如何在启动中的ConfigureServices方法中获得开发/登台/生产托管环境?
public void ConfigureServices(IServiceCollection services)
{
// Which environment are we running under?
}
ConfigureServices方法只接受一个IServiceCollection参数。
如何在启动中的ConfigureServices方法中获得开发/登台/生产托管环境?
public void ConfigureServices(IServiceCollection services)
{
// Which environment are we running under?
}
ConfigureServices方法只接受一个IServiceCollection参数。
当前回答
由于还没有完整的复制和粘贴解决方案,基于Joe Audette的回答:
public IWebHostEnvironment Environment { get; }
public Startup(IWebHostEnvironment environment, IConfiguration configuration)
{
Environment = environment;
...
}
public void ConfigureServices(IServiceCollection services)
{
if (Environment.IsDevelopment())
{
// Do something
}else{
// Do something
}
...
}
其他回答
宿主环境来自ASPNET_ENV环境变量,在启动过程中使用IHostingEnvironment可用。IsEnvironment扩展方法,或IsDevelopment或IsProduction中相应的方便方法之一。在Startup()中保存你需要的东西,或者在ConfigureServices调用中保存:
var foo = Environment.GetEnvironmentVariable("ASPNET_ENV");
在NET6中,启动和程序合并为一个文件,启动中不再有ConfigureServices方法。现在你可以简单地使用
builder.Environment.IsProduction()
builder.Environment.IsStaging()
builder.Environment.IsDevelopment()
就在第一行之后
var builder = WebApplication.CreateBuilder(args);
如果你需要在你的代码库中某个不容易访问IHostingEnvironment的地方测试这个,另一个简单的方法是这样做的:
bool isDevelopment = Environment.GetEnvironmentVariable("ASPNETCORE_ENVIRONMENT") == "Development";
由于还没有完整的复制和粘贴解决方案,基于Joe Audette的回答:
public IWebHostEnvironment Environment { get; }
public Startup(IWebHostEnvironment environment, IConfiguration configuration)
{
Environment = environment;
...
}
public void ConfigureServices(IServiceCollection services)
{
if (Environment.IsDevelopment())
{
// Do something
}else{
// Do something
}
...
}
你可以很容易地在ConfigureServices中访问它,只是在Startup方法期间将它持久化到一个属性,该方法首先被调用并将其传递进来,然后你可以从ConfigureServices访问该属性。
public Startup(IWebHostEnvironment env, IApplicationEnvironment appEnv)
{
...your code here...
CurrentEnvironment = env;
}
private IWebHostEnvironment CurrentEnvironment{ get; set; }
public void ConfigureServices(IServiceCollection services)
{
string envName = CurrentEnvironment.EnvironmentName;
... your code here...
}