是否可以使用一些代码获得设备的IP地址?
当前回答
// @NonNull
public static String getIPAddress() {
if (TextUtils.isEmpty(deviceIpAddress))
new PublicIPAddress().execute();
return deviceIpAddress;
}
public static String deviceIpAddress = "";
public static class PublicIPAddress extends AsyncTask<String, Void, String> {
InetAddress localhost = null;
protected String doInBackground(String... urls) {
try {
localhost = InetAddress.getLocalHost();
URL url_name = new URL("http://bot.whatismyipaddress.com");
BufferedReader sc = new BufferedReader(new InputStreamReader(url_name.openStream()));
deviceIpAddress = sc.readLine().trim();
} catch (Exception e) {
deviceIpAddress = "";
}
return deviceIpAddress;
}
protected void onPostExecute(String string) {
Lg.d("deviceIpAddress", string);
}
}
其他回答
虽然有一个正确的答案,我在这里分享我的答案,希望这样会更方便。
WifiManager wifiMan = (WifiManager) context.getSystemService(Context.WIFI_SERVICE);
WifiInfo wifiInf = wifiMan.getConnectionInfo();
int ipAddress = wifiInf.getIpAddress();
String ip = String.format("%d.%d.%d.%d", (ipAddress & 0xff),(ipAddress >> 8 & 0xff),(ipAddress >> 16 & 0xff),(ipAddress >> 24 & 0xff));
方法getDeviceIpAddress返回设备的ip地址,如果连接了wifi接口,则首选wifi接口地址。
@NonNull
private String getDeviceIpAddress() {
String actualConnectedToNetwork = null;
ConnectivityManager connManager = (ConnectivityManager) getSystemService(Context.CONNECTIVITY_SERVICE);
if (connManager != null) {
NetworkInfo mWifi = connManager.getNetworkInfo(ConnectivityManager.TYPE_WIFI);
if (mWifi.isConnected()) {
actualConnectedToNetwork = getWifiIp();
}
}
if (TextUtils.isEmpty(actualConnectedToNetwork)) {
actualConnectedToNetwork = getNetworkInterfaceIpAddress();
}
if (TextUtils.isEmpty(actualConnectedToNetwork)) {
actualConnectedToNetwork = "127.0.0.1";
}
return actualConnectedToNetwork;
}
@Nullable
private String getWifiIp() {
final WifiManager mWifiManager = (WifiManager) getApplicationContext().getSystemService(Context.WIFI_SERVICE);
if (mWifiManager != null && mWifiManager.isWifiEnabled()) {
int ip = mWifiManager.getConnectionInfo().getIpAddress();
return (ip & 0xFF) + "." + ((ip >> 8) & 0xFF) + "." + ((ip >> 16) & 0xFF) + "."
+ ((ip >> 24) & 0xFF);
}
return null;
}
@Nullable
public String getNetworkInterfaceIpAddress() {
try {
for (Enumeration<NetworkInterface> en = NetworkInterface.getNetworkInterfaces(); en.hasMoreElements(); ) {
NetworkInterface networkInterface = en.nextElement();
for (Enumeration<InetAddress> enumIpAddr = networkInterface.getInetAddresses(); enumIpAddr.hasMoreElements(); ) {
InetAddress inetAddress = enumIpAddr.nextElement();
if (!inetAddress.isLoopbackAddress() && inetAddress instanceof Inet4Address) {
String host = inetAddress.getHostAddress();
if (!TextUtils.isEmpty(host)) {
return host;
}
}
}
}
} catch (Exception ex) {
Log.e("IP Address", "getLocalIpAddress", ex);
}
return null;
}
如果你有一个壳;Ifconfig eth0也适用于x86设备
老实说,我对代码安全只是有点熟悉,所以这可能有点像黑客。但对我来说,这是最通用的方法:
package com.my_objects.ip;
import java.net.InetAddress;
import java.net.UnknownHostException;
public class MyIpByHost
{
public static void main(String a[])
{
try
{
InetAddress host = InetAddress.getByName("nameOfDevice or webAddress");
System.out.println(host.getHostAddress());
}
catch (UnknownHostException e)
{
e.printStackTrace();
}
} }
最近,一个IP地址仍然由getLocalIpAddress()返回,尽管与网络断开连接(没有服务指示器)。说明“设置>关于话机>状态”中显示的IP地址与应用程序想象的不一致。
我之前已经通过添加以下代码实现了一个解决方案:
ConnectivityManager cm = getConnectivityManager();
NetworkInfo net = cm.getActiveNetworkInfo();
if ((null == net) || !net.isConnectedOrConnecting()) {
return null;
}
有谁听过吗?
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