Charset UTF8_CHARSET = Charset.forName("UTF-8");
String strISO = "{\"name\":\"א\"}";
System.out.println(strISO);
byte[] b = strISO.getBytes();
for (byte c: b) {
    System.out.print("[" + c + "]");
}
String str = new String(b, UTF8_CHARSET);
System.out.println(str);

Charset UTF8_CHARSET = Charset.forName("UTF-8");
String strISO = "{\"name\":\"א\"}";
System.out.println(strISO);
byte[] b = strISO.getBytes();
for (byte c: b) {
    System.out.print("[" + c + "]");
}
String str = new String(b, UTF8_CHARSET);
System.out.println(str);

String original = "hello world";
byte[] utf8Bytes = original.getBytes("UTF-8");

这里有一个解决方案，避免执行Charset查找每次转换:

import java.nio.charset.Charset;

private final Charset UTF8_CHARSET = Charset.forName("UTF-8");

String decodeUTF8(byte[] bytes) {
    return new String(bytes, UTF8_CHARSET);
}

byte[] encodeUTF8(String string) {
    return string.getBytes(UTF8_CHARSET);
}

//query is your json   

 DefaultHttpClient httpClient = new DefaultHttpClient();
 HttpPost postRequest = new HttpPost("http://my.site/test/v1/product/search?qy=");

 StringEntity input = new StringEntity(query, "UTF-8");
 input.setContentType("application/json");
 postRequest.setEntity(input);   
 HttpResponse response=response = httpClient.execute(postRequest);

我的tomcat7实现是接受字符串作为ISO-8859-1;不管HTTP请求的内容类型是什么。当我试图正确解释'é'这样的字符时，下面的解决方案对我有效。

byte[] b1 = szP1.getBytes("ISO-8859-1");
System.out.println(b1.toString());

String szUT8 = new String(b1, "UTF-8");
System.out.println(szUT8);

当试图将字符串解释为US-ASCII时，字节信息没有正确解释。

b1 = szP1.getBytes("US-ASCII");
System.out.println(b1.toString());