于本机的dumpThreads方法，它在内部使用)。
相应地，Java Throwable有一个本地方法fillInStackTrace。我认为前面描述的kill -catch块以某种方式触发了该方法的执行。
但让我告诉你另一个故事……
在Scala中，一些函数特性是使用ControlThrowable在JVM中编译的，它扩展了Throwable，并以以下方式覆盖了它的fillInStackTrace:
override def fillInStackTrace(): Throwable = this
所以我调整了上面的测试(循环量减少了十，我的机器有点慢:):
class ControlException extends ControlThrowable
class T {
var value = 0
def reset = {
value = 0
}
def method1(i: Int) = {
value = ((value + i) / i) << 1
if ((i & 0xfffffff) == 1000000000) {
println("You'll never see this!")
}
}
def method2(i: Int) = {
value = ((value + i) / i) << 1
if ((i & 0xfffffff) == 1000000000) {
throw new Exception()
}
}
def method3(i: Int) = {
value = ((value + i) / i) << 1
if ((i & 0x1) == 1) {
throw new Exception()
}
}
def method4(i: Int) = {
value = ((value + i) / i) << 1
if ((i & 0x1) == 1) {
throw new ControlException()
}
}
}
class Main {
var l = System.currentTimeMillis
val t = new T
for (i <- 1 to 10000000)
t.method1(i)
l = System.currentTimeMillis - l
println("method1 took " + l + " ms, result was " + t.value)
t.reset
l = System.currentTimeMillis
for (i <- 1 to 10000000) try {
t.method2(i)
} catch {
case _ => println("You'll never see this")
}
l = System.currentTimeMillis - l
println("method2 took " + l + " ms, result was " + t.value)
t.reset
l = System.currentTimeMillis
for (i <- 1 to 10000000) try {
t.method4(i)
} catch {
case _ => // do nothing
}
l = System.currentTimeMillis - l
println("method4 took " + l + " ms, result was " + t.value)
t.reset
l = System.currentTimeMillis
for (i <- 1 to 10000000) try {
t.method3(i)
} catch {
case _ => // do nothing
}
l = System.currentTimeMillis - l
println("method3 took " + l + " ms, result was " + t.value)
}
所以，结果是:
method1 took 146 ms, result was 2
method2 took 159 ms, result was 2
method4 took 1551 ms, result was 2
method3 took 42492 ms, result was 2
你看，method3和method4之间唯一的区别是它们会抛出不同类型的异常。是的，method4仍然比method1和method2慢，但是差异是可以接受的。
