这对我来说很管用:

  targetView.getParent().requestChildFocus(targetView,targetView);

RequestChildFocus(查看子视图，查看焦点)

child -这个ViewParent的想要聚焦的子对象。该视图将包含聚焦视图。它并不一定是真正有焦点的观点。

focused -实际上具有焦点的child的后代视图

将postDelayed添加到视图中，这样getTop()就不会返回0。

binding.scrollViewLogin.postDelayed({
            val scrollTo = binding.textInputLayoutFirstName.top
            binding.scrollViewLogin.isSmoothScrollingEnabled = true
            binding.scrollViewLogin.smoothScrollTo(0, scrollTo)
     }, 400
) 

还要确保视图是scrollView的直接子视图，否则你会得到getTop()为零。示例:嵌入在TextInputLayout中的edittext的getTop()将返回0。在这种情况下，我们需要计算TextInputLayout的getTop()它是ScrollView的直接子。

<ScrollView>
    <TextInputLayout>
        <EditText/>
    </TextInputLayout>
</ScrollView>

我基于WarrenFaith的答案做了一个小工具方法，这段代码也考虑了视图是否已经在滚动视图中可见，不需要滚动。

public static void scrollToView(final ScrollView scrollView, final View view) {

    // View needs a focus
    view.requestFocus();

    // Determine if scroll needs to happen
    final Rect scrollBounds = new Rect();
    scrollView.getHitRect(scrollBounds);
    if (!view.getLocalVisibleRect(scrollBounds)) {
        new Handler().post(new Runnable() {
            @Override
            public void run() {
                scrollView.smoothScrollTo(0, view.getBottom());
            }
        });
    } 
}

我的解决方案是:

            int[] spinnerLocation = {0,0};
            spinner.getLocationOnScreen(spinnerLocation);

            int[] scrollLocation = {0, 0};
            scrollView.getLocationInWindow(scrollLocation);

            int y = scrollView.getScrollY();

            scrollView.smoothScrollTo(0, y + spinnerLocation[1] - scrollLocation[1]);

你可以像这样使用ObjectAnimator:

ObjectAnimator.ofInt(yourScrollView, "scrollY", yourView.getTop()).setDuration(1500).start();

参考资料:https://stackoverflow.com/a/6438240/2624806

接下来的工作要好得多。

mObservableScrollView.post(new Runnable() {
            public void run() { 
                mObservableScrollView.fullScroll([View_FOCUS][1]); 
            }
        });