String original = "hello world";
byte[] utf8Bytes = original.getBytes("UTF-8");

作为替代，可以使用Apache Commons中的StringUtils。

 byte[] bytes = {(byte) 1};
 String convertedString = StringUtils.newStringUtf8(bytes);

or

 String myString = "example";
 byte[] convertedBytes = StringUtils.getBytesUtf8(myString);

如果你有非标准的字符集，你可以相应地使用getBytesUnchecked()或newString()。

这里有一个解决方案，避免执行Charset查找每次转换:

import java.nio.charset.Charset;

private final Charset UTF8_CHARSET = Charset.forName("UTF-8");

String decodeUTF8(byte[] bytes) {
    return new String(bytes, UTF8_CHARSET);
}

byte[] encodeUTF8(String string) {
    return string.getBytes(UTF8_CHARSET);
}

非常晚，但我刚刚遇到了这个问题，这是我的解决方案:

private static String removeNonUtf8CompliantCharacters( final String inString ) {
    if (null == inString ) return null;
    byte[] byteArr = inString.getBytes();
    for ( int i=0; i < byteArr.length; i++ ) {
        byte ch= byteArr[i]; 
        // remove any characters outside the valid UTF-8 range as well as all control characters
        // except tabs and new lines
        if ( !( (ch > 31 && ch < 253 ) || ch == '\t' || ch == '\n' || ch == '\r') ) {
            byteArr[i]=' ';
        }
    }
    return new String( byteArr );
}

Charset UTF8_CHARSET = Charset.forName("UTF-8");
String strISO = "{\"name\":\"א\"}";
System.out.println(strISO);
byte[] b = strISO.getBytes();
for (byte c: b) {
    System.out.print("[" + c + "]");
}
String str = new String(b, UTF8_CHARSET);
System.out.println(str);

Reader reader = new BufferedReader(
    new InputStreamReader(
        new ByteArrayInputStream(
            string.getBytes(StandardCharsets.UTF_8)), StandardCharsets.UTF_8));