我无法找到一种方法来创建一个输入字段颤振，将打开一个数字键盘，应该采取数字输入。这是可能的颤振材料部件?一些GitHub讨论似乎表明这是一个受支持的功能，但我无法找到任何关于它的文档。
当前回答
仅限号码类型
keyboardType: TextInputType.number
和更多的选择与数字垫
keyboardType: TextInputType.numberWithOptions(decimal: true,signed: false)
其他回答
你可以添加键盘类型的输入格式，就像这样
TextField(
inputFormatters: <TextInputFormatter>[
FilteringTextInputFormatter.digitsOnly
],// Only numbers can be entered
keyboardType: TextInputType.number,
);
下面是Android上实际的手机键盘代码:
按键部分:keyboardType: TextInputType.phone，
TextFormField(
style: TextStyle(
fontSize: 24
),
controller: _phoneNumberController,
keyboardType: TextInputType.phone,
decoration: InputDecoration(
prefixText: "+1 ",
labelText: 'Phone number'),
validator: (String value) {
if (value.isEmpty) {
return 'Phone number (+x xxx-xxx-xxxx)';
}
return null;
},
),
TextField(
controller: _controller,
keyboardType: TextInputType.number,
inputFormatters: <TextInputFormatter>[
FilteringTextInputFormatter.allow(RegExp(r'[0.0-9.9]')),
])
设置你的keyboardType为TextInputType.number，
例如:keyboardType: TextInputType.number，
TextFormField(
controller: yourcontroller,
keyboardType: TextInputType.number,
decoration: const InputDecoration(
labelText: 'Mobile',
suffixIcon: Padding(
padding: EdgeInsets.only(),
child:
Icon(Icons.phone_outlined, color: Color(0xffff4876)),
),
),
validator: (text) {
if (text == null || text.isEmpty) {
return 'Please enter your Mobile No.';
}
return null;
},
),
设置键盘和验证器
String numberValidator(String value) {
if(value == null) {
return null;
}
final n = num.tryParse(value);
if(n == null) {
return '"$value" is not a valid number';
}
return null;
}
new TextFormField(
keyboardType: TextInputType.number,
validator: numberValidator,
textAlign: TextAlign.right
...
https://docs.flutter.io/flutter/material/TextFormField/TextFormField.html https://docs.flutter.io/flutter/services/TextInputType-class.html
