如何查看后台服务是否正在运行?

我想要一个切换服务状态的Android活动——它让我打开它,如果它是关闭的,如果它是关闭的。


当前回答

在你的服务子类中,使用一个静态布尔值来获取服务的状态,如下所示。

MyService.kt

class MyService : Service() {
    override fun onCreate() {
        super.onCreate()
        isServiceStarted = true
    }
    override fun onDestroy() {
        super.onDestroy()
        isServiceStarted = false
    }
    companion object {
        var isServiceStarted = false
    }
}

MainActivity.kt

class MainActivity : AppCompatActivity(){
    override fun onCreate(savedInstanceState: Bundle?) {
        super.onCreate(savedInstanceState)
        setContentView(R.layout.activity_main)

        val serviceStarted = FileObserverService.isServiceStarted
        if (!serviceStarted) {
            val startFileObserverService = Intent(this, FileObserverService::class.java)
            ContextCompat.startForegroundService(this, startFileObserverService)
        }
    }
}

其他回答

简单使用绑定不创建自动查看ps和更新…

public abstract class Context {

 ... 

  /*
  * @return {true} If you have successfully bound to the service, 
  *  {false} is returned if the connection is not made 
  *  so you will not receive the service object.
  */
  public abstract boolean bindService(@RequiresPermission Intent service,
        @NonNull ServiceConnection conn, @BindServiceFlags int flags);

例子:

    Intent bindIntent = new Intent(context, Class<Service>);
    boolean bindResult = context.bindService(bindIntent, ServiceConnection, 0);

为什么不使用呢?getRunningServices ()

List<ActivityManager.RunningServiceInfo> getRunningServices (int maxNum)
Return a list of the services that are currently running.

注意:此方法仅用于调试或实现服务管理类型的用户界面。


附注:android文档具有误导性,我已经在谷歌跟踪器上打开了一个问题,以消除任何疑问:

https://issuetracker.google.com/issues/68908332

正如我们所看到的,绑定服务实际上通过ActivityManager绑定器通过服务缓存绑定器调用了一个事务-我不能跟踪哪个服务负责绑定,但正如我们所看到的,绑定的结果是:

int res = ActivityManagerNative.getDefault().bindService(...);
return res != 0;

通过装订本进行交易:

ServiceManager.getService("activity");

下一个:

  public static IBinder getService(String name) {
    try {
        IBinder service = sCache.get(name);
        if (service != null) {
            return service;
        } else {
            return getIServiceManager().getService(name);

这是在ActivityThread中通过:

 public final void bindApplication(...) {

        if (services != null) {
            // Setup the service cache in the ServiceManager
            ServiceManager.initServiceCache(services);
        }

在ActivityManagerService的method中调用:

 private final boolean attachApplicationLocked(IApplicationThread thread,
            int pid) {
    ...
    thread.bindApplication(... , getCommonServicesLocked(),...)

然后:

 private HashMap<String, IBinder> getCommonServicesLocked() {

但没有“活动”,只有窗口包和报警。

所以我们需要返回调用:

 return getIServiceManager().getService(name);

    sServiceManager = ServiceManagerNative.asInterface(BinderInternal.getContextObject());

这使呼叫通过:

    mRemote.transact(GET_SERVICE_TRANSACTION, data, reply, 0);

这就导致:

BinderInternal.getContextObject()

这是本地方法....

  /**
     * Return the global "context object" of the system.  This is usually
     * an implementation of IServiceManager, which you can use to find
     * other services.
     */
    public static final native IBinder getContextObject();

我现在没有时间去挖掘c,所以在我解析rest call之前,我暂停了我的回答。

但是检查服务是否正在运行的最好方法是创建bind(如果没有创建bind,则服务不存在)-并通过bind查询服务的状态(在其状态上使用存储的内部标志)。

更新23.06.2018

我发现这些很有趣:

/**
 * Provide a binder to an already-bound service.  This method is synchronous
 * and will not start the target service if it is not present, so it is safe
 * to call from {@link #onReceive}.
 *
 * For peekService() to return a non null {@link android.os.IBinder} interface
 * the service must have published it before. In other words some component
 * must have called {@link android.content.Context#bindService(Intent, ServiceConnection, int)} on it.
 *
 * @param myContext The Context that had been passed to {@link #onReceive(Context, Intent)}
 * @param service Identifies the already-bound service you wish to use. See
 * {@link android.content.Context#bindService(Intent, ServiceConnection, int)}
 * for more information.
 */
public IBinder peekService(Context myContext, Intent service) {
    IActivityManager am = ActivityManager.getService();
    IBinder binder = null;
    try {
        service.prepareToLeaveProcess(myContext);
        binder = am.peekService(service, service.resolveTypeIfNeeded(
                myContext.getContentResolver()), myContext.getOpPackageName());
    } catch (RemoteException e) {
    }
    return binder;
}

简而言之:)

“为已经绑定的服务提供绑定器。此方法是同步的,如果目标服务不存在,则不会启动该服务。”

(Intent service, String resolvedType) String callingPackage)抛出RemoteException;

