是否可以使用一些代码获得设备的IP地址?
当前回答
在你的活动中,下面的函数getIpAddress(context)返回电话的IP地址:
public static String getIpAddress(Context context) {
WifiManager wifiManager = (WifiManager) context.getApplicationContext()
.getSystemService(WIFI_SERVICE);
String ipAddress = intToInetAddress(wifiManager.getDhcpInfo().ipAddress).toString();
ipAddress = ipAddress.substring(1);
return ipAddress;
}
public static InetAddress intToInetAddress(int hostAddress) {
byte[] addressBytes = { (byte)(0xff & hostAddress),
(byte)(0xff & (hostAddress >> 8)),
(byte)(0xff & (hostAddress >> 16)),
(byte)(0xff & (hostAddress >> 24)) };
try {
return InetAddress.getByAddress(addressBytes);
} catch (UnknownHostException e) {
throw new AssertionError();
}
}
其他回答
我不使用Android,但我会用完全不同的方式来解决这个问题。
发送一个查询到谷歌,像这样: https://www.google.com/webhp?sourceid=chrome-instant&ion=1&espv=2&ie=UTF-8#q=my%20ip
并引用发布响应的HTML字段。您也可以直接查询到源。
谷歌最可能比你的应用程序存在的时间长。
只要记住,这可能是你的用户在这个时候没有互联网,你希望发生什么!
祝你好运
你可以这样做
String stringUrl = "https://ipinfo.io/ip";
//String stringUrl = "http://whatismyip.akamai.com/";
// Instantiate the RequestQueue.
RequestQueue queue = Volley.newRequestQueue(MainActivity.instance);
//String url ="http://www.google.com";
// Request a string response from the provided URL.
StringRequest stringRequest = new StringRequest(Request.Method.GET, stringUrl,
new Response.Listener<String>() {
@Override
public void onResponse(String response) {
// Display the first 500 characters of the response string.
Log.e(MGLogTag, "GET IP : " + response);
}
}, new Response.ErrorListener() {
@Override
public void onErrorResponse(VolleyError error) {
IP = "That didn't work!";
}
});
// Add the request to the RequestQueue.
queue.add(stringRequest);
你可以使用LinkProperties。建议用于新的Android版本。
此功能检索WiFi和移动数据的本地IP地址。它需要Manifest.permission。ACCESS_NETWORK_STATE许可。
@Nullable
public static String getDeviceIpAddress(@NonNull ConnectivityManager connectivityManager) {
LinkProperties linkProperties = connectivityManager.getLinkProperties(connectivityManager.getActiveNetwork());
InetAddress inetAddress;
for(LinkAddress linkAddress : linkProperties.getLinkAddresses()) {
inetAddress = linkAddress.getAddress();
if (inetAddress instanceof Inet4Address
&& !inetAddress.isLoopbackAddress()
&& inetAddress.isSiteLocalAddress()) {
return inetAddress.getHostAddress();
}
}
return null;
}
虽然有一个正确的答案,我在这里分享我的答案,希望这样会更方便。
WifiManager wifiMan = (WifiManager) context.getSystemService(Context.WIFI_SERVICE);
WifiInfo wifiInf = wifiMan.getConnectionInfo();
int ipAddress = wifiInf.getIpAddress();
String ip = String.format("%d.%d.%d.%d", (ipAddress & 0xff),(ipAddress >> 8 & 0xff),(ipAddress >> 16 & 0xff),(ipAddress >> 24 & 0xff));
在Kotlin中,没有Formatter
private fun getIPAddress(useIPv4 : Boolean): String {
try {
var interfaces = Collections.list(NetworkInterface.getNetworkInterfaces())
for (intf in interfaces) {
var addrs = Collections.list(intf.getInetAddresses());
for (addr in addrs) {
if (!addr.isLoopbackAddress()) {
var sAddr = addr.getHostAddress();
var isIPv4: Boolean
isIPv4 = sAddr.indexOf(':')<0
if (useIPv4) {
if (isIPv4)
return sAddr;
} else {
if (!isIPv4) {
var delim = sAddr.indexOf('%') // drop ip6 zone suffix
if (delim < 0) {
return sAddr.toUpperCase()
}
else {
return sAddr.substring(0, delim).toUpperCase()
}
}
}
}
}
}
} catch (e: java.lang.Exception) { }
return ""
}
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