例如,我有日期:“23/2/2010”(2010年2月23日)。我想把它传递给一个返回星期几的函数。我该怎么做呢?
在这个例子中,函数应该返回String "Tue"。
此外,如果只需要日期顺序,如何检索?
例如,我有日期:“23/2/2010”(2010年2月23日)。我想把它传递给一个返回星期几的函数。我该怎么做呢?
在这个例子中,函数应该返回String "Tue"。
此外,如果只需要日期顺序,如何检索?
当前回答
import java.text.SimpleDateFormat;
import java.util.Scanner;
class DayFromDate {
public static void main(String args[]) {
System.out.println("Enter the date(dd/mm/yyyy):");
Scanner scan = new Scanner(System.in);
String Date = scan.nextLine();
try {
boolean dateValid = dateValidate(Date);
if(dateValid == true) {
SimpleDateFormat df = new SimpleDateFormat( "dd/MM/yy" );
java.util.Date date = df.parse( Date );
df.applyPattern( "EEE" );
String day= df.format( date );
if(day.compareTo("Sat") == 0 || day.compareTo("Sun") == 0) {
System.out.println(day + ": Weekend");
} else {
System.out.println(day + ": Weekday");
}
} else {
System.out.println("Invalid Date!!!");
}
} catch(Exception e) {
System.out.println("Invalid Date Formats!!!");
}
}
static public boolean dateValidate(String d) {
String dateArray[] = d.split("/");
int day = Integer.parseInt(dateArray[0]);
int month = Integer.parseInt(dateArray[1]);
int year = Integer.parseInt(dateArray[2]);
System.out.print(day + "\n" + month + "\n" + year + "\n");
boolean leapYear = false;
if((year % 4 == 0) && (year % 100 != 0) || (year % 400 == 0)) {
leapYear = true;
}
if(year > 2099 || year < 1900)
return false;
if(month < 13) {
if(month == 1 || month == 3 || month == 5 || month == 7 || month == 8 || month == 10 || month == 12) {
if(day > 31)
return false;
} else if(month == 4 || month == 6 || month == 9 || month == 11) {
if(day > 30)
return false;
} else if(leapYear == true && month == 2) {
if(day > 29)
return false;
} else if(leapYear == false && month == 2) {
if(day > 28)
return false;
}
return true;
} else return false;
}
}
其他回答
另一个“有趣”的方法是使用末日算法。这是一个更长的方法,但如果您不需要用给定的日期创建Calendar对象,那么它也更快。
import java.text.ParseException;
import java.text.SimpleDateFormat;
import java.util.ArrayList;
import java.util.Calendar;
import java.util.HashMap;
import java.util.Map;
import java.util.Random;
/**
*
* @author alain.janinmanificat
*/
public class Doomsday {
public static HashMap<Integer, ArrayList<Integer>> anchorDaysMap = new HashMap<>();
public static HashMap<Integer, Integer> doomsdayDate = new HashMap<>();
public static String weekdays[] = new DateFormatSymbols(Locale.FRENCH).getWeekdays();
/**
* @param args the command line arguments
*/
public static void main(String[] args) throws ParseException, ParseException {
// Map is fed manually but we can use this to calculate it : http://en.wikipedia.org/wiki/Doomsday_rule#Finding_a_century.27s_anchor_day
anchorDaysMap.put(Integer.valueOf(0), new ArrayList<Integer>() {
{
add(Integer.valueOf(1700));
add(Integer.valueOf(2100));
add(Integer.valueOf(2500));
}
});
anchorDaysMap.put(Integer.valueOf(2), new ArrayList<Integer>() {
{
add(Integer.valueOf(1600));
add(Integer.valueOf(2000));
add(Integer.valueOf(2400));
}
});
anchorDaysMap.put(Integer.valueOf(3), new ArrayList<Integer>() {
{
add(Integer.valueOf(1500));
add(Integer.valueOf(1900));
add(Integer.valueOf(2300));
}
});
anchorDaysMap.put(Integer.valueOf(5), new ArrayList<Integer>() {
{
add(Integer.valueOf(1800));
add(Integer.valueOf(2200));
add(Integer.valueOf(2600));
}
});
//Some reference date that always land on Doomsday
doomsdayDate.put(Integer.valueOf(1), Integer.valueOf(3));
doomsdayDate.put(Integer.valueOf(2), Integer.valueOf(14));