*

public static IBinder peekService(IBinder remote, Intent service, String resolvedType)
             throws RemoteException {
    Parcel data = Parcel.obtain();
    Parcel reply = Parcel.obtain();
    data.writeInterfaceToken("android.app.IActivityManager");
    service.writeToParcel(data, 0);
    data.writeString(resolvedType);
    remote.transact(android.os.IBinder.FIRST_CALL_TRANSACTION+84, data, reply, 0);
    reply.readException();
    IBinder binder = reply.readStrongBinder();
    reply.recycle();
    data.recycle();
    return binder;
}

*

检查服务是否正在运行的正确方法是简单地询问它。在您的服务中实现一个BroadcastReceiver来响应来自活动的ping。在服务启动时注册BroadcastReceiver,在服务被销毁时注销它。从您的活动(或任何组件)发送一个本地广播意图到服务,如果它响应,您就知道它正在运行。注意下面代码中ACTION_PING和ACTION_PONG之间的细微差别。

public class PingableService extends Service {
    public static final String ACTION_PING = PingableService.class.getName() + ".PING";
    public static final String ACTION_PONG = PingableService.class.getName() + ".PONG";

    public int onStartCommand (Intent intent, int flags, int startId) {
        LocalBroadcastManager.getInstance(this).registerReceiver(mReceiver, new IntentFilter(ACTION_PING));
        return super.onStartCommand(intent, flags, startId);
    }

    @Override
    public void onDestroy () {
        LocalBroadcastManager.getInstance(this).unregisterReceiver(mReceiver);
        super.onDestroy();
    }

    private BroadcastReceiver mReceiver = new BroadcastReceiver() {
        @Override
        public void onReceive (Context context, Intent intent) {
            if (intent.getAction().equals(ACTION_PING)) {
                LocalBroadcastManager manager = LocalBroadcastManager.getInstance(getApplicationContext());
                manager.sendBroadcast(new Intent(ACTION_PONG));
            }
        }
    };
}

public class MyActivity extends Activity {
    private boolean isSvcRunning = false;

    @Override
    protected void onStart() {
        LocalBroadcastManager manager = LocalBroadcastManager.getInstance(getApplicationContext());
        manager.registerReceiver(mReceiver, new IntentFilter(PingableService.ACTION_PONG));
        // the service will respond to this broadcast only if it's running
        manager.sendBroadcast(new Intent(PingableService.ACTION_PING));
        super.onStart();
    }

    @Override
    protected void onStop() {
        LocalBroadcastManager.getInstance(this).unregisterReceiver(mReceiver);
        super.onStop();
    }

    protected BroadcastReceiver mReceiver = new BroadcastReceiver() {
        @Override
        public void onReceive (Context context, Intent intent) {
            // here you receive the response from the service
            if (intent.getAction().equals(PingableService.ACTION_PONG)) {
                isSvcRunning = true;
            }
        }
    };
}

不久前我也遇到了同样的问题。由于我的服务是本地的,我最终只是在服务类中使用一个静态字段来切换状态,正如hackbod在这里描述的那样

编辑(供记录):

下面是hackbod提出的解决方案:

如果你的客户端和服务器代码是同一个.apk的一部分,而你是 绑定到服务的具体意图(一个指定 确切的服务类别),然后您可以简单地将您的服务设置为a 全局变量,当它正在运行时,您的客户端可以检查。 我们故意没有API来检查服务是否正确 跑步是因为,当你想做某事时,几乎没有失败 这样,代码中就会出现竞争条件。

摘自Android文档:

比如sendBroadcast(Intent),但是如果有任何接收器 这个函数将阻塞并立即分发它们 返回之前。

你可以把这次入侵看成是"ping "服务。因为我们可以同步广播,所以我们可以在UI线程上同步广播并获得结果。

服务

@Override
public void onCreate() {
   LocalBroadcastManager
     .getInstance(this)
     .registerReceiver(new ServiceEchoReceiver(), new IntentFilter("ping"));
     //do not forget to deregister the receiver when the service is destroyed to avoid
     //any potential memory leaks 
}

private class ServiceEchoReceiver extends BroadcastReceiver {
    public void onReceive (Context context, Intent intent) {
      LocalBroadcastManager
         .getInstance(this)
         .sendBroadcastSync(new Intent("pong"));
    }
}

活动

    bool serviceRunning = false;

    protected void onCreate (Bundle savedInstanceState){
        LocalBroadcastManager.getInstance(this).registerReceiver(pong, new IntentFilter("pong"));
        LocalBroadcastManager.getInstance(this).sendBroadcastSync(new Intent("ping"));
        if(!serviceRunning){
           //run the service
        }
    }

    private BroadcastReceiver pong = new BroadcastReceiver(){
        public void onReceive (Context context, Intent intent) {
          serviceRunning = true;   
        }
    }

当然,在许多应用程序中,赢家是服务上的静态布尔字段,在service . oncreate()中设置为true,在service . ondestroy()中设置为false,因为它要简单得多。

/**
 * Check if the service is Running 
 * @param serviceClass the class of the Service
 *
 * @return true if the service is running otherwise false
 */
public boolean checkServiceRunning(Class<?> serviceClass){
    ActivityManager manager = (ActivityManager) getSystemService(ACTIVITY_SERVICE);
    for (RunningServiceInfo service : manager.getRunningServices(Integer.MAX_VALUE))
    {
        if (serviceClass.getName().equals(service.service.getClassName()))
        {
            return true;
        }
    }
    return false;
}