跳转语句(例如break)是 每个案例块后要求， 包括最后一个块是否 case语句或默认值 声明。只有一个例外，不像 c++的switch语句)，c#没有 支撑着一种含蓄的坠落 一个箱子连着另一个箱子。一个 例外是如果case语句有 没有代码。

——c# switch()文档

你可以像c++一样通过goto关键字实现fall through。

EX:

switch(num)
{
   case 1:
      goto case 3;
   case 2:
      goto case 3;
   case 3:
      //do something
      break;
   case 4:
      //do something else
      break;
   case default:
      break;
}

(复制/粘贴我在其他地方提供的答案)

通过在case中没有代码(见case 0)，或使用特殊的goto case(见case 1)或goto default(见case 2)表单，可以实现切换情况:

switch (/*...*/) {
    case 0: // shares the exact same code as case 1
    case 1:
        // do something
        goto case 2;
    case 2:
        // do something else
        goto default;
    default:
        // do something entirely different
        break;
}

他们为c#改变了switch语句(来自C/Java/ c++)的行为。我想原因是人们忘记了失败，导致了错误。我读过的一本书说使用goto进行模拟，但对我来说这听起来不像是一个好的解决方案。

你可以“转到案例标签” http://www.blackwasp.co.uk/CSharpGoto.aspx

The goto statement is a simple command that unconditionally transfers the control of the program to another statement. The command is often criticised with some developers advocating its removal from all high-level programming languages because it can lead to spaghetti code. This occurs when there are so many goto statements or similar jump statements that the code becomes difficult to read and maintain. However, there are programmers who point out that the goto statement, when used carefully, provides an elegant solution to some problems...

您忘记在情形3中添加“break;”语句。在情形2中，你把它写到if块中。 因此，试试这个吧:

case 3:            
{
    ans += string.Format("{0} hundred and ", numbers[number / 100]);
    break;
}


case 2:            
{
    int t = (number / 10) % 10;            
    if (t == 1)            
    {                
        ans += teens[number % 10];                
    }            
    else if (t > 1)                
    {
        ans += string.Format("{0}-", tens[t]);        
    }
    break;
}

case 1:            
{
    int o = number % 10;            
    ans += numbers[o];            
    break;        
}

default:            
{
    throw new ArgumentException("number");
}