scrollView.post(new Runnable() {
    @Override
    public void run() {
        scrollView.smoothScrollTo(0, myTextView.getTop());
    }
});

回答来自我的实际项目。

private final void focusOnView(){
    yourScrollView.post(new Runnable() {
        @Override
        public void run() {
            yourScrollView.scrollTo(0, yourEditText.getBottom());
        }
    });
}

我的解决方案是:

            int[] spinnerLocation = {0,0};
            spinner.getLocationOnScreen(spinnerLocation);

            int[] scrollLocation = {0, 0};
            scrollView.getLocationInWindow(scrollLocation);

            int y = scrollView.getScrollY();

            scrollView.smoothScrollTo(0, y + spinnerLocation[1] - scrollLocation[1]);

如果ScrollView是ChildView的直接父类，上面的答案就可以很好地工作。如果你的ChildView被包装在ScrollView中的另一个ViewGroup中，它将导致意外的行为，因为View.getTop()获得相对于其父的位置。在这种情况下，你需要实现这个:

public static void scrollToInvalidInputView(ScrollView scrollView, View view) {
    int vTop = view.getTop();

    while (!(view.getParent() instanceof ScrollView)) {
        view = (View) view.getParent();
        vTop += view.getTop();
    }

    final int scrollPosition = vTop;

    new Handler().post(() -> scrollView.smoothScrollTo(0, scrollPosition));
}

另一种说法是:

scrollView.postDelayed(new Runnable()
{
    @Override
    public void run()
    {
        scrollView.smoothScrollTo(0, img_transparent.getTop());
    }
}, 200);

或者可以使用post()方法。

Sherif elKhatib的答案可以大大改进，如果你想将视图滚动到滚动视图的中心。这个可重用的方法平滑地将视图滚动到HorizontalScrollView的可见中心。

private final void focusOnView(final HorizontalScrollView scroll, final View view) {
    new Handler().post(new Runnable() {
        @Override
        public void run() {
            int vLeft = view.getLeft();
            int vRight = view.getRight();
            int sWidth = scroll.getWidth();
            scroll.smoothScrollTo(((vLeft + vRight - sWidth) / 2), 0);
        }
    });
}

对于垂直ScrollView的使用

...
int vTop = view.getTop();
int vBottom = view.getBottom();
int sHeight = scroll.getBottom();
scroll.smoothScrollTo(0, ((vTop + vBottom - sHeight) / 2));
...