例如,我有日期:“23/2/2010”(2010年2月23日)。我想把它传递给一个返回星期几的函数。我该怎么做呢?
在这个例子中,函数应该返回String "Tue"。
此外,如果只需要日期顺序,如何检索?
例如,我有日期:“23/2/2010”(2010年2月23日)。我想把它传递给一个返回星期几的函数。我该怎么做呢?
在这个例子中,函数应该返回String "Tue"。
此外,如果只需要日期顺序,如何检索?
当前回答
下面是两行代码片段,使用Java 1.8 Time API满足您的需求。
LocalDate localDate = LocalDate.of(Integer.valueOf(year),Integer.valueOf(month),Integer.valueOf(day));
String dayOfWeek = String.valueOf(localDate.getDayOfWeek());
其他回答
import java.text.SimpleDateFormat;
import java.util.Scanner;
class DayFromDate {
public static void main(String args[]) {
System.out.println("Enter the date(dd/mm/yyyy):");
Scanner scan = new Scanner(System.in);
String Date = scan.nextLine();
try {
boolean dateValid = dateValidate(Date);
if(dateValid == true) {
SimpleDateFormat df = new SimpleDateFormat( "dd/MM/yy" );
java.util.Date date = df.parse( Date );
df.applyPattern( "EEE" );
String day= df.format( date );
if(day.compareTo("Sat") == 0 || day.compareTo("Sun") == 0) {
System.out.println(day + ": Weekend");
} else {
System.out.println(day + ": Weekday");
}
} else {
System.out.println("Invalid Date!!!");
}
} catch(Exception e) {
System.out.println("Invalid Date Formats!!!");
}
}
static public boolean dateValidate(String d) {
String dateArray[] = d.split("/");
int day = Integer.parseInt(dateArray[0]);
int month = Integer.parseInt(dateArray[1]);
int year = Integer.parseInt(dateArray[2]);
System.out.print(day + "\n" + month + "\n" + year + "\n");
boolean leapYear = false;
if((year % 4 == 0) && (year % 100 != 0) || (year % 400 == 0)) {
leapYear = true;
}
if(year > 2099 || year < 1900)
return false;
if(month < 13) {
if(month == 1 || month == 3 || month == 5 || month == 7 || month == 8 || month == 10 || month == 12) {
if(day > 31)
return false;
} else if(month == 4 || month == 6 || month == 9 || month == 11) {
if(day > 30)
return false;
} else if(leapYear == true && month == 2) {
if(day > 29)
return false;
} else if(leapYear == false && month == 2) {
if(day > 28)
return false;
}
return true;
} else return false;
}
}
通过使用java.util.scanner包给用户输入日期、月和年来查找星期几的程序:
import java.util.Scanner;
public class Calender {
public static String getDay(String day, String month, String year) {
int ym, yp, d, ay, a = 0;
int by = 20;
int[] y = new int[]{6, 4, 2, 0};
int[] m = new int []{0, 3, 3, 6, 1, 4, 6, 2, 5, 0, 3, 5};
String[] wd = {"Sunday", "Monday", "Tuesday", "Wednesday", "Thursday", "Friday", "Saturday"};
int gd = Integer.parseInt(day);
int gm = Integer.parseInt(month);
int gy = Integer.parseInt(year);
ym = gy % 100;
yp = ym / 4;
ay = gy / 100;
while (ay != by) {
by = by + 1;
a = a + 1;
if(a == 4) {
a = 0;
}
}
if ((ym % 4 == 0) && (gm == 2)) {
d = (gd + m[gm - 1] + ym + yp + y[a] - 1) % 7;
} else
d = (gd + m[gm - 1] + ym + yp + y[a]) % 7;
return wd[d];
}
public static void main(String[] args) {
Scanner in = new Scanner(System.in);
String day = in.next();
String month = in.next();
String year = in.next();
System.out.println(getDay(day, month, year));
}
}
为今天找一个日期,然后从中找出一个星期。
LocalDate d = java.time.LocalDate.now();
System.out.println(java.time.LocalDate.now());
Calendar c = Calendar.getInstance();
int dayOfWeek = c.get(Calendar.DAY_OF_WEEK);
System.out.println(dayOfWeek);
public class TryDateFormats {
public static void main(String[] args) throws ParseException {
String month = "08";
String day = "05";
String year = "2015";
String inputDateStr = String.format("%s/%s/%s", day, month, year);
Date inputDate = new SimpleDateFormat("dd/MM/yyyy").parse(inputDateStr);
Calendar calendar = Calendar.getInstance();
calendar.setTime(inputDate);
String dayOfWeek = calendar.getDisplayName(Calendar.DAY_OF_WEEK, Calendar.LONG, Locale.US).toUpperCase();
System.out.println(dayOfWeek);
}
}
添加了另一种完全符合OP要求的方法,而不使用最新的内置方法:
public static String getDay(String inputDate) {
String dayOfWeek = null;
String[] days = new String[]{"Mon", "Tue", "Wed", "Thu", "Fri", "Sat", "Sun"};
try {
SimpleDateFormat format1 = new SimpleDateFormat("dd/MM/yyyy");
Date dt1 = format1.parse(inputDate);
dayOfWeek = days[dt1.getDay() - 1];
} catch(Exception e) {
System.out.println(e);
}
return dayOfWeek;
}