doomsdayDate.put(Integer.valueOf(3), Integer.valueOf(14));
doomsdayDate.put(Integer.valueOf(4), Integer.valueOf(4));
doomsdayDate.put(Integer.valueOf(5), Integer.valueOf(9));
doomsdayDate.put(Integer.valueOf(6), Integer.valueOf(6));
doomsdayDate.put(Integer.valueOf(7), Integer.valueOf(4));
doomsdayDate.put(Integer.valueOf(8), Integer.valueOf(8));
doomsdayDate.put(Integer.valueOf(9), Integer.valueOf(5));
doomsdayDate.put(Integer.valueOf(10), Integer.valueOf(10));
doomsdayDate.put(Integer.valueOf(11), Integer.valueOf(7));
doomsdayDate.put(Integer.valueOf(12), Integer.valueOf(12));
long time = System.currentTimeMillis();
for (int i = 0; i < 100000; i++) {
//Get a random date
int year = 1583 + new Random().nextInt(500);
int month = 1 + new Random().nextInt(12);
int day = 1 + new Random().nextInt(7);
//Get anchor day and DoomsDay for current date
int twoDigitsYear = (year % 100);
int century = year - twoDigitsYear;
int adForCentury = getADCentury(century);
int dd = ((int) twoDigitsYear / 12) + twoDigitsYear % 12 + (int) ((twoDigitsYear % 12) / 4);
//Get the gap between current date and a reference DoomsDay date
int referenceDay = doomsdayDate.get(month);
int gap = (day - referenceDay) % 7;
int result = (gap + adForCentury + dd) % 7;
if(result<0){
result*=-1;
}
String dayDate= weekdays[(result + 1) % 8];
//System.out.println("day:" + dayDate);
}
System.out.println("time (ms) : " + (System.currentTimeMillis() - time)); //time (ms) : 80
time = System.currentTimeMillis();
for (int i = 0; i < 100000; i++) {
Calendar c = Calendar.getInstance();
//I should have used random date here too, but it's already slower this way
c.setTime(new SimpleDateFormat("dd/MM/yyyy").parse("12/04/1861"));
// System.out.println(new SimpleDateFormat("EE").format(c.getTime()));
int result2 = c.get(Calendar.DAY_OF_WEEK);
// System.out.println("day idx :"+ result2);
}
System.out.println("time (ms) : " + (System.currentTimeMillis() - time)); //time (ms) : 884
}
public static int getADCentury(int century) {
for (Map.Entry<Integer, ArrayList<Integer>> entry : anchorDaysMap.entrySet()) {
if (entry.getValue().contains(Integer.valueOf(century))) {
return entry.getKey();
}
}
return 0;
}
}
java.time
使用java。在Java 8及以后版本中内置了时间框架。
DayOfWeek枚举可以生成一个字符串,其中包含自动本地化为本地语言和文化规范的日期名称。指定一个TextStyle来指示您想要长形式或缩写名称。
import java.time.LocalDate
import java.time.format.DateTimeFormatter
import java.time.format.TextStyle
import java.util.Locale
import java.time.DayOfWeek;
DateTimeFormatter formatter = DateTimeFormatter.ofPattern("d/M/yyyy");
LocalDate date = LocalDate.parse("23/2/2010", formatter); // LocalDate = 2010-02-23
DayOfWeek dow = date.getDayOfWeek(); // Extracts a `DayOfWeek` enum object.
String output = dow.getDisplayName(TextStyle.SHORT, Locale.US); // String = Tue
日历类有内置的displayName功能:
Calendar.getInstance().getDisplayName(Calendar.DAY_OF_WEEK, Calendar.SHORT, Locale.getDefault()); // Thu
Calendar.SHORT -> Thu
Calendar.LONG_FORMAT -> Thursday
Java 1.6以来可用。参见Oracle文档
Calendar cal = Calendar.getInstance(desired date);
cal.setTimeInMillis(System.currentTimeMillis());
int dayOfWeek = cal.get(Calendar.DAY_OF_WEEK);
通过提供当前时间戳获取日值。
一句话回答:
return LocalDate.parse("06/02/2018",DateTimeFormatter.ofPattern("dd/MM/yyyy")).getDayOfWeek().name();
使用的例子:
public static String getDayOfWeek(String date){
return LocalDate.parse(date, DateTimeFormatter.ofPattern("dd/MM/yyyy")).getDayOfWeek().name();
}
public static void callerMethod(){
System.out.println(getDayOfWeek("06/02/2018")); //TUESDAY
}