一个设备可能有几个IP地址，在一个特定的应用程序中使用的IP地址可能不是接收请求的服务器将看到的IP地址。事实上，一些用户使用VPN或Cloudflare Warp等代理。

如果你的目的是获得IP地址，就像服务器从你的设备接收请求一样，那么最好是通过Java客户端查询IP地理定位服务，如Ipregistry(免责声明:我为该公司工作):

https://github.com/ipregistry/ipregistry-java

IpregistryClient client = new IpregistryClient("tryout");
RequesterIpInfo requesterIpInfo = client.lookup();
requesterIpInfo.getIp();

除了使用非常简单之外，您还可以获得其他信息，例如国家、语言、货币、设备IP的时区，并且您可以识别用户是否正在使用代理。

我不使用Android，但我会用完全不同的方式来解决这个问题。

发送一个查询到谷歌，像这样: https://www.google.com/webhp?sourceid=chrome-instant&ion=1&espv=2&ie=UTF-8#q=my%20ip

并引用发布响应的HTML字段。您也可以直接查询到源。

谷歌最可能比你的应用程序存在的时间长。

只要记住，这可能是你的用户在这个时候没有互联网，你希望发生什么!

祝你好运

private InetAddress getLocalAddress()throws IOException {

            try {
                for (Enumeration<NetworkInterface> en = NetworkInterface.getNetworkInterfaces(); en.hasMoreElements();) {
                    NetworkInterface intf = en.nextElement();
                    for (Enumeration<InetAddress> enumIpAddr = intf.getInetAddresses(); enumIpAddr.hasMoreElements();) {
                        InetAddress inetAddress = enumIpAddr.nextElement();
                        if (!inetAddress.isLoopbackAddress()) {
                            //return inetAddress.getHostAddress().toString();
                            return inetAddress;
                        }
                    }
                }
            } catch (SocketException ex) {
                Log.e("SALMAN", ex.toString());
            }
            return null;
        }

在你的活动中，下面的函数getIpAddress(context)返回电话的IP地址:

public static String getIpAddress(Context context) {
    WifiManager wifiManager = (WifiManager) context.getApplicationContext()
                .getSystemService(WIFI_SERVICE);

    String ipAddress = intToInetAddress(wifiManager.getDhcpInfo().ipAddress).toString();

    ipAddress = ipAddress.substring(1);

    return ipAddress;
}

public static InetAddress intToInetAddress(int hostAddress) {
    byte[] addressBytes = { (byte)(0xff & hostAddress),
                (byte)(0xff & (hostAddress >> 8)),
                (byte)(0xff & (hostAddress >> 16)),
                (byte)(0xff & (hostAddress >> 24)) };

    try {
        return InetAddress.getByAddress(addressBytes);
    } catch (UnknownHostException e) {
        throw new AssertionError();
    }
}

编译一些想法，以更好的kotlin解决方案从WifiManager获得wifi ip:

private fun getWifiIp(context: Context): String? {
  return context.getSystemService<WifiManager>().let {
     when {
      it == null -> "No wifi available"
      !it.isWifiEnabled -> "Wifi is disabled"
      it.connectionInfo == null -> "Wifi not connected"
      else -> {
        val ip = it.connectionInfo.ipAddress
        ((ip and 0xFF).toString() + "." + (ip shr 8 and 0xFF) + "." + (ip shr 16 and 0xFF) + "." + (ip shr 24 and 0xFF))
      }
    }
  }
}

或者，您可以通过NetworkInterface获取ip4环回设备的ip地址:

fun getNetworkIp4LoopbackIps(): Map<String, String> = try {
  NetworkInterface.getNetworkInterfaces()
    .asSequence()
    .associate { it.displayName to it.ip4LoopbackIps() }
    .filterValues { it.isNotEmpty() }
} catch (ex: Exception) {
  emptyMap()
}

private fun NetworkInterface.ip4LoopbackIps() =
  inetAddresses.asSequence()
    .filter { !it.isLoopbackAddress && it is Inet4Address }
    .map { it.hostAddress }
    .filter { it.isNotEmpty() }
    .joinToString()

引用 // get设备Ip地址

open fun getLocalIpAddress(): String? {
    try {
        val en: Enumeration<NetworkInterface> = NetworkInterface.getNetworkInterfaces()
        while (en.hasMoreElements()) {
            val networkInterface: NetworkInterface = en.nextElement()
            val enumerationIpAddress: Enumeration<InetAddress> = networkInterface.inetAddresses
            while (enumerationIpAddress.hasMoreElements()) {
                val inetAddress: InetAddress = enumerationIpAddress.nextElement()
                if (!inetAddress.isLoopbackAddress && inetAddress is Inet4Address) {
                    return inetAddress.getHostAddress()
                }
            }
        }
    } catch (ex: SocketException) {
        ex.printStackTrace()
    }
    return null
}