下面是从表单中获取数据的最短方法，也是使用FormData避免id和ref的最佳方法

import React, { Component } from 'react'

class FormComponent extends Component {
  formSubmit = (event) => {
    event.preventDefault()
    var data = new FormData(event.target)
    let formObject = Object.fromEntries(data.entries())
    console.log(formObject)
  }
  render() {
    return (
      <div>
        <form onSubmit={this.formSubmit}>
          <label>Name</label>
          <input name="name" placeholder="name" />
          <label>Email</label>
          <input type="email" name="email" />
          <input type="submit" />
        </form>
      </div>
    )
  }
}
export default FormComponent

es6析构的更清晰的例子

class Form extends Component {
    constructor(props) {
        super(props);
        this.state = {
            login: null,
            password: null,
            email: null
        }
    }

    onChange(e) {
        this.setState({
            [e.target.name]: e.target.value
        })
    }

    onSubmit(e) {
        e.preventDefault();
        let login = this.state.login;
        let password = this.state.password;
        // etc
    }

    render() {
        return (
            <form onSubmit={this.onSubmit.bind(this)}>
                <input type="text" name="login" onChange={this.onChange.bind(this)} />
                <input type="password" name="password" onChange={this.onChange.bind(this)} />
                <input type="email" name="email" onChange={this.onChange.bind(this)} />
                <button type="submit">Sign Up</button>
            </form>
        );
    }
}

下面是我使用单个inputChangeHandler收集多个表单输入的方法

import React from "react";

const COLORS = ["red", "orange", "yellow", "purple", "green", "white", "black"];

export default function App() {

  const initialFormFields = {
    name: undefined,
    email: undefined,
    favourite_color: undefined
  };
  const [formInput, setFormInput] = React.useState(initialFormFields);

  function inputChangeHandler(event) {
    setFormInput(prevFormState => ({
      ...prevFormState,
      [event.target.name]: event.target.value
    }))
  };

  return (
    <div className="App">
      <form>
        <label>Name: <input name="name" type="text" value={formInput.name} onChange={inputChangeHandler}/></label>
        <label>Email: <input name="email" type="email" value={formInput.email} onChange={inputChangeHandler}/></label>
        <div>
          {COLORS.map(color => <label><input type="radio" name="favourite_color" value={color} key={color} onChange={inputChangeHandler}/> {color} </label>)}
        </div>
      </form>

      <div>
        Entered Name: {formInput.name}
        Entered Email: {formInput.email}
        Favourite Color: {formInput.favourite_color}
      </div>
    </div>
  );
}

这可能会帮助Meteor (v1.3)的用户:

render: function() {
    return (
        <form onSubmit={this.submitForm.bind(this)}>
            <input type="text" ref="email" placeholder="Email" />
            <input type="password" ref="password" placeholder="Password" />
            <button type="submit">Login</button>
        </form>
    );
},
submitForm: function(e) {
    e.preventDefault();
    console.log( this.refs.email.value );
    console.log( this.refs.password.value );
}

另一种方法是使用ref属性并使用this.refs引用值。这里有一个简单的例子:

render: function() {
    return (<form onSubmit={this.submitForm}>
        <input ref="theInput" />
    </form>);
},
submitForm: function(e) {
    e.preventDefault();
    alert(React.findDOMNode(this.refs.theInput).value);
}

更多信息可以在React文档中找到: https://facebook.github.io/react/docs/more-about-refs.html#the-ref-string-attribute

关于如何在React中使用单选按钮中描述的很多原因?这种方法并不总是最好的，但在一些简单的情况下确实是一种有用的替代方法。

如果你尝试Aliaksandr Sushkevich解决方案，Typescript会抱怨，一个解决方法可以使用类型断言

<form
    onSubmit={(e: React.SyntheticEvent) => {
    e.preventDefault();
    const target = e.target as typeof e.target & {
      username: { value: string };
      password: { value: string };
    };
    const username = target.username.value; // typechecks
    const password = target.password.value; // typechecks
    // etc...
  }}
>
<input type="text" name="username"/>
...

不过，这仍然只是一种变通方法，因为在这里您要告诉typescript期望什么。如果您添加的值没有相应的输入元素，这将在运行时中断。