我知道你可以一次插入多行，是否有一种方法可以一次更新多行(如在，在一个查询)在MySQL?
编辑: 例如，我有以下内容
Name id Col1 Col2
Row1 1 6 1
Row2 2 2 3
Row3 3 9 5
Row4 4 16 8
我想将以下所有更新组合成一个查询
UPDATE table SET Col1 = 1 WHERE id = 1;
UPDATE table SET Col1 = 2 WHERE id = 2;
UPDATE table SET Col2 = 3 WHERE id = 3;
UPDATE table SET Col1 = 10 WHERE id = 4;
UPDATE table SET Col2 = 12 WHERE id = 4;
当前回答
您可能还对在更新上使用连接感兴趣，这也是可能的。
Update someTable Set someValue = 4 From someTable s Inner Join anotherTable a on s.id = a.id Where a.id = 4
-- Only updates someValue in someTable who has a foreign key on anotherTable with a value of 4.
编辑:如果要更新的值不是来自数据库中的其他地方，则需要发出多个更新查询。
其他回答
为什么没有人在一个查询中提到多个语句?
在php中，使用mysqli实例的multi_query方法。
来自php手册
MySQL允许在一个语句字符串中包含多条语句。一次发送多个语句可以减少客户端-服务器之间的往返，但需要特殊处理。
下面是更新30,000 raw中与其他3种方法的比较结果。代码可以在这里找到，这是基于@Dakusan的回答
事务:5.5194580554962 插入:0.20669293403625 例:16.474853992462 多:0.0412278175354
如您所见，多语句查询比最高答案更有效。
如果你得到这样的错误信息:
PHP Warning: Error while sending SET_OPTION packet
你可能需要增加mysql配置文件中的max_allowed_packet，在我的机器是/etc/mysql/my.cnf，然后重新启动mysqld。
是的，这是可能的-你可以使用INSERT…重复密钥更新。
举个例子:
INSERT INTO table (id,Col1,Col2) VALUES (1,1,1),(2,2,3),(3,9,3),(4,10,12)
ON DUPLICATE KEY UPDATE Col1=VALUES(Col1),Col2=VALUES(Col2);
您可能还对在更新上使用连接感兴趣，这也是可能的。
Update someTable Set someValue = 4 From someTable s Inner Join anotherTable a on s.id = a.id Where a.id = 4
-- Only updates someValue in someTable who has a foreign key on anotherTable with a value of 4.
编辑:如果要更新的值不是来自数据库中的其他地方，则需要发出多个更新查询。
这个问题很老了，但我想用另一个答案来扩展这个话题。
我的观点是，实现它的最简单的方法是用一个事务包装多个查询。这句话的意思是:ON DUPLICATE KEY UPDATE是一个很好的黑客，但人们应该意识到它的缺点和限制:
As being said, if you happen to launch the query with rows whose primary keys don't exist in the table, the query inserts new "half-baked" records. Probably it's not what you want If you have a table with a not null field without default value and don't want to touch this field in the query, you'll get "Field 'fieldname' doesn't have a default value" MySQL warning even if you don't insert a single row at all. It will get you into trouble, if you decide to be strict and turn mysql warnings into runtime exceptions in your app.
I made some performance tests for three of suggested variants, including the INSERT ... ON DUPLICATE KEY UPDATE variant, a variant with "case / when / then" clause and a naive approach with transaction. You may get the python code and results here. The overall conclusion is that the variant with case statement turns out to be twice as fast as two other variants, but it's quite hard to write correct and injection-safe code for it, so I personally stick to the simplest approach: using transactions.
编辑:Dakusan的发现证明我的性能估计不太有效。请参阅另一个更详细的研究的答案。
UPDATE `your_table` SET
`something` = IF(`id`="1","new_value1",`something`), `smth2` = IF(`id`="1", "nv1",`smth2`),
`something` = IF(`id`="2","new_value2",`something`), `smth2` = IF(`id`="2", "nv2",`smth2`),
`something` = IF(`id`="4","new_value3",`something`), `smth2` = IF(`id`="4", "nv3",`smth2`),
`something` = IF(`id`="6","new_value4",`something`), `smth2` = IF(`id`="6", "nv4",`smth2`),
`something` = IF(`id`="3","new_value5",`something`), `smth2` = IF(`id`="3", "nv5",`smth2`),
`something` = IF(`id`="5","new_value6",`something`), `smth2` = IF(`id`="5", "nv6",`smth2`)
//你只是在php中构建它
$q = 'UPDATE `your_table` SET ';
foreach($data as $dat){
$q .= '
`something` = IF(`id`="'.$dat->id.'","'.$dat->value.'",`something`),
`smth2` = IF(`id`="'.$dat->id.'", "'.$dat->value2.'",`smth2`),';
}
$q = substr($q,0,-1);
所以你可以用一个查询更新孔表
