非常直截了当。在javascript中,我需要检查字符串是否包含数组中持有的任何子字符串。


当前回答

我也遇到过这样的问题。我有一个URL,我想检查链接是否以图像格式或其他文件格式结束,有一个图像格式数组。以下是我所做的:

const imagesFormat = ['.jpg','.png','.svg']
const link = "https://res.cloudinary.com/***/content/file_padnar.pdf"
const isIncludes = imagesFormat.some(format => link.includes(format))
    
// false

其他回答

对于用谷歌搜索的人来说,

确切的答案应该是。

const substrings = ['connect', 'ready'];
const str = 'disconnect';
if (substrings.some(v => str === v)) {
   // Will only return when the `str` is included in the `substrings`
}

var str = "A for apple" var subString = ["apple"] console.log (str.includes (subString))

function containsAny(str, substrings) {
    for (var i = 0; i != substrings.length; i++) {
       var substring = substrings[i];
       if (str.indexOf(substring) != - 1) {
         return substring;
       }
    }
    return null; 
}

var result = containsAny("defg", ["ab", "cd", "ef"]);
console.log("String was found in substring " + result);

使用underscore.js或lodash.js,你可以对字符串数组执行以下操作:

var contacts = ['Billy Bob', 'John', 'Bill', 'Sarah'];

var filters = ['Bill', 'Sarah'];

contacts = _.filter(contacts, function(contact) {
    return _.every(filters, function(filter) { return (contact.indexOf(filter) === -1); });
});

// ['John']

在一个字符串上:

var contact = 'Billy';
var filters = ['Bill', 'Sarah'];

_.every(filters, function(filter) { return (contact.indexOf(filter) >= 0); });

// true

你可以这样检查:

<!DOCTYPE html>
<html>
   <head>
      <script src="https://ajax.googleapis.com/ajax/libs/jquery/3.4.1/jquery.min.js"></script>
      <script>
         $(document).ready(function(){
         var list = ["bad", "words", "include"] 
         var sentence = $("#comments_text").val()

         $.each(list, function( index, value ) {
           if (sentence.indexOf(value) > -1) {
                console.log(value)
            }
         });
         });
      </script>
   </head>
   <body>
      <input id="comments_text" value="This is a bad, with include test"> 
   </body>
</html>