这个怎么样?

function getQueryVar(varName){
    // Grab and unescape the query string - appending an '&' keeps the RegExp simple
    // for the sake of this example.
    var queryStr = unescape(window.location.search) + '&';

    // Dynamic replacement RegExp
    var regex = new RegExp('.*?[&\\?]' + varName + '=(.*?)&.*');

    // Apply RegExp to the query string
    var val = queryStr.replace(regex, "$1");

    // If the string is the same, we didn't find a match - return false
    return val == queryStr ? false : val;
}

．．然后用:

alert('Var "dest" = ' + getQueryVar('dest'));

干杯

下面是一个快速简单的JavaScript查询字符串解析方法:

function getQueryVariable(variable) {
    var query = window.location.search.substring(1);
    var vars = query.split('&');
    for (var i = 0; i < vars.length; i++) {
        var pair = vars[i].split('=');
        if (decodeURIComponent(pair[0]) == variable) {
            return decodeURIComponent(pair[1]);
        }
    }
    console.log('Query variable %s not found', variable);
}

现在向page.html发起请求?x =你好:

console.log(getQueryVariable('x'));

如果你知道你将只有一个查询字符串变量，你可以简单地做:

var dest = location.search.replace(/^.*?\=/, '');

我也是!http://jsfiddle.net/drzaus/8EE8k/

(注:无花哨嵌套或重复检查)

deparam = (function(d,x,params,p,i,j) {
return function (qs) {
    // start bucket; can't cheat by setting it in scope declaration or it overwrites
    params = {};
    // remove preceding non-querystring, correct spaces, and split
    qs = qs.substring(qs.indexOf('?')+1).replace(x,' ').split('&');
    // march and parse
    for (i = qs.length; i > 0;) {
        p = qs[--i];
        // allow equals in value
        j = p.indexOf('=');
        // what if no val?
        if(j === -1) params[d(p)] = undefined;
        else params[d(p.substring(0,j))] = d(p.substring(j+1));
    }

    return params;
};//--  fn  deparam
})(decodeURIComponent, /\+/g);

和测试:

var tests = {};
tests["simple params"] = "ID=2&first=1&second=b";
tests["full url"] = "http://blah.com/?third=c&fourth=d&fifth=e";
tests['just ?'] = '?animal=bear&fruit=apple&building=Empire State Building&spaces=these+are+pluses';
tests['with equals'] = 'foo=bar&baz=quux&equals=with=extra=equals&grault=garply';
tests['no value'] = 'foo=bar&baz=&qux=quux';
tests['value omit'] = 'foo=bar&baz&qux=quux';

var $output = document.getElementById('output');
function output(msg) {
    msg = Array.prototype.slice.call(arguments, 0).join("\n");
    if($output) $output.innerHTML += "\n" + msg + "\n";
    else console.log(msg);
}
var results = {}; // save results, so we can confirm we're not incorrectly referencing
$.each(tests, function(msg, test) {
    var q = deparam(test);
    results[msg] = q;
    output(msg, test, JSON.stringify(q), $.param(q));
    output('-------------------');
});

output('=== confirming results non-overwrite ===');
$.each(results, function(msg, result) {
    output(msg, JSON.stringify(result));
    output('-------------------');
});

结果:

simple params
ID=2&first=1&second=b
{"second":"b","first":"1","ID":"2"}
second=b&first=1&ID=2
-------------------
full url
http://blah.com/?third=c&fourth=d&fifth=e
{"fifth":"e","fourth":"d","third":"c"}
fifth=e&fourth=d&third=c
-------------------
just ?
?animal=bear&fruit=apple&building=Empire State Building&spaces=these+are+pluses
{"spaces":"these are pluses","building":"Empire State Building","fruit":"apple","animal":"bear"}
spaces=these%20are%20pluses&building=Empire%20State%20Building&fruit=apple&animal=bear
-------------------
with equals
foo=bar&baz=quux&equals=with=extra=equals&grault=garply
{"grault":"garply","equals":"with=extra=equals","baz":"quux","foo":"bar"}
grault=garply&equals=with%3Dextra%3Dequals&baz=quux&foo=bar
-------------------
no value
foo=bar&baz=&qux=quux
{"qux":"quux","baz":"","foo":"bar"}
qux=quux&baz=&foo=bar
-------------------
value omit
foo=bar&baz&qux=quux
{"qux":"quux","foo":"bar"}   <-- it's there, i swear!
qux=quux&baz=&foo=bar        <-- ...see, jQuery found it
-------------------

以下是我对@bobby发布的答案的评论，这是我将使用的代码:

    function parseQuery(str)
        {
        if(typeof str != "string" || str.length == 0) return {};
        var s = str.split("&");
        var s_length = s.length;
        var bit, query = {}, first, second;
        for(var i = 0; i < s_length; i++)
            {
            bit = s[i].split("=");
            first = decodeURIComponent(bit[0]);
            if(first.length == 0) continue;
            second = decodeURIComponent(bit[1]);
            if(typeof query[first] == "undefined") query[first] = second;
            else if(query[first] instanceof Array) query[first].push(second);
            else query[first] = [query[first], second]; 
            }
        return query;
        }

这段代码接受所提供的查询字符串(作为'str')并返回一个对象。字符串在所有&出现的情况下都被拆分，从而生成一个数组。然后遍历数组，其中的每一项都用“=”分隔。这将导致子数组，其中第0个元素是参数，第1个元素是值(如果no =符号则为undefined)。它们被映射到对象属性，例如字符串"hello=1&another=2&something"被转换为:

{
hello: "1",
another: "2",
something: undefined
}

此外，这段代码注意到重复出现，如“hello=1&hello=2”，并将结果转换为一个数组，例如:

{
hello: ["1", "2"]
}

您还会注意到它处理不使用=符号的情况。它还忽略&符号后面是否有一个等号。

对于最初的问题有点过度，但如果你需要在javascript中使用查询字符串，这是一个可重用的解决方案:)

我想要一个简单的函数，它接受URL作为输入，并返回查询参数的映射。 如果我要改进这个函数，我将支持URL中数组数据的标准，和或嵌套变量。

这应该可以用于jQuery。参数(qparams)函数。

function getQueryParams(url){
    var qparams = {},
        parts = (url||'').split('?'),
        qparts, qpart,
        i=0;

    if(parts.length <= 1 ){
        return qparams;
    }else{
        qparts = parts[1].split('&');
        for(i in qparts){

            qpart = qparts[i].split('=');
            qparams[decodeURIComponent(qpart[0])] = 
                           decodeURIComponent(qpart[1] || '');
        }
    }

    return qparams;
};