我遇到了一些情况,现在,它将是方便的,能够找到“最顶层”的视图控制器(一个负责当前视图),但还没有找到一种方法。

基本上,挑战是这样的:给定一个在一个类中执行,这个类不是一个视图控制器(或一个视图)[并且没有活动视图的地址],并且没有传递最顶层视图控制器的地址(或者,比如说,导航控制器的地址),是否有可能找到那个视图控制器?(如果是的话,是怎么做到的?)

或者,如果找不到,有没有可能找到最高处的风景?


当前回答

这个解决方案是最完整的。它考虑到: UINavigationController UIPageViewController UITabBarController 最上面的视图控制器来自顶部视图控制器

以Swift 3为例。

有3个重载

//Get the topmost view controller for the current application.
public func MGGetTopMostViewController() -> UIViewController?  {

    if let currentWindow:UIWindow = UIApplication.shared.keyWindow {
        return MGGetTopMostViewController(fromWindow: currentWindow)
    }

    return nil
}

//Gets the topmost view controller from a specific window.
public func MGGetTopMostViewController(fromWindow window:UIWindow) -> UIViewController? {

    if let rootViewController:UIViewController = window.rootViewController
    {
        return MGGetTopMostViewController(fromViewController:  rootViewController)
    }

    return nil
}


//Gets the topmost view controller starting from a specific UIViewController
//Pass the rootViewController into this to get the apps top most view controller
public func MGGetTopMostViewController(fromViewController viewController:UIViewController) -> UIViewController {

    //UINavigationController
    if let navigationViewController:UINavigationController = viewController as? UINavigationController {
        let viewControllers:[UIViewController] = navigationViewController.viewControllers
        if navigationViewController.viewControllers.count >= 1 {
            return MGGetTopMostViewController(fromViewController: viewControllers[viewControllers.count - 1])
        }
    }

    //UIPageViewController
    if let pageViewController:UIPageViewController = viewController as? UIPageViewController {
        if let viewControllers:[UIViewController] = pageViewController.viewControllers {
            if viewControllers.count >= 1 {
                return MGGetTopMostViewController(fromViewController: viewControllers[0])
            }
        }
    }

    //UITabViewController
    if let tabBarController:UITabBarController = viewController as? UITabBarController {
        if let selectedViewController:UIViewController = tabBarController.selectedViewController {
            return MGGetTopMostViewController(fromViewController: selectedViewController)
        }
    }

    //Lastly, Attempt to get the topmost presented view controller
    var presentedViewController:UIViewController! = viewController.presentedViewController
    var nextPresentedViewController:UIViewController! = presentedViewController?.presentedViewController

    //If there is a presented view controller, get the top most prensentedViewController and return it.
    if presentedViewController != nil {
        while nextPresentedViewController != nil {

            //Set the presented view controller as the next one.
            presentedViewController = nextPresentedViewController

            //Attempt to get the next presented view controller
            nextPresentedViewController = presentedViewController.presentedViewController
        }
        return presentedViewController
    }

    //If there is no topmost presented view controller, return the view controller itself.
    return viewController
}

其他回答

iOS 4在UIWindow上引入了rootViewController属性:

[UIApplication sharedApplication].keyWindow.rootViewController;

你需要在创建视图控制器后自己设置。

@implementation UIWindow (Extensions)

- (UIViewController*) topMostController
{
    UIViewController *topController = [self rootViewController];

    while (topController.presentedViewController) {
        topController = topController.presentedViewController;
    }

    return topController;
}

@end

扩展@Eric的回答,你需要小心,keyWindow实际上是你想要的窗口。例如,如果您试图在点击警报视图中的某些内容后使用此方法,keyWindow实际上将是警报的窗口,这无疑会给您带来问题。这发生在我在野外通过警报处理深度链接时,并导致SIGABRTs没有堆栈跟踪。要调试的婊子。

下面是我现在使用的代码:

- (UIViewController *)getTopMostViewController {
    UIWindow *topWindow = [UIApplication sharedApplication].keyWindow;
    if (topWindow.windowLevel != UIWindowLevelNormal) {
        NSArray *windows = [UIApplication sharedApplication].windows;
        for(topWindow in windows)
        {
            if (topWindow.windowLevel == UIWindowLevelNormal)
                break;
        }
    }

    UIViewController *topViewController = topWindow.rootViewController;

    while (topViewController.presentedViewController) {
        topViewController = topViewController.presentedViewController;
    }

    return topViewController;
}

你可以把这个和你喜欢的从这个问题的其他答案中检索顶视图控制器的方法混合在一起。

使用下面的扩展抓取当前可见的UIViewController。适用于Swift 4.0及更高版本

Swift 4.0及以上版本:

extension UIApplication {
    
    class func topViewController(_ viewController: UIViewController? = UIApplication.shared.keyWindow?.rootViewController) -> UIViewController? {
        if let nav = viewController as? UINavigationController {
            return topViewController(nav.visibleViewController)
        }
        if let tab = viewController as? UITabBarController {
            if let selected = tab.selectedViewController {
                return topViewController(selected)
            }
        }
        if let presented = viewController?.presentedViewController {
            return topViewController(presented)
        }
        return viewController
    }
}

如何使用?

let objViewcontroller = UIApplication.topViewController()

另一个解决方案依赖于responder链,它可能工作,也可能不工作,这取决于第一个responder是什么:

获取第一个响应器。 获取与第一个responder相关联的UIViewController。

示例伪代码:

+ (UIViewController *)currentViewController {
    UIView *firstResponder = [self firstResponder]; // from the first link above, but not guaranteed to return a UIView, so this should be handled more appropriately.
    UIViewController *viewController = [firstResponder viewController]; // from the second link above
    return viewController;
}