摘自Android文档:

比如sendBroadcast(Intent)，但是如果有任何接收器 这个函数将阻塞并立即分发它们 返回之前。

你可以把这次入侵看成是"ping "服务。因为我们可以同步广播，所以我们可以在UI线程上同步广播并获得结果。

服务

@Override
public void onCreate() {
   LocalBroadcastManager
     .getInstance(this)
     .registerReceiver(new ServiceEchoReceiver(), new IntentFilter("ping"));
     //do not forget to deregister the receiver when the service is destroyed to avoid
     //any potential memory leaks 
}

private class ServiceEchoReceiver extends BroadcastReceiver {
    public void onReceive (Context context, Intent intent) {
      LocalBroadcastManager
         .getInstance(this)
         .sendBroadcastSync(new Intent("pong"));
    }
}

活动

    bool serviceRunning = false;

    protected void onCreate (Bundle savedInstanceState){
        LocalBroadcastManager.getInstance(this).registerReceiver(pong, new IntentFilter("pong"));
        LocalBroadcastManager.getInstance(this).sendBroadcastSync(new Intent("ping"));
        if(!serviceRunning){
           //run the service
        }
    }

    private BroadcastReceiver pong = new BroadcastReceiver(){
        public void onReceive (Context context, Intent intent) {
          serviceRunning = true;   
        }
    }

当然，在许多应用程序中，赢家是服务上的静态布尔字段，在service . oncreate()中设置为true，在service . ondestroy()中设置为false，因为它要简单得多。

我稍微修改了上面给出的一个解决方案，但是传递的是类而不是泛型字符串名称，以便确保比较来自同一个方法class. getname()的字符串

public class ServiceTools {
    private static String LOG_TAG = ServiceTools.class.getName();

    public static boolean isServiceRunning(Context context,Class<?> serviceClass){
        final ActivityManager activityManager = (ActivityManager)context.getSystemService(Context.ACTIVITY_SERVICE);
        final List<RunningServiceInfo> services = activityManager.getRunningServices(Integer.MAX_VALUE);

        for (RunningServiceInfo runningServiceInfo : services) {
            Log.d(Constants.TAG, String.format("Service:%s", runningServiceInfo.service.getClassName()));
            if (runningServiceInfo.service.getClassName().equals(serviceClass.getName())){
                return true;
            }
        }
        return false;
    }
}

然后

Boolean isServiceRunning = ServiceTools.isServiceRunning(
                    MainActivity.this.getApplicationContext(),
                    BackgroundIntentService.class);

首先，您不应该通过使用ActivityManager来访问服务。(下面讨论)

Services can run on their own, be bound to an Activity or both. The way to check in an Activity if your Service is running or not is by making an interface (that extends Binder) where you declare methods that both, the Activity and the Service, understand. You can do this by making your own Interface where you declare for example "isServiceRunning()". You can then bind your Activity to your Service, run the method isServiceRunning(), the Service will check for itself if it is running or not and returns a boolean to your Activity.

您还可以使用此方法停止您的服务或以其他方式与之交互。

这是我提出的一个很好的解决方案，但它只适用于运行在单独进程中的服务。这可以通过在manifest中添加一个android:process属性来实现。

<service
        android:name=".ExampleService"
        android:process="com.example.service"
        ...

现在，您的服务将运行在具有给定名称的单独进程中。从你的应用程序你可以打电话

val activityManager = context.getSystemService(Context.ACTIVITY_SERVICE) as ActivityManager
activityManager.runningAppProcesses.any { it.processName == "com.example.service" }

如果服务正在运行，则返回true，否则返回false。

重要提示:请注意，它将显示您的服务是何时启动的，但当您禁用它时(即在系统从它解除绑定后)，该进程仍然是活跃的。所以你可以简单地强制移除它:

override fun onUnbind(intent: Intent?): Boolean {
    stopSelf()
    return super.onUnbind(intent)
}

override fun onDestroy() {
    super.onDestroy()
    killProcess(Process.myPid())
}

然后它就完美地工作了。

请使用这个密码。

if (isMyServiceRunning(MainActivity.this, xyzService.class)) { // Service class name
    // Service running
} else {
    // Service Stop
}


public static boolean isMyServiceRunning(Activity activity, Class<?> serviceClass) {
        ActivityManager manager = (ActivityManager) activity.getSystemService(Context.ACTIVITY_SERVICE);
        for (ActivityManager.RunningServiceInfo service : manager.getRunningServices(Integer.MAX_VALUE)) {
            if (serviceClass.getName().equals(service.service.getClassName())) {
                return true;
            }
        }
        return false;
    }

如果你有一个多模块的应用程序，你想知道服务是否从一个模块运行，这取决于包含该服务的模块，你可以使用这个函数:

fun isServiceRunning(context: Context, serviceClassName: String): Boolean {

    val manager = ContextCompat.getSystemService(
        context,
        ActivityManager::class.java
    ) ?: return false

    return manager.getRunningServices(Integer.MAX_VALUE).any { serviceInfo ->
        serviceInfo.service.shortClassName.contains(vpnServiceClassName)
    }
}

MyService服务用法:

isServiceRunning(context, "MyService")

如果服务类名称更改而调用函数没有相应更改，则此函数可能无法正常工作。