警告:无耻的插头!

您还可以使用类似我的JsTrace对象的东西来进行模块化跟踪，并具有模块级别的“切换”功能，从而只打开您当时想要看到的内容。

http://jstrace.codeplex.com

(也有一个NuGet包，为那些谁关心)

所有级别默认为“error”，尽管你可以关闭它们。 不过，我想不出为什么您不希望看到错误

你可以这样改变它们:

Trace.traceLevel('ModuleName1', Trace.Levels.log);
Trace.traceLevel('ModuleName2', Trace.Levels.info);

要获得更多文档，请查看文档

T

我认为2020年最简单、最容易理解的方法是创建一个像log()这样的全局函数，你可以选择以下方法之一:

const debugging = true;

function log(toLog) {
  if (debugging) {
    console.log(toLog);
  }
}

function log(toLog) {
  if (true) { // You could manually change it (Annoying, though)
    console.log(toLog);
  }
}

你可以说这些功能的缺点是:

您仍然在运行时调用函数 您必须记住在第二个选项中更改调试变量或if语句 您需要确保在加载所有其他文件之前加载了该函数

And my retorts to these statements is that this is the only method that won't completely remove the console or console.log function which I think is bad programming because other developers who are working on the website would have to realize that you ignorantly removed them. Also, you can't edit JavaScript source code in JavaScript, so if you really want something to just wipe all of those from the code you could use a minifier that minifies your code and removes all console.logs. Now, the choice is yours, what will you do?

在脚本中重新定义console.log函数。

console.log = function() {}

够了，不再给控制台发消息了。

编辑:

扩展了Cide的想法。一个自定义记录器，您可以使用它从代码中切换登录。

从我的Firefox控制台:

var logger = function()
{
    var oldConsoleLog = null;
    var pub = {};

    pub.enableLogger =  function enableLogger() 
                        {
                            if(oldConsoleLog == null)
                                return;

                            window['console']['log'] = oldConsoleLog;
                        };

    pub.disableLogger = function disableLogger()
                        {
                            oldConsoleLog = console.log;
                            window['console']['log'] = function() {};
                        };

    return pub;
}();

$(document).ready(
    function()
    {
        console.log('hello');

        logger.disableLogger();
        console.log('hi', 'hiya');
        console.log('this wont show up in console');

        logger.enableLogger();
        console.log('This will show up!');
    }
 );

如何使用上面的“记录器”?在就绪事件中，调用记录器。disableLogger使控制台消息不被记录。向记录器添加调用。enabllogger和logger。在希望将消息记录到控制台的方法中的disableLogger。

这是来自SolutionYogi和Chris s的答案的混合。它维护console.log行号和文件名。jsFiddle示例。

// Avoid global functions via a self calling anonymous one (uses jQuery)
(function(MYAPP, $, undefined) {
    // Prevent errors in browsers without console.log
    if (!window.console) window.console = {};
    if (!window.console.log) window.console.log = function(){};

    //Private var
    var console_log = console.log;  

    //Public methods
    MYAPP.enableLog = function enableLogger() { console.log = console_log; };   
    MYAPP.disableLog = function disableLogger() { console.log = function() {}; };

}(window.MYAPP = window.MYAPP || {}, jQuery));


// Example Usage:
$(function() {    
    MYAPP.disableLog();    
    console.log('this should not show');

    MYAPP.enableLog();
    console.log('This will show');
});

禁用console.log:

console.log = function() {};

禁用所有写入控制台的功能。

for (let func in console) {
   console[func] = function() {};
}

据我从文档中得知，Firebug没有提供任何变量来切换调试状态。相反，将console.log()包装在一个有条件地调用它的包装器中，即:

DEBUG = true; // set to false to disable debugging
function debug_log() {
    if ( DEBUG ) {
        console.log.apply(this, arguments);
    }
}

为了不需要改变所有现有的调用，你可以使用这个代替:

DEBUG = true; // set to false to disable debugging
old_console_log = console.log;
console.log = function() {
    if ( DEBUG ) {
        old_console_log.apply(this, arguments);
    }
